The sliding window algorithm helps you efficiently process parts of data step-by-step without repeating work. It saves time by moving a 'window' over data instead of starting fresh each time.
Sliding window algorithm in Rest API
Start learning this pattern below
Jump into concepts and practice - no test required
class SlidingWindow: def __init__(self, size): self.size = size self.window = [] def add(self, value): if len(self.window) == self.size: self.window.pop(0) # Remove oldest value self.window.append(value) def get_window(self): return self.window
This class keeps a fixed-size window of the most recent values.
When adding a new value, it removes the oldest if the window is full.
sw = SlidingWindow(3) sw.add(1) sw.add(2) sw.add(3) print(sw.get_window()) # Output: [1, 2, 3]
sw.add(4) print(sw.get_window()) # Output: [2, 3, 4]
empty_sw = SlidingWindow(2) print(empty_sw.get_window()) # Output: []
single_sw = SlidingWindow(1) single_sw.add(10) print(single_sw.get_window()) # Output: [10] single_sw.add(20) print(single_sw.get_window()) # Output: [20]
This program shows how the sliding window moves as new values are added. It starts empty, then fills up to size 3, and slides forward by removing the oldest value each time a new one is added.
class SlidingWindow: def __init__(self, size): self.size = size self.window = [] def add(self, value): if len(self.window) == self.size: self.window.pop(0) # Remove oldest value self.window.append(value) def get_window(self): return self.window # Create a sliding window of size 3 sliding_window = SlidingWindow(3) # Add values and print window each time print('Initial window:', sliding_window.get_window()) values_to_add = [5, 10, 15, 20, 25] for value in values_to_add: sliding_window.add(value) print(f'Window after adding {value}:', sliding_window.get_window())
Time complexity of adding a value is O(1) because removing and appending are fast operations.
Space complexity is O(window size) since we only store a fixed number of elements.
A common mistake is forgetting to remove the oldest element when the window is full, which makes the window grow indefinitely.
Use sliding window when you want to process continuous chunks of data efficiently instead of recalculating from scratch.
The sliding window algorithm helps process data in fixed-size chunks efficiently.
It moves forward by removing the oldest data and adding new data.
This saves time and memory compared to recalculating over the entire data repeatedly.
Practice
sliding window algorithm in processing data streams?Solution
Step 1: Understand the sliding window concept
The sliding window algorithm processes data in fixed-size chunks, moving forward by removing the oldest data and adding new data.Step 2: Identify the main advantage
This approach avoids recalculating over the entire data repeatedly, saving time and memory.Final Answer:
It processes data in fixed-size chunks efficiently by reusing previous computations. -> Option AQuick Check:
Sliding window = efficient chunk processing [OK]
- Thinking it sorts data first
- Assuming it stores all data in memory
- Believing it processes data randomly
data in Python?Solution
Step 1: Recall Python list slicing syntax
To get the first 3 elements, use data[0:3], which includes indices 0, 1, and 2.Step 2: Check other options
data(0,3) is invalid syntax, data[3] gets only one element at index 3, data[:] gets the whole list.Final Answer:
window = data[0:3] -> Option BQuick Check:
Slice first 3 elements = data[0:3] [OK]
- Using parentheses instead of brackets
- Selecting a single element instead of a slice
- Taking the whole list instead of a window
data = [1, 3, 5, 7, 9]
window_size = 3
result = []
for i in range(len(data) - window_size + 1):
window_sum = sum(data[i:i+window_size])
result.append(window_sum)
print(result)Solution
Step 1: Understand the loop range and slicing
The loop runs from i=0 to i=2 (5 - 3 + 1 = 3 iterations). Each slice is data[i:i+3].Step 2: Calculate sums for each window
i=0: sum([1,3,5])=9; i=1: sum([3,5,7])=15; i=2: sum([5,7,9])=21.Final Answer:
[9, 15, 21] -> Option DQuick Check:
Sliding sums = [9, 15, 21] [OK]
- Incorrect loop range causing index errors
- Summing wrong slices
- Confusing window size with list length
data = [2, 4, 6, 8]
window_size = 2
result = []
for i in range(len(data) - window_size):
window_sum = sum(data[i:i+window_size])
result.append(window_sum)
print(result)Solution
Step 1: Analyze the loop range
The loop runs from 0 to len(data) - window_size - 1, which is 4 - 2 - 1 = 1, so only indices 0 and 1.Step 2: Identify missing last window
The last valid window starts at index 2 (data[2:4]), but the loop excludes it because it should run to len(data) - window_size + 1.Final Answer:
The loop range misses the last window, causing incomplete results. -> Option CQuick Check:
Loop range must cover all windows [OK]
- Using wrong loop range causing missed windows
- Misusing sum function
- Not initializing result list
data. Which approach is most efficient?Solution
Step 1: Understand the problem of efficiency
Calculating sum from scratch for each window is slow for large data because it repeats work.Step 2: Apply sliding window optimization
By keeping the previous window sum, add the new element and subtract the oldest element to get the next sum quickly.Step 3: Evaluate other options
Sorting does not help find consecutive window sums; recursion adds overhead and is inefficient here.Final Answer:
Use a sliding window by adding the new element and subtracting the oldest element from the previous sum. -> Option AQuick Check:
Sliding window sum update = add new - remove old [OK]
- Recalculating sums fully each time
- Sorting unrelated to consecutive sums
- Using recursion unnecessarily
