Math-related operations in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to calculate the square of 4.

Python

result = 4 [1] 2
print(result)

Drag options to blanks, or click blank then click option'

A+

B*

C**

D//

Attempts:

3 left

💡 Hint

Common Mistakes

Using '*' instead of '**' will multiply but not raise to power.

Using '+' will add numbers instead of exponentiation.

The ** operator is used to raise a number to the power of another number. Here, 4 squared is 4².

2fill in blank

medium

Complete the code to find the remainder when 17 is divided by 5.

Python

remainder = 17 [1] 5
print(remainder)

Drag options to blanks, or click blank then click option'

A%

B*

C//

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using '//' gives the quotient, not the remainder.

Using '*' or '+' will not give the remainder.

The % operator gives the remainder of division. 17 % 5 equals 2.

3fill in blank

hard

Fix the error in the code to calculate the integer division of 15 by 4.

Python

result = 15 [1] 4
print(result)

Drag options to blanks, or click blank then click option'

A%

B*

C/

D//

Attempts:

3 left

💡 Hint

Common Mistakes

Using '/' returns a float, not an integer.

Using '%' returns the remainder, not the quotient.

The // operator performs integer division, giving the quotient without the remainder. 15 // 4 equals 3.

4fill in blank

hard

Fill both blanks to create a dictionary of squares for numbers 1 to 5, but only include squares greater than 10.

Python

squares = {x: x[1]2 for x in range(1, 6) if x[1]2[2]10}
print(squares)

Drag options to blanks, or click blank then click option'

A**

B*

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '*' instead of '**' will multiply but not square.

Using '<' instead of '>' will filter the wrong numbers.

Use ** to square the number and > to filter squares greater than 10.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys, values as numbers, and only include values greater than 2.

Python

result = [1]: [2] for [3], [2] in {'a':1, 'b':3, 'c':5}.items() if [2] > 2}
print(result)

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

Ck

Ditem

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'item' instead of 'k' and 'v' for loop variables.

Not converting keys to uppercase.

Mixing up keys and values in the dictionary comprehension.

Use k.upper() for uppercase keys, v for values, and k as the key variable in the loop.

Practice

1. Which operator in Python is used to find the remainder of a division?

easy

A. The multiplication operator *

B. The division operator /

C. The exponent operator **

D. The modulus operator %

Solution

1. Step 1: Understand the modulus operator

   The modulus operator % returns the remainder after division of one number by another.

2. Step 2: Compare with other operators

   The division operator / returns the quotient, exponent ** raises to power, and multiplication * multiplies numbers.

3. Final Answer:

   The modulus operator % -> Option D

4. Quick Check:

   Remainder = % operator [OK]

Hint: Remainder uses % operator in math [OK]

Common Mistakes:

• Confusing / with %
• Using * for remainder
• Thinking ** gives remainder

2. Which of the following is the correct operator syntax to calculate 3 to the power of 4 in Python?

easy

A. 3 ^ 4

B. 3 ^^ 4

C. 3 ** 4

D. pow(3, 4)

Solution

1. Step 1: Identify the exponent operator in Python

   Python uses ** to calculate powers, so 3 ** 4 means 3 to the power 4.

2. Step 2: Check other options

   3 ^ 4 is bitwise XOR, pow(3, 4) is a function but not syntax operator, 3 ^^ 4 is invalid syntax.

3. Final Answer:

   3 ** 4 -> Option C

4. Quick Check:

   Power uses ** operator [OK]

Hint: Use ** for powers, not ^ [OK]

Common Mistakes:

• Using ^ instead of **
• Trying ^^ which is invalid
• Confusing pow() function with operator

3. What is the output of this Python code?

result = 10 % 3
print(result)

medium

A. 1

B. 3

C. 0

D. 10

Solution

1. Step 1: Calculate 10 modulo 3

   10 divided by 3 is 3 with remainder 1, so 10 % 3 equals 1.

2. Step 2: Understand print output

   The print statement outputs the value stored in result, which is 1.

3. Final Answer:

   1 -> Option A

4. Quick Check:

   10 % 3 = 1 [OK]

Hint: Modulo gives remainder after division [OK]

Common Mistakes:

• Confusing modulo with division
• Expecting quotient instead of remainder
• Misreading print output

4. Find the error in this code snippet:

value = 5 **
print(value)

medium

A. print() function is used incorrectly

B. Missing second operand for exponent operator

C. Exponent operator should be ^

D. Variable name 'value' is invalid

Solution

1. Step 1: Check the exponent operator usage

   The exponent operator ** needs two numbers, but here only one number (5) is given before it.

2. Step 2: Identify syntax error

   Because the second operand is missing, Python will raise a syntax error before print runs.

3. Final Answer:

   Missing second operand for exponent operator -> Option B

4. Quick Check:

   ** needs two numbers [OK]

Hint: Exponent needs two numbers, not one [OK]

Common Mistakes:

• Using ^ instead of **
• Thinking print() is wrong here
• Assuming variable name causes error

5. You want to calculate the area of a circle with radius 7 using Python. Which code correctly uses math operations to do this?

import math
radius = 7
area = ?
print(area)

hard

A. area = math.pi * (radius ** 2)

B. area = math.pi ** radius

C. area = pi * radius * radius

D. area = math.pi + radius ** 2

Solution

1. Step 1: Recall formula for circle area

   The area of a circle is π times radius squared, or π * r².

2. Step 2: Translate formula to Python code

   Use math.pi for π and radius ** 2 for radius squared, so math.pi * (radius ** 2).

3. Final Answer:

   area = math.pi * (radius ** 2) -> Option A

4. Quick Check:

   Area = π * r² [OK]

Hint: Use ** 2 for square, multiply by math.pi [OK]

Common Mistakes:

• Using addition instead of multiplication
• Using exponent on pi instead of radius
• Forgetting to square radius