This program shows how name mangling hides the attribute and how to access it safely inside the class or with the mangled name.
Python
class Secret:
def __init__(self):
self.__hidden = 'hidden value'def show(self):
return self.__hidden
s = Secret()
print(s.show())
# Trying to access directly will cause errortry:
print(s.__hidden)
except AttributeError as e:
print('Error:', e)
# Accessing with name mangling syntaxprint(s._Secret__hidden)
OutputSuccess
Important Notes
Name mangling is not true privacy, just a way to avoid accidental access.
Use single underscore (_) for 'protected' attributes, double underscore (__) for name mangling.
Summary
Name mangling adds the class name to attributes starting with double underscores.
This helps avoid accidental access or name conflicts.
You can still access mangled names using _ClassName__attribute syntax if needed.
Practice
(1/5)
1. What does name mangling do to an attribute starting with double underscores in a Python class?
easy
A. It adds the class name before the attribute name to avoid conflicts.
B. It makes the attribute public and accessible everywhere.
C. It deletes the attribute from the class.
D. It converts the attribute name to uppercase.
Solution
Step 1: Understand double underscore prefix
Attributes starting with double underscores trigger name mangling in Python classes.
Step 2: Effect of name mangling
Python adds the class name before the attribute name to avoid accidental access or conflicts.
Final Answer:
It adds the class name before the attribute name to avoid conflicts. -> Option A
Quick Check:
Name mangling = adds class name prefix [OK]
Hint: Double underscores add class name prefix to attribute [OK]
Common Mistakes:
Thinking double underscores make attribute public
Confusing name mangling with deleting attributes
Assuming attribute name changes to uppercase
2. Which of the following is the correct way to define a private attribute using name mangling in a Python class?
easy
A. self.__my_attr = 5
B. def __my_attr(self): pass
C. self._my_attr = 5
D. self.my_attr__ = 5
Solution
Step 1: Identify private attribute syntax
Private attributes use double underscores at the start of the name, like __my_attr.
Step 2: Check correct assignment
Assigning with self.__my_attr = 5 correctly defines a private attribute with name mangling.
Final Answer:
self.__my_attr = 5 -> Option A
Quick Check:
Double underscore prefix = private attribute [OK]
Hint: Use double underscores before attribute name for private [OK]
Common Mistakes:
Using single underscore instead of double
Placing underscores after attribute name
Defining private attribute as a method incorrectly
3. What will be the output of this code?
class A:
def __init__(self):
self.__x = 10
a = A()
print(hasattr(a, '__x'))
print(hasattr(a, '_A__x'))
medium
A. True\nTrue
B. False\nTrue
C. True\nFalse
D. False\nFalse
Solution
Step 1: Check attribute __x existence
Due to name mangling, __x is stored as _A__x internally, so hasattr(a, '__x') returns False.
Step 2: Check mangled attribute _A__x existence
hasattr(a, '_A__x') returns True because this is the mangled name storing the value.
Final Answer:
False
True -> Option B
Quick Check:
__x hidden as _A__x = False, True [OK]
Hint: Check mangled name with _ClassName__attr [OK]
Common Mistakes:
Assuming __x is directly accessible
Confusing mangled name with original
Expecting both hasattr calls to be True
4. What is the error in this code snippet?
class B:
def __init__(self):
self.__val = 5
b = B()
print(b.__val)
medium
A. SyntaxError due to double underscores
B. No error, prints 5
C. TypeError because __val is private
D. AttributeError because __val is name mangled
Solution
Step 1: Understand name mangling effect
__val is mangled to _B__val internally, so b.__val does not exist.
Step 2: Accessing __val causes AttributeError
Trying to print b.__val raises AttributeError because the attribute is hidden by name mangling.
Final Answer:
AttributeError because __val is name mangled -> Option D
Quick Check:
Accessing __val directly = AttributeError [OK]
Hint: Access mangled attribute with _ClassName__attr [OK]
Common Mistakes:
Expecting no error when accessing __val
Thinking double underscores cause syntax error
Confusing AttributeError with TypeError
5. Given this class:
class C:
def __init__(self):
self.__data = 42
def get_data(self):
return self.__data
c = C()
How can you access the private attribute __data from outside the class without using the get_data method?
hard
A. c.__data
B. c._data
C. c._C__data
D. c.get_data()
Solution
Step 1: Understand name mangling for __data
The attribute __data is stored internally as _C__data due to name mangling.
Step 2: Access mangled attribute directly
You can access it from outside the class using c._C__data.
Final Answer:
c._C__data -> Option C
Quick Check:
Access private with _ClassName__attr [OK]
Hint: Use _ClassName__attr to access private attribute [OK]
Common Mistakes:
Trying to access c.__data directly
Using single underscore _data instead
Confusing method call with attribute access
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