Case with ranges and patterns in Ruby - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of case with range and pattern matching

What is the output of this Ruby code?

Ruby

score = 85
result = case score
when 90..100 then "Excellent"
when 75..89 then "Good"
when 50..74 then "Pass"
else "Fail"
end
puts result

A Good

B Excellent

C Pass

D Fail

💡 Hint

Check which range 85 falls into.

The variable score is 85, which falls into the range 75..89, so the case returns "Good".

❓ Predict Output

intermediate

Pattern matching with case and array

What will this Ruby code print?

Ruby

value = [1, 2, 3]
case value
in [Integer, Integer, 3]
  puts "Matched pattern"
else
  puts "No match"
end

A No match

B RuntimeError

C SyntaxError

D Matched pattern

💡 Hint

Check if the array matches the pattern with two integers followed by 3.

The array [1, 2, 3] matches the pattern [Integer, Integer, 3], so it prints "Matched pattern".

❓ Predict Output

advanced

Case with pattern matching and variable binding

What is the output of this Ruby code?

Ruby

point = { x: 10, y: 20 }
case point
in { x: 10, y: y_val }
  puts "Y is #{y_val}"
else
  puts "No match"
end

A Y is y_val

B Y is 20

C No match

D SyntaxError

💡 Hint

Look at how y is bound in the pattern.

The pattern matches a hash with x:10 and binds y to y_val, which is 20, so it prints "Y is 20".

❓ Predict Output

advanced

Case with range and pattern matching combined

What will this Ruby code output?

Ruby

value = 7
case value
in 1..5
  puts "Low"
in 6..10
  puts "Medium"
else
  puts "High"
end

A High

B Low

C Medium

D SyntaxError

💡 Hint

Check which range 7 belongs to.

7 is in the range 6..10, so the case prints "Medium".

❓ Predict Output

expert

Complex pattern matching with nested structures

What is the output of this Ruby code?

Ruby

data = { user: { name: "Alice", age: 30 }, status: :active }
case data
in { user: { name: "Alice", age: age_val }, status: :active }
  puts "Active user Alice, age #{age_val}"
else
  puts "No match"
end

A Active user Alice, age 30

B No match

C SyntaxError

D RuntimeError

💡 Hint

Look carefully at the nested hash pattern and variable binding.

The pattern matches the nested hash and binds age to age_val (30), so it prints "Active user Alice, age 30".