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Why does the with statement guarantee resource cleanup even if an error occurs inside its block?

hard📝 Conceptual Q10 of 15
Python - Context Managers
Why does the with statement guarantee resource cleanup even if an error occurs inside its block?
ABecause it ignores all errors inside the block
BBecause it closes resources only if no error occurs
CBecause it restarts the block automatically
DBecause it calls the resource's __exit__ method on block exit
Step-by-Step Solution
Solution:
  1. Step 1: Understand the role of __exit__ in context managers

    The __exit__ method is called when the block finishes, even if an error happens.
  2. Step 2: Recognize that __exit__ handles cleanup

    This method ensures resources are cleaned up regardless of exceptions.
  3. Final Answer:

    Because it calls the resource's __exit__ method on block exit -> Option D
  4. Quick Check:

    With calls __exit__ on exit = cleanup always [OK]
Quick Trick: With calls __exit__ method to ensure cleanup [OK]
Common Mistakes:
  • Thinking errors are ignored
  • Believing block restarts
  • Assuming cleanup only on no error

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