Why object-oriented programming is used in Python - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a class named Car.

Python

class [1]:
    pass

Drag options to blanks, or click blank then click option'

ACar

Bcar

Cvehicle

DCarClass

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase names for classes

Using unrelated names

The class name should be Car to define the class correctly.

2fill in blank

medium

Complete the code to add an __init__ method that stores the car's brand.

Python

class Car:
    def __init__(self, brand):
        self.[1] = brand

Drag options to blanks, or click blank then click option'

Acar_brand

Bname

Cbrand

Dbrand_name

Attempts:

3 left

💡 Hint

Common Mistakes

Using different attribute names than parameters

Forgetting self.

The attribute name should be brand to match the parameter and store the car's brand.

3fill in blank

hard

Fix the error in the method to return the car's brand.

Python

class Car:
    def __init__(self, brand):
        self.brand = brand
    def get_brand(self):
        return self.[1]

Drag options to blanks, or click blank then click option'

Abrand_name

Bname

Ccar_brand

Dbrand

Attempts:

3 left

💡 Hint

Common Mistakes

Returning a wrong attribute name

Missing self.

The method should return self.brand to access the stored brand attribute.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps car brands to their lengths.

Python

brands = ['Ford', 'BMW', 'Audi']
lengths = {brand[1]: len(brand) for brand in brands if len(brand) [2] 3}

Drag options to blanks, or click blank then click option'

A.upper()

B>

C<

D.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong comparison operators

Not applying string methods correctly

The first blank uses .upper() to convert brand names to uppercase keys. The second blank uses > to filter brands longer than 3 letters.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase brand names to their lengths if length is greater than 3.

Python

brands = ['Ford', 'BMW', 'Audi']
lengths = {{ [1]: [2] for brand in brands if len(brand) [3] 3 }}

Drag options to blanks, or click blank then click option'

Abrand.upper()

Blen(brand)

C>

Dbrand.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up keys and values

Wrong comparison operator

The dictionary keys are uppercase brand names (brand.upper()), values are their lengths (len(brand)), and the condition filters brands longer than 3 (>).