Next and break statements in R Programming - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to skip the current iteration when x equals 3.

R Programming

for (x in 1:5) {
  if (x == 3) {
    [1]
  }
  print(x)
}

Drag options to blanks, or click blank then click option'

Abreak

Bcontinue

Cnext

Dskip

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'break' instead of 'next' will stop the entire loop.

In R, next skips the current loop iteration and continues with the next one.

2fill in blank

medium

Complete the code to stop the loop when x equals 4.

R Programming

for (x in 1:5) {
  if (x == 4) {
    [1]
  }
  print(x)
}

Drag options to blanks, or click blank then click option'

Astop

Bbreak

Cnext

Dexit

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'next' will skip the iteration but not stop the loop.

The break statement stops the entire loop immediately.

3fill in blank

hard

Fix the error in the code to skip printing number 2.

R Programming

for (i in 1:3) {
  if (i == 2) {
    [1]
  }
  print(i)
}

Drag options to blanks, or click blank then click option'

Anext

Bcontinue

Cskip

Dbreak

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'break' stops the loop entirely.

Use next to skip printing when i is 2.

4fill in blank

hard

Fill both blanks to skip printing odd numbers and stop the loop at 8.

R Programming

for (num in 1:10) {
  if (num [1] 2 != 0) {
    [2]
  }
  if (num == 8) {
    break
  }
  print(num)
}

Drag options to blanks, or click blank then click option'

A%%

Bnext

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '==' instead of '%%' for modulo.

Using 'break' instead of 'next' to skip.

Use %% to check remainder and next to skip odd numbers.

5fill in blank

hard

Fill all three blanks to skip numbers divisible by 3, stop at 7, and print the rest.

R Programming

for (val in 1:10) {
  if (val [1] 3 == 0) {
    [2]
  }
  if (val [3] 7) {
    break
  }
  print(val)
}

Drag options to blanks, or click blank then click option'

A%%

Bnext

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '!=' instead of '==' to check for 7.

Using 'break' instead of 'next' to skip.

Use %% for modulo, next to skip divisible by 3, and == to stop at 7.

Practice

1. What does the next statement do inside a loop in R?

easy

A. Skips the current iteration and moves to the next one

B. Stops the entire loop immediately

C. Restarts the loop from the beginning

D. Exits the current function

Solution

1. Step 1: Understand the purpose of next

   The next statement is used to skip the rest of the current loop iteration and continue with the next iteration.

2. Step 2: Compare with other statements

   Unlike break, which stops the loop completely, next only skips to the next round.

3. Final Answer:

   Skips the current iteration and moves to the next one -> Option A

4. Quick Check:

   next skips iteration [OK]

Hint: Remember: next skips iteration, break stops loop [OK]

Common Mistakes:

• Confusing next with break
• Thinking next restarts the loop
• Believing next exits the function

2. Which of the following is the correct syntax to skip the current iteration in a for loop in R?

easy

A. skip

B. continue

C. break

D. next

Solution

1. Step 1: Recall R loop control keywords

   In R, the keyword to skip the current iteration is next. There is no continue keyword in R.

2. Step 2: Identify correct keyword

   break stops the loop, skip is not a valid keyword.

3. Final Answer:

   next -> Option D

4. Quick Check:

   Use next to skip iteration [OK]

Hint: Use 'next' to skip, not 'continue' in R [OK]

Common Mistakes:

• Using 'continue' instead of 'next'
• Using 'skip' which is invalid
• Confusing 'break' with skipping iteration

3. What will be the output of the following R code?

for(i in 1:5) {
  if(i == 3) next
  print(i)
}

medium

A. [1] 1 2 4 5

B. [1] 1 2 3 4 5

C. [1] 1 2 3 4

D. [1] 1 2 3 4 5 3

Solution

1. Step 1: Analyze the loop and condition

   The loop runs from 1 to 5. When i == 3, the next statement skips printing 3.

2. Step 2: Determine printed values

   Values 1, 2, 4, and 5 are printed. The number 3 is skipped.

3. Final Answer:

   [1] 1 2 4 5 -> Option A

4. Quick Check:

   next skips 3, so output excludes 3 [OK]

Hint: next skips printing 3, so output misses 3 [OK]

Common Mistakes:

• Including 3 in output
• Thinking next stops loop
• Confusing output format

4. Identify the error in this R code snippet:

for(i in 1:5) {
  if(i == 4) next()
  print(i)
}

medium

A. The loop variable i is not defined

B. Using parentheses with next causes an error

C. print() cannot be used inside loops

D. The if condition syntax is incorrect

Solution

1. Step 1: Check usage of next statement

   In R, next is a statement, not a function, so it should not have parentheses.

2. Step 2: Identify syntax error

   Using next() causes a syntax error. Correct usage is just next.

3. Final Answer:

   Using parentheses with next causes an error -> Option B

4. Quick Check:

   next is not a function, no parentheses [OK]

Hint: Don't add () after next; it's not a function [OK]

Common Mistakes:

• Writing next() instead of next
• Assuming next is a function
• Misreading error cause

5. Consider the following R code:

sum <- 0
for(i in 1:10) {
  if(i %% 2 == 0) next
  if(i > 7) break
  sum <- sum + i
}
print(sum)

What is the output of this code?

hard

A. 25

B. 20

C. 16

D. 30

Solution

1. Step 1: Understand loop conditions

   The loop runs from 1 to 10. It skips even numbers with next. It stops completely when i > 7 due to break.

2. Step 2: Calculate sum of odd numbers less than or equal to 7

   Odd numbers before break: 1, 3, 5, 7. Sum = 1+3+5+7 = 16.

3. Final Answer:

   16 -> Option C

4. Quick Check:

   Sum odd < 8 = 16 [OK]

Hint: Sum odd numbers until i > 7, skip evens [OK]

Common Mistakes:

• Including even numbers in sum
• Ignoring break condition
• Summing all numbers 1 to 10