Why exceptions occur in Python - Challenge Your Understanding

Challenge - 5 Problems

❓ Predict Output

intermediate

What is the output of this code with division by zero?

Consider the following Python code. What will it output when run?

Python

try:
    result = 10 / 0
except ZeroDivisionError:
    print("Cannot divide by zero")

A ZeroDivisionError

B 0

C Cannot divide by zero

D 10

💡 Hint

Think about what happens when you divide a number by zero in Python.

Dividing by zero causes a ZeroDivisionError. The except block catches this and prints the message.

❓ Predict Output

intermediate

What error does this code raise?

What error will this code produce when run?

Python

my_list = [1, 2, 3]
print(my_list[5])

A IndexError

B TypeError

C KeyError

D ValueError

💡 Hint

Think about what happens when you try to access a list element outside its range.

Accessing an index that does not exist in a list raises an IndexError.

❓ Predict Output

advanced

What is the output of this code with a missing key in a dictionary?

What will this code print when executed?

Python

my_dict = {'a': 1, 'b': 2}
try:
    print(my_dict['c'])
except KeyError:
    print('Key not found')

A Key not found

B None

C KeyError

D 2

💡 Hint

What happens when you try to access a dictionary key that does not exist?

Accessing a missing key raises KeyError, which is caught and prints 'Key not found'.

❓ Predict Output

advanced

What error does this code raise with wrong type operation?

What error will this code produce when run?

Python

number = 5
text = 'hello'
print(number + text)

A SyntaxError

B ValueError

C NameError

D TypeError

💡 Hint

Think about adding a number and a string in Python.

You cannot add an integer and a string directly, which causes a TypeError.

🧠 Conceptual

expert

Why does this code raise an UnboundLocalError?

What is the cause of the error in this code snippet?

Python

x = 10
def func():
    print(x)
    x = 5
func()

A Because x is not defined anywhere in the program

B Because x is assigned inside the function after being used, making it a local variable before assignment

C Because print cannot be used inside a function

D Because functions cannot access variables outside their scope

💡 Hint

Think about how Python treats variables assigned inside functions.

Assigning to x inside the function makes x local. Using it before assignment causes UnboundLocalError.