Solution:Step 1: Understand list of Employee objectsemployees is a list of Employee instances with name and salary attributes.Step 2: Use dictionary comprehension to map names to salariessalary_dict = {e.name: e.salary for e in employees} correctly uses e.name and e.salary for each object e.Final An

[Solved] Given this class:class Employee: def __init__(self, name, salary): self.name = name self.... | Python

Python - Classes and Object Lifecycle

Given this class:

class Employee:
    def __init__(self, name, salary):
        self.name = name
        self.salary = salary

employees = [
    Employee('John', 5000),
    Employee('Jane', 6000),
    Employee('Doe', 5500)
]

How can you create a dictionary mapping employee names to their salaries using these objects?

Asalary_dict = {employees.name: employees.salary}

Bsalary_dict = {e.name: e.salary for e in employees}

Csalary_dict = dict(employees)

Dsalary_dict = {name: salary for name, salary in employees}

Step-by-Step Solution

Solution:

Step 1: Understand list of Employee objects
employees is a list of Employee instances with name and salary attributes.
Step 2: Use dictionary comprehension to map names to salaries
salary_dict = {e.name: e.salary for e in employees} correctly uses e.name and e.salary for each object e.
Final Answer:
salary_dict = {e.name: e.salary for e in employees} -> Option B
Quick Check:
Use dict comprehension with object attributes [OK]

Quick Trick: Use {obj.attr: obj.attr2 for obj in list} to create dict [OK]

Common Mistakes:

Trying to unpack objects directly
Using class name instead of object variable

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Given this class:

Step 1: Understand list of Employee objects

Step 2: Use dictionary comprehension to map names to salaries

Final Answer:

Quick Check:

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