Handling specific exceptions in Python - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of specific exception handling

What is the output of this code when the input is 0?

Python

try:
    result = 10 / 0
except ZeroDivisionError:
    print("Cannot divide by zero")
except Exception:
    print("Some other error")

A No output

B Some other error

C 0

D Cannot divide by zero

💡 Hint

Think about which exception is raised by dividing by zero.

Dividing by zero raises a ZeroDivisionError, so the first except block runs and prints "Cannot divide by zero".

❓ Predict Output

intermediate

Output when catching multiple exceptions

What will this code print?

Python

try:
    x = int('abc')
except (ValueError, TypeError):
    print("Caught ValueError or TypeError")
except Exception:
    print("Caught some other exception")

A Caught some other exception

B Caught ValueError or TypeError

C abc

D No output

💡 Hint

What exception does int('abc') raise?

int('abc') raises a ValueError, which is caught by the first except block.

❓ Predict Output

advanced

Exception handling with else and finally

What is the output of this code?

Python

try:
    print("Start")
    x = 5 / 1
except ZeroDivisionError:
    print("Divide by zero error")
else:
    print("No error occurred")
finally:
    print("Always runs")

A

Start
No error occurred
Always runs

B

Start
Divide by zero error
Always runs

C

No error occurred
Always runs

D

Start
Always runs

💡 Hint

Consider what happens when no exception is raised.

Since 5/1 does not raise an error, the else block runs after try, then finally always runs.

❓ Predict Output

advanced

What error is raised?

What error does this code raise?

Python

try:
    d = {'a': 1}
    print(d['b'])
except KeyError:
    print("Key not found")
except Exception:
    print("Other error")

A None

B Other error

C Key not found

D KeyError exception not caught

💡 Hint

What happens when you access a missing key in a dictionary?

Accessing d['b'] raises a KeyError, which is caught by the first except block.

❓ Predict Output

expert

Output with nested try-except and re-raising

What is the output of this code?

Python

try:
    try:
        x = 1 / 0
    except ZeroDivisionError:
        print("Inner catch")
        raise
except ZeroDivisionError:
    print("Outer catch")

A

Inner catch
Outer catch

B Inner catch

C Outer catch

D No output

💡 Hint

What happens when an exception is re-raised inside an except block?

The inner except catches and prints "Inner catch", then re-raises the exception. The outer except catches it and prints "Outer catch".