Sliding window algorithm in Rest API - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the sliding window size.

Rest API

window_size = [1]

Drag options to blanks, or click blank then click option'

A0

B5

C10

D-1

Attempts:

3 left

💡 Hint

Common Mistakes

Using zero or negative numbers for window size causes errors.

The sliding window size is set to 10 to process chunks of 10 elements.

2fill in blank

medium

Complete the code to slide the window by one position.

Rest API

start = start [1] 1

Drag options to blanks, or click blank then click option'

A/

B+

C*

D-

Attempts:

3 left

💡 Hint

Common Mistakes

Using subtraction instead of addition moves the window backward.

Sliding the window means moving the start index forward by 1, so we add 1.

3fill in blank

hard

Fix the error in the code to correctly calculate the window sum.

Rest API

window_sum = window_sum [1] nums[end] - nums[start - 1]

Drag options to blanks, or click blank then click option'

A+

B-

C/

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using '-' in the blank causes incorrect calculation.

To update the sum when sliding the window, add the new element and subtract the old one. The code adds the new element and subtracts the old one outside the blank, so the blank must be '+'.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps each word to its length if length is greater than 3.

Rest API

{word: [1] for word in words if [2]

Drag options to blanks, or click blank then click option'

Alen(word)

Bword

Clen(word) > 3

Dword > 3

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself instead of its length.

Comparing the word string to a number.

The dictionary comprehension maps each word to its length using len(word). The condition filters words with length greater than 3 using len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase keys to values only if values are positive.

Rest API

result = {{ [1]: [2] for k, v in data.items() if v [3] 0 }}

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using k.lower() instead of k.upper().

Using incorrect comparison operators.

The keys are converted to uppercase with k.upper(), values are v, and the condition filters values greater than 0 using >.

Practice

1. What is the main advantage of using the sliding window algorithm in processing data streams?

easy

A. It processes data in fixed-size chunks efficiently by reusing previous computations.

B. It sorts the entire data before processing.

C. It stores all data in memory for faster access.

D. It processes data randomly without any order.

Solution

1. Step 1: Understand the sliding window concept

   The sliding window algorithm processes data in fixed-size chunks, moving forward by removing the oldest data and adding new data.

2. Step 2: Identify the main advantage

   This approach avoids recalculating over the entire data repeatedly, saving time and memory.

3. Final Answer:

   It processes data in fixed-size chunks efficiently by reusing previous computations. -> Option A

4. Quick Check:

   Sliding window = efficient chunk processing [OK]

Hint: Remember: sliding window reuses old results to save time [OK]

Common Mistakes:

• Thinking it sorts data first
• Assuming it stores all data in memory
• Believing it processes data randomly

2. Which of the following is the correct way to initialize a sliding window of size 3 over a list named data in Python?

easy

A. window = data[3]

B. window = data[0:3]

C. window = data(0,3)

D. window = data[:]

Solution

1. Step 1: Recall Python list slicing syntax

   To get the first 3 elements, use data[0:3], which includes indices 0, 1, and 2.

2. Step 2: Check other options

   data(0,3) is invalid syntax, data[3] gets only one element at index 3, data[:] gets the whole list.

3. Final Answer:

   window = data[0:3] -> Option B

4. Quick Check:

   Slice first 3 elements = data[0:3] [OK]

Hint: Use data[start:end] to slice lists in Python [OK]

Common Mistakes:

• Using parentheses instead of brackets
• Selecting a single element instead of a slice
• Taking the whole list instead of a window

3. Given the Python code below, what will be the output?

data = [1, 3, 5, 7, 9]
window_size = 3
result = []
for i in range(len(data) - window_size + 1):
    window_sum = sum(data[i:i+window_size])
    result.append(window_sum)
print(result)

medium

A. [1, 3, 5]

B. [15, 21, 27]

C. [3, 5, 7]

D. [9, 15, 21]

Solution

1. Step 1: Understand the loop range and slicing

   The loop runs from i=0 to i=2 (5 - 3 + 1 = 3 iterations). Each slice is data[i:i+3].

2. Step 2: Calculate sums for each window

   i=0: sum([1,3,5])=9; i=1: sum([3,5,7])=15; i=2: sum([5,7,9])=21.

3. Final Answer:

   [9, 15, 21] -> Option D

4. Quick Check:

   Sliding sums = [9, 15, 21] [OK]

Hint: Sum slices of size window_size in a loop [OK]

Common Mistakes:

• Incorrect loop range causing index errors
• Summing wrong slices
• Confusing window size with list length

4. The following code tries to implement a sliding window sum but has a bug. What is the error?

data = [2, 4, 6, 8]
window_size = 2
result = []
for i in range(len(data) - window_size):
    window_sum = sum(data[i:i+window_size])
    result.append(window_sum)
print(result)

medium

A. The result list is not initialized.

B. The sum function is used incorrectly.

C. The loop range misses the last window, causing incomplete results.

D. Window size is larger than data length.

Solution

1. Step 1: Analyze the loop range

   The loop runs from 0 to len(data) - window_size - 1, which is 4 - 2 - 1 = 1, so only indices 0 and 1.

2. Step 2: Identify missing last window

   The last valid window starts at index 2 (data[2:4]), but the loop excludes it because it should run to len(data) - window_size + 1.

3. Final Answer:

   The loop range misses the last window, causing incomplete results. -> Option C

4. Quick Check:

   Loop range must cover all windows [OK]

Hint: Use range(len(data) - window_size + 1) for full coverage [OK]

Common Mistakes:

• Using wrong loop range causing missed windows
• Misusing sum function
• Not initializing result list

5. You want to find the maximum sum of any sliding window of size 4 in a large list data. Which approach is most efficient?

hard

A. Use a sliding window by adding the new element and subtracting the oldest element from the previous sum.

B. Calculate sum of each window from scratch using sum(data[i:i+4]) in a loop.

C. Sort the entire list and pick the top 4 elements to sum.

D. Use recursion to calculate sums of all windows.

Solution

1. Step 1: Understand the problem of efficiency

   Calculating sum from scratch for each window is slow for large data because it repeats work.

2. Step 2: Apply sliding window optimization

   By keeping the previous window sum, add the new element and subtract the oldest element to get the next sum quickly.

3. Step 3: Evaluate other options

   Sorting does not help find consecutive window sums; recursion adds overhead and is inefficient here.

4. Final Answer:

   Use a sliding window by adding the new element and subtracting the oldest element from the previous sum. -> Option A

5. Quick Check:

   Sliding window sum update = add new - remove old [OK]

Hint: Update sums by adding new and removing old element [OK]

Common Mistakes:

• Recalculating sums fully each time
• Sorting unrelated to consecutive sums
• Using recursion unnecessarily