Formatting structured data in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to convert the dictionary to a JSON string.

Python

import json

person = {"name": "Alice", "age": 30}
json_str = json.[1](person)
print(json_str)

Drag options to blanks, or click blank then click option'

Adumps

Bloads

Cload

Ddump

Attempts:

3 left

💡 Hint

Common Mistakes

Using json.load or json.loads instead of json.dumps

Confusing dump and dumps functions

The json.dumps() function converts a Python object into a JSON string.

2fill in blank

medium

Complete the code to pretty-print the JSON string with indentation.

Python

import json

data = {"city": "Paris", "population": 2148327}
pretty_json = json.dumps(data, [1]=4)
print(pretty_json)

Drag options to blanks, or click blank then click option'

Aensure_ascii

Bsort_keys

Cseparators

Dindent

Attempts:

3 left

💡 Hint

Common Mistakes

Using sort_keys instead of indent

Forgetting to set indent to a number

The indent parameter adds spaces to format the JSON string nicely.

3fill in blank

hard

Fix the error in the code to load JSON data from a string.

Python

import json

json_data = '{"fruit": "apple", "count": 10}'
data = json.[1](json_data)
print(data)

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Aloads

Bdumps

Cload

Ddump

Attempts:

3 left

💡 Hint

Common Mistakes

Using json.load instead of json.loads

Using json.dumps or json.dump which write JSON

The json.loads() function reads a JSON string and converts it to a Python object.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if length is greater than 3.

Python

words = ["apple", "bat", "cat", "door"]
lengths = {word: [1] for word in words if [2] > 3}
print(lengths)

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Alen(word)

Bword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length

Checking the word instead of its length in the condition

The first blank needs len(word) to get the length. The second blank also needs len(word) to check if length is greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their counts only if count is positive.

Python

counts = {"apple": 2, "banana": 0, "cherry": 5}
result = { [1]: [2] for [3], count in counts.items() if count > 0 }
print(result)

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Aword.upper()

Bcount

Cword

Dfruit

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong variable names in the loop

Not converting the word to uppercase for the key

The key is the uppercase word (word.upper()), the value is the count, and the loop variable is word.