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Pythonprogramming~10 mins

Try–except execution flow in Python - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to catch a division by zero error.

Python
try:
    result = 10 / 0
except [1]:
    print("Cannot divide by zero")
Drag options to blanks, or click blank then click option'
AZeroDivisionError
BValueError
CTypeError
DIndexError
Attempts:
3 left
💡 Hint
Common Mistakes
Using a wrong exception type like ValueError or TypeError.
Not catching the exception at all.
2fill in blank
medium

Complete the code to print a message when no error occurs.

Python
try:
    print("Hello")
except Exception:
    print("Error occurred")
else:
    [1]
Drag options to blanks, or click blank then click option'
Apass
Bprint("No errors!")
Craise
Dbreak
Attempts:
3 left
💡 Hint
Common Mistakes
Using raise inside else which re-raises an error.
Using break outside loops causing syntax error.
3fill in blank
hard

Fix the error in the except block to catch any exception.

Python
try:
    x = int('abc')
except [1]:
    print("Caught an error")
Drag options to blanks, or click blank then click option'
AException
BError
CBaseException
DValueError
Attempts:
3 left
💡 Hint
Common Mistakes
Using Error which is not a built-in exception class.
Using BaseException which is too broad and not recommended.
4fill in blank
hard

Fill both blanks to handle a file error and print a message.

Python
try:
    with open('file.txt', '[1]') as f:
        content = f.read()
except [2]:
    print("File not found")
Drag options to blanks, or click blank then click option'
Ar
Bw
CFileNotFoundError
DIOError
Attempts:
3 left
💡 Hint
Common Mistakes
Using write mode 'w' which creates the file instead of reading.
Catching IOError which is more general than FileNotFoundError.
5fill in blank
hard

Fill all three blanks to handle multiple exceptions and print the error type.

Python
try:
    num = int(input('Enter a number: '))
    result = 10 / num
except [1]:
    print("Cannot convert input to integer")
except [2]:
    print("Division by zero error")
except [3]:
    print("Some other error occurred")
Drag options to blanks, or click blank then click option'
AValueError
BZeroDivisionError
CException
DTypeError
Attempts:
3 left
💡 Hint
Common Mistakes
Mixing up exception types and their purposes.
Not including a general exception handler.

Practice

(1/5)
1. What is the main purpose of using a try-except block in Python?
easy
A. To speed up the program execution
B. To handle errors and prevent the program from crashing
C. To repeat a block of code multiple times
D. To define a new function

Solution

  1. Step 1: Understand the role of try block

    The try block contains code that might cause an error during execution.
  2. Step 2: Understand the role of except block

    The except block catches and handles the error so the program does not stop abruptly.
  3. Final Answer:

    To handle errors and prevent the program from crashing -> Option B
  4. Quick Check:

    Try-except handles errors = B [OK]
Hint: Try-except blocks catch errors to keep programs running [OK]
Common Mistakes:
  • Thinking try-except speeds up code
  • Confusing try-except with loops
  • Using try-except to define functions
2. Which of the following is the correct syntax to catch a ZeroDivisionError in Python?
easy
A. try: x = 1/0 except ZeroDivisionError: print('Cannot divide by zero')
B. try: x = 1/0 catch ZeroDivisionError: print('Cannot divide by zero')
C. try: x = 1/0 except: print('Error') finally ZeroDivisionError:
D. try: x = 1/0 except ZeroDivisionError then: print('Cannot divide by zero')

Solution

  1. Step 1: Identify correct try-except syntax

    Python uses try: followed by except ExceptionType: to catch errors.
  2. Step 2: Check each option for syntax errors

    try: x = 1/0 except ZeroDivisionError: print('Cannot divide by zero') uses correct except ZeroDivisionError: syntax; others use invalid keywords like catch or incorrect formatting.
  3. Final Answer:

    try: x = 1/0 except ZeroDivisionError: print('Cannot divide by zero') -> Option A
  4. Quick Check:

    Correct except syntax = A [OK]
Hint: Use 'except ExceptionType:' to catch specific errors [OK]
Common Mistakes:
  • Using 'catch' instead of 'except'
  • Adding 'then' after except
  • Misplacing 'finally' keyword
3. What will be the output of the following code?
try:
    print('Start')
    x = 5 / 0
    print('End')
except ZeroDivisionError:
    print('Error caught')
print('Done')
medium
A. Start End Error caught Done
B. Error caught Done
C. Start Done
D. Start Error caught Done

Solution

  1. Step 1: Trace code inside try block

    It prints 'Start', then tries to divide 5 by 0, which raises ZeroDivisionError before printing 'End'.
  2. Step 2: Handle exception and continue

    The except block catches the error and prints 'Error caught'. After that, the program continues and prints 'Done'.
  3. Final Answer:

    Start Error caught Done -> Option D
  4. Quick Check:

    Exception stops try block, except runs = C [OK]
Hint: Error stops try; except runs; code after try-except runs [OK]
Common Mistakes:
  • Assuming 'End' prints after error
  • Missing that except block runs
  • Thinking program stops after error
4. Identify the error in this code snippet:
try:
    print('Hello')
except ValueError
    print('Value error occurred')
medium
A. try block cannot have print statements
B. Missing parentheses after except
C. Missing colon ':' after except ValueError
D. except block must come before try block

Solution

  1. Step 1: Check syntax of except statement

    The except line must end with a colon ':' to define the block.
  2. Step 2: Identify missing colon

    In the code, except ValueError is missing the colon, causing a syntax error.
  3. Final Answer:

    Missing colon ':' after except ValueError -> Option C
  4. Quick Check:

    except line needs ':' = A [OK]
Hint: Always put ':' after except ExceptionType [OK]
Common Mistakes:
  • Forgetting colon after except
  • Adding parentheses after except
  • Misordering try and except blocks
5. You want to safely convert user input to an integer, using try-except-else and catching ValueError specifically, printing 'Invalid input' for invalid input and 'Input is', num for valid input, without stopping the program. Which code does this?
hard
A. try: num = int(input('Enter number: ')) except ValueError: print('Invalid input') else: print('Input is', num)
B. try: num = int(input('Enter number: ')) except: print('Invalid input') else: print('Input is', num)
C. try: num = int(input('Enter number: ')) except ValueError: print('Invalid input') finally: print('Done')
D. try: num = int(input('Enter number: ')) except ValueError: print('Invalid input')

Solution

  1. Step 1: Understand try-except-else structure

    The try block attempts conversion; except handles errors; else runs if no error occurs.
  2. Step 2: Check which option prints 'Invalid input' on error and shows input if valid

    try: num = int(input('Enter number: ')) except ValueError: print('Invalid input') else: print('Input is', num) correctly prints 'Invalid input' on ValueError and prints the number if conversion succeeds.
  3. Final Answer:

    try: num = int(input('Enter number: ')) except ValueError: print('Invalid input') else: print('Input is', num) -> Option A
  4. Quick Check:

    Use except for errors, else for success = D [OK]
Hint: Use except for errors and else for success actions [OK]
Common Mistakes:
  • Not using else to handle successful input
  • Catching all exceptions without specifying
  • Missing error handling causing crash