Operator precedence in R Programming - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to calculate the correct result using operator precedence.

R Programming

result <- 3 + 4 * [1]

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A2

B2L

C2.0

Attempts:

3 left

💡 Hint

Common Mistakes

Adding 3 + 4 first, then multiplying by 2.

Multiplication has higher precedence than addition, so 4 * 2 is calculated first, then 3 is added.

2fill in blank

medium

Complete the code to get the correct logical result considering operator precedence.

R Programming

result <- TRUE | FALSE & [1]

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AFALSE

BTRUE

CNA

DNULL

Attempts:

3 left

💡 Hint

Common Mistakes

Evaluating OR before AND, leading to wrong result.

AND (&) has higher precedence than OR (|), so FALSE & FALSE is evaluated first, resulting in FALSE, then TRUE | FALSE is TRUE.

3fill in blank

hard

Fix the error in the expression by completing the code with the correct operator.

R Programming

result <- (5 + 3) [1] 2 ^ 3

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A/

B+

C-

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using + or - instead of * changes the intended calculation.

Exponentiation (^) has higher precedence than multiplication (*), so 2 ^ 3 is calculated first, then multiplied by (5 + 3).

4fill in blank

hard

Fill both blanks to correctly calculate the expression considering operator precedence.

R Programming

result <- 10 [1] 4 [2] 2

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A-

B+

C*

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Doing addition or subtraction before division.

Multiplication and division have higher precedence than addition and subtraction. Here, 4 / 2 is calculated first, then added to 10.

5fill in blank

hard

Fill all three blanks to correctly compute the expression with proper operator precedence.

R Programming

result <- (8 [1] 2) [2] 3 [3] 4

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A+

B*

C-

D^

Attempts:

3 left

💡 Hint

Common Mistakes

Ignoring parentheses or wrong operator order.

Parentheses are evaluated first: 8 + 2 = 10. Then multiplication and exponentiation follow. 3 ^ 4 is calculated first, then multiplied by 10.