[Solved] What will be the output of this code?class A: def __init__(self): self.__x = 10 a = A() print(hasattr(a, '__x')) print(hasattr(a, '_A__x')) | Python

Python - Encapsulation and Data Protection

What will be the output of this code?

class A:
    def __init__(self):
        self.__x = 10

a = A()
print(hasattr(a, '__x'))
print(hasattr(a, '_A__x'))

ATrue\nTrue

BFalse\nTrue

CTrue\nFalse

DFalse\nFalse

Step-by-Step Solution

Solution:

Step 1: Check attribute __x existence
Due to name mangling, __x is stored as _A__x internally, so hasattr(a, '__x') returns False.
Step 2: Check mangled attribute _A__x existence
hasattr(a, '_A__x') returns True because this is the mangled name storing the value.
Final Answer:
False True -> Option B
Quick Check:
__x hidden as _A__x = False, True [OK]

Quick Trick: Check mangled name with _ClassName__attr [OK]

Common Mistakes:

Master "Encapsulation and Data Protection" in Python

9 interactive learning modes - each teaches the same concept differently

More Python Quizzes

What will be the output of this code?