Why exceptions occur in Python - Challenge Your Understanding

Challenge - 5 Problems

❓ Predict Output

intermediate

What is the output of this code with division by zero?

Consider the following Python code. What will it output when run?

Python

try:
    result = 10 / 0
except ZeroDivisionError:
    print("Cannot divide by zero")

A ZeroDivisionError

B 0

C Cannot divide by zero

D 10

💡 Hint

Think about what happens when you divide a number by zero in Python.

Dividing by zero causes a ZeroDivisionError. The except block catches this and prints the message.

❓ Predict Output

intermediate

What error does this code raise?

What error will this code produce when run?

Python

my_list = [1, 2, 3]
print(my_list[5])

A IndexError

B TypeError

C KeyError

D ValueError

💡 Hint

Think about what happens when you try to access a list element outside its range.

Accessing an index that does not exist in a list raises an IndexError.

❓ Predict Output

advanced

What is the output of this code with a missing key in a dictionary?

What will this code print when executed?

Python

my_dict = {'a': 1, 'b': 2}
try:
    print(my_dict['c'])
except KeyError:
    print('Key not found')

A Key not found

B None

C KeyError

D 2

💡 Hint

What happens when you try to access a dictionary key that does not exist?

Accessing a missing key raises KeyError, which is caught and prints 'Key not found'.

❓ Predict Output

advanced

What error does this code raise with wrong type operation?

What error will this code produce when run?

Python

number = 5
text = 'hello'
print(number + text)

A SyntaxError

B ValueError

C NameError

D TypeError

💡 Hint

Think about adding a number and a string in Python.

You cannot add an integer and a string directly, which causes a TypeError.

🧠 Conceptual

expert

Why does this code raise an UnboundLocalError?

What is the cause of the error in this code snippet?

Python

x = 10
def func():
    print(x)
    x = 5
func()

A Because x is not defined anywhere in the program

B Because x is assigned inside the function after being used, making it a local variable before assignment

C Because print cannot be used inside a function

D Because functions cannot access variables outside their scope

💡 Hint

Think about how Python treats variables assigned inside functions.

Assigning to x inside the function makes x local. Using it before assignment causes UnboundLocalError.

Practice

1. Why do exceptions occur in a Python program?

easy

A. Because the program encounters an unexpected error during execution

B. Because the program runs perfectly without any errors

C. Because the program finishes all tasks successfully

D. Because the program has no code to execute

Solution

1. Step 1: Understand what exceptions mean

   Exceptions happen when the program faces an unexpected problem it cannot handle normally.

2. Step 2: Identify the cause of exceptions

   Unexpected errors like dividing by zero or accessing missing files cause exceptions.

3. Final Answer:

   Because the program encounters an unexpected error during execution -> Option A

4. Quick Check:

   Unexpected error = Exception occurs [OK]

Hint: Exceptions happen only when errors occur during running [OK]

Common Mistakes:

• Thinking exceptions occur when program runs fine
• Confusing exceptions with normal program flow
• Believing exceptions happen without any error

2. Which of the following is the correct way to catch an exception in Python?

easy

A. try:
# code
except Exception:
# handle error

B. catch:
# code
try Exception:
# handle error

C. handle:
# code
catch Exception:
# handle error

D. try:
# code
catch Exception:
# handle error

Solution

1. Step 1: Recall Python syntax for exception handling

   Python uses try to run code and except to catch errors.

2. Step 2: Match the correct syntax

   try: # code except Exception: # handle error uses try and except Exception, which is correct.

3. Final Answer:

   try:\n # code\nexcept Exception:\n # handle error -> Option A

4. Quick Check:

   Use try and except keywords [OK]

Hint: Remember: try and except catch errors in Python [OK]

Common Mistakes:

• Using catch instead of except
• Swapping try and except keywords
• Incorrect keyword order or spelling

3. What will be the output of this code?

try:
    x = 5 / 0
except ZeroDivisionError:
    print('Cannot divide by zero')

medium

A. No output

B. 5

C. ZeroDivisionError

D. Cannot divide by zero

Solution

1. Step 1: Analyze the code inside try block

   The code tries to divide 5 by 0, which causes a ZeroDivisionError.

2. Step 2: Check the except block

   The except block catches ZeroDivisionError and prints 'Cannot divide by zero'.

3. Final Answer:

   Cannot divide by zero -> Option D

4. Quick Check:

   ZeroDivisionError caught prints message [OK]

Hint: Division by zero triggers ZeroDivisionError [OK]

Common Mistakes:

• Expecting program to crash without output
• Confusing error name with printed message
• Ignoring except block handling

4. Find the error in this code snippet:

try:
    print(10 / 2)
except ZeroDivisionError
    print('Error')

medium

A. No error in the code

B. Wrong exception type used

C. Missing colon after except statement

D. Missing try keyword

Solution

1. Step 1: Check syntax of except statement

   The except line lacks a colon at the end, which is required in Python.

2. Step 2: Confirm other parts are correct

   try keyword and exception type are correct; only colon is missing.

3. Final Answer:

   Missing colon after except statement -> Option C

4. Quick Check:

   except line must end with colon [OK]

Hint: Always put colon after except statement [OK]

Common Mistakes:

• Forgetting colon after except
• Assuming wrong exception type causes syntax error
• Thinking try keyword is missing

5. You want to open a file and read its content, but the file might not exist. Which code correctly handles this exception?

hard

A. try:
with open('data.txt') as f:
print(f.read())
except:
pass

B. try:
with open('data.txt') as f:
print(f.read())
except FileNotFoundError:
print('File not found')

C. try:
with open('data.txt') as f:
print(f.read())
except ZeroDivisionError:
print('File not found')

D. with open('data.txt') as f:
print(f.read())
except FileNotFoundError:
print('File not found')

Solution

1. Step 1: Understand the problem

   Opening a file that may not exist can cause FileNotFoundError.

2. Step 2: Check which option correctly catches FileNotFoundError

   try: with open('data.txt') as f: print(f.read()) except FileNotFoundError: print('File not found') uses try-except with FileNotFoundError and prints a message, which is correct.

3. Final Answer:

   try:\n with open('data.txt') as f:\n print(f.read())\nexcept FileNotFoundError:\n print('File not found') -> Option B

4. Quick Check:

   Catch FileNotFoundError to handle missing files [OK]

Hint: Catch FileNotFoundError to handle missing files [OK]

Common Mistakes:

• Placing except outside try block
• Catching wrong exception type
• Ignoring exception handling completely