Overwrite vs append behavior in Python - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to add a new item to the list without removing existing items.

Python

my_list = [1, 2, 3]
my_list.[1](4)
print(my_list)

Drag options to blanks, or click blank then click option'

Ainsert

Bextend

Cappend

Dremove

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'extend' adds multiple items and expects an iterable.

Using 'remove' deletes an item instead of adding.

The append method adds a single item to the end of the list without removing existing items.

2fill in blank

medium

Complete the code to replace the value of the key 'name' in the dictionary.

Python

person = {'name': 'Alice', 'age': 30}
person['name'] = [1]
print(person)

Drag options to blanks, or click blank then click option'

A'Bob'

B'Alice'

C'30'

D'age'

Attempts:

3 left

💡 Hint

Common Mistakes

Using the old value again instead of the new one.

Forgetting quotes around the string.

Assigning a new value to person['name'] overwrites the old value.

3fill in blank

hard

Fix the error in the code to add a new key-value pair to the dictionary without overwriting existing keys.

Python

settings = {'volume': 5, 'brightness': 7}
settings.[1]({'contrast': 10})
print(settings)

Drag options to blanks, or click blank then click option'

Aappend

Bupdate

Cadd

Dextend

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'append' which is not a dictionary method.

Using 'add' which does not exist for dictionaries.

The update method adds new key-value pairs or updates existing keys without removing other keys.

4fill in blank

hard

Fill both blanks to create a dictionary with word lengths only for words longer than 3 letters.

Python

words = ['cat', 'house', 'dog', 'elephant']
lengths = {word: [1] for word in words if len(word) [2] 3}
print(lengths)

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Alen(word)

Bword

C>

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself instead of its length.

Using the wrong comparison operator.

We use len(word) to get the length and filter words with length greater than 3 using >.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values only if the value is greater than 0.

Python

data = {'a': 1, 'b': 0, 'c': 3}
result = [1]: [2] for k, v in data.items() if v [3] 0
print(result)

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Not converting keys to uppercase.

Using wrong comparison operator or filtering condition.

Keys are converted to uppercase with k.upper(), values are v, and we filter values greater than 0 using >.