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R Programmingprogramming~20 mins

Recursive functions in R Programming - Practice Problems & Coding Challenges

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Challenge - 5 Problems
🎖️
Recursive Mastery
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Test your skills under time pressure!
❓ Predict Output
intermediate
2:00remaining
Output of a simple factorial recursion
What is the output of this R code when calling factorial(4)?
R Programming
factorial <- function(n) {
  if (n == 0) {
    return(1)
  } else {
    return(n * factorial(n - 1))
  }
}
factorial(4)
A120
BError: object 'factorial' not found
C10
D24
Attempts:
2 left
💡 Hint
Remember factorial of 4 is 4 * 3 * 2 * 1.
❓ Predict Output
intermediate
2:00remaining
Output of Fibonacci recursive function
What is the output of fib(5) given this R function?
R Programming
fib <- function(n) {
  if (n <= 1) {
    return(n)
  } else {
    return(fib(n - 1) + fib(n - 2))
  }
}
fib(5)
A5
B8
C3
DError: recursive call limit reached
Attempts:
2 left
💡 Hint
Fibonacci sequence starts 0,1,1,2,3,5...
🔧 Debug
advanced
2:00remaining
Identify the error in this recursive sum function
What error will this R code produce when calling sum_recursive(3)?
R Programming
sum_recursive <- function(n) {
  if (n == 0) {
    return(0)
  } else {
    return(n + sum_recursive)
  }
}
sum_recursive(3)
A6
BError: argument is missing, with no default
CError: object 'sum_recursive' not found
DError: recursive call limit reached
Attempts:
2 left
💡 Hint
Check how the recursive call is made inside the function.
❓ Predict Output
advanced
2:00remaining
Output of recursive string reversal
What is the output of reverse_str('abc') with this R function?
R Programming
reverse_str <- function(s) {
  if (nchar(s) == 0) {
    return("")
  } else {
    return(paste0(substr(s, nchar(s), nchar(s)), reverse_str(substr(s, 1, nchar(s) - 1))))
  }
}
reverse_str('abc')
A"cba"
B"abc"
CError: non-numeric argument to binary operator
D"bac"
Attempts:
2 left
💡 Hint
The function takes last character and appends reversed rest.
🧠 Conceptual
expert
2:00remaining
Maximum recursion depth error cause
Which option best explains why this recursive R function causes a 'maximum recursion depth exceeded' error?
R Programming
infinite_recursion <- function(n) {
  if (n == 0) {
    return(0)
  } else {
    return(infinite_recursion(n + 1))
  }
}
infinite_recursion(1)
AThe base case is missing so recursion never stops.
BThe function has a syntax error causing infinite calls.
CThe function never reaches the base case because n increases instead of decreasing.
DThe function calls itself with the same argument causing infinite loop.
Attempts:
2 left
💡 Hint
Check how the argument changes in recursive calls.

Practice

(1/5)
1. What is the main purpose of a base case in a recursive function?
easy
A. To stop the recursion and prevent infinite calls
B. To call the function again with the same input
C. To increase the input size for the next call
D. To print the result of the recursion

Solution

  1. Step 1: Understand recursion basics

    A recursive function calls itself repeatedly with smaller inputs.
  2. Step 2: Identify the role of base case

    The base case stops the recursion to avoid infinite loops and eventual crash.
  3. Final Answer:

    To stop the recursion and prevent infinite calls -> Option A
  4. Quick Check:

    Base case = stop recursion [OK]
Hint: Base case always stops recursion to avoid infinite loops [OK]
Common Mistakes:
  • Forgetting the base case causes infinite recursion
  • Thinking base case calls function again
  • Confusing base case with recursive step
2. Which of the following is the correct syntax to define a recursive function fact in R that calculates factorial?
easy
A. fact <- function(n) { repeat n * fact(n - 1) }
B. fact <- function(n) { while(n > 0) n * fact(n - 1) }
C. fact <- function(n) { if(n == 1) n + fact(n - 1) }
D. fact <- function(n) { if(n == 0) 1 else n * fact(n - 1) }

Solution

  1. Step 1: Check base case and recursive call

    fact <- function(n) { if(n == 0) 1 else n * fact(n - 1) } correctly uses if condition for base case (n == 0) and recursive call with n-1.
  2. Step 2: Identify syntax errors in other options

    Options B, C, and D misuse loops or have wrong base case or missing else.
  3. Final Answer:

    fact <- function(n) { if(n == 0) 1 else n * fact(n - 1) } -> Option D
  4. Quick Check:

    Correct base case and recursive call syntax [OK]
Hint: Base case uses if, recursive call uses else with smaller input [OK]
Common Mistakes:
  • Using loops instead of recursion
  • Missing else leads to errors
  • Wrong base case condition
3. What is the output of this R code?
fib <- function(n) {
  if (n <= 1) return(n)
  else return(fib(n-1) + fib(n-2))
}
fib(4)
medium
A. 5
B. 4
C. 3
D. 7

Solution

  1. Step 1: Trace fib(4) calls

    fib(4) = fib(3) + fib(2); fib(3) = fib(2) + fib(1); fib(2) = fib(1) + fib(0)
  2. Step 2: Calculate values bottom-up

    fib(1)=1, fib(0)=0; fib(2)=1+0=1; fib(3)=1+1=2; fib(4)=2+1=3
  3. Final Answer:

    3 -> Option C
  4. Quick Check:

    Fibonacci(4) = 3 [OK]
Hint: Fibonacci(4) = 3 by adding previous two values [OK]
Common Mistakes:
  • Confusing index starting at 0 or 1
  • Adding wrong recursive calls
  • Forgetting base cases
4. Identify the error in this recursive R function to sum numbers from 1 to n:
sum_to_n <- function(n) {
  if (n == 1) return(1)
  else return(n + sum_to_n(n))
}
sum_to_n(3)
medium
A. The recursive call uses the same n, causing infinite recursion
B. The function should use a loop instead
C. The base case is missing
D. The return statement is outside the function

Solution

  1. Step 1: Check recursive call argument

    The function calls sum_to_n(n) instead of sum_to_n(n-1), so input never decreases.
  2. Step 2: Understand effect of error

    This causes infinite recursion because n stays the same and base case is never reached.
  3. Final Answer:

    The recursive call uses the same n, causing infinite recursion -> Option A
  4. Quick Check:

    Recursive call must reduce input [OK]
Hint: Recursive call must use smaller input to reach base case [OK]
Common Mistakes:
  • Calling function with same argument
  • Missing base case
  • Confusing recursion with loops
5. Write a recursive R function flatten_list that takes a nested list of numbers and returns a flat vector of all numbers.
What is the correct approach?
hard
A. Use recursion but forget to combine results from recursive calls
B. Check if input is a list; if yes, recursively flatten each element and combine; else return the element as vector
C. Return the input directly without any processing
D. Use a for loop to iterate and append elements without recursion

Solution

  1. Step 1: Identify recursive structure

    Nested lists require checking each element; if it's a list, call flatten_list recursively.
  2. Step 2: Combine results properly

    Combine all flattened elements into one vector to get a flat list of numbers.
  3. Final Answer:

    Check if input is a list; if yes, recursively flatten each element and combine; else return the element as vector -> Option B
  4. Quick Check:

    Recursion + combine results = flatten list [OK]
Hint: Recursively flatten each list element and combine results [OK]
Common Mistakes:
  • Not combining recursive results
  • Forgetting to check if element is a list
  • Using loops only without recursion
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