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Rest APIprogramming~20 mins

Why pagination manages large datasets in Rest API - Challenge Your Understanding

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Challenge - 5 Problems
🎖️
Pagination Mastery
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Test your skills under time pressure!
🧠 Conceptual
intermediate
2:00remaining
Why use pagination in REST APIs?

Imagine you have a REST API that returns a list of thousands of items. Why is pagination important in this case?

AIt encrypts the data to make it secure during transfer.
BIt combines all data into one big response to avoid multiple requests.
CIt reduces the amount of data sent in each response, improving speed and reducing memory use.
DIt automatically deletes old data to keep the dataset small.
Attempts:
2 left
💡 Hint

Think about what happens if you try to send thousands of items at once.

Predict Output
intermediate
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Output of paginated API response

Given this simplified API response code snippet, what will be the output when requesting page 2 with page size 3?

Rest API
data = ['a', 'b', 'c', 'd', 'e', 'f', 'g']
page = 2
page_size = 3
start = (page - 1) * page_size
end = start + page_size
result = data[start:end]
print(result)
A['d', 'e', 'f']
B['a', 'b', 'c']
C['g']
D['e', 'f', 'g']
Attempts:
2 left
💡 Hint

Calculate the start and end indexes carefully.

🔧 Debug
advanced
2:00remaining
Identify the error in pagination logic

What error will this pagination code cause when requesting page 0?

Rest API
def get_page(data, page, size):
    start = (page - 1) * size
    end = start + size
    return data[start:end]

items = ['x', 'y', 'z']
print(get_page(items, 0, 2))
AReturns ['z'] due to negative start index slicing
BReturns empty list due to negative start index slicing
CRaises IndexError because start index is negative
DRaises TypeError because page is zero
Attempts:
2 left
💡 Hint

Think about how Python handles negative indexes in slicing.

📝 Syntax
advanced
2:00remaining
Syntax error in pagination parameter parsing

Which option will cause a syntax error when parsing pagination parameters in Python?

Rest API
def parse_params(params):
    page = int(params.get('page', 1))
    size = int(params.get('size', 10))
    return page, size
Apage = int(params.get('page' 1))
Bsize = int(params.get('size', 10))
Cpage = int(params.get('page', 1))
Dreturn page, size
Attempts:
2 left
💡 Hint

Look carefully at the syntax of the get() method.

🚀 Application
expert
2:00remaining
Calculate total pages for pagination

You have 53 items and want to paginate with 10 items per page. How many pages are needed?

A5
B53
C7
D6
Attempts:
2 left
💡 Hint

Divide total items by page size and round up.