File path handling in Python - Mini Project: Build & Apply

File path handling

📖 Scenario: You are organizing files on your computer. You want to work with file paths to find out folder names and file names easily.

🎯 Goal: You will create a program that uses file path handling to extract folder names and file names from a given path.

📋 What You'll Learn

Create a variable with a file path string

Create a variable to hold the folder name from the path

Create a variable to hold the file name from the path

Print the folder name and file name

💡 Why This Matters

🌍 Real World

File path handling is useful when working with files on your computer, like organizing documents or reading data files.

💼 Career

Many programming jobs require working with file paths to read, write, or organize files correctly across different operating systems.

1

Create the file path variable

Create a variable called file_path and set it to the string "/home/user/documents/report.txt".

Python

# Create a variable called file_path with the exact string
# Your code here

Hint

Use quotes around the path string exactly as shown.

2

Import pathlib and create folder name variable

Import the Path class from the pathlib module. Then create a variable called folder_name that gets the parent folder of file_path using Path(file_path).parent.

Python

file_path = "/home/user/documents/report.txt"
# Import Path from pathlib and create folder_name using Path(file_path).parent
# Your code here

Hint

Use from pathlib import Path to import. Use Path(file_path).parent to get the folder.

3

Create file name variable

Create a variable called file_name that gets the file name from file_path using Path(file_path).name.

Python

from pathlib import Path
file_path = "/home/user/documents/report.txt"
folder_name = Path(file_path).parent
# Create file_name using Path(file_path).name
# Your code here

Hint

Use Path(file_path).name to get the file name.

4

Print folder name and file name

Print the folder_name and file_name variables on separate lines using two print statements.

Python

from pathlib import Path
file_path = "/home/user/documents/report.txt"
folder_name = Path(file_path).parent
file_name = Path(file_path).name
# Print folder_name and file_name on separate lines
# Your code here

Hint

Use two print statements: print(folder_name) and print(file_name).

Practice

1. Which Python module is recommended for safe and easy file path handling?

easy

A. pathlib

B. os.path

C. sys

D. math

Solution

1. Step 1: Identify the module for file paths

   The pathlib module provides an easy and modern way to handle file paths safely.

2. Step 2: Compare with other modules

   While os.path also handles paths, pathlib is recommended for its simplicity and object-oriented approach.

3. Final Answer:

   pathlib -> Option A

4. Quick Check:

   File path handling = pathlib [OK]

Hint: Remember: pathlib is the modern way to handle paths [OK]

Common Mistakes:

• Confusing pathlib with os.path
• Using sys for paths
• Choosing unrelated modules like math

2. Which of the following is the correct way to join paths using pathlib in Python?

easy

A. Path('folder') + 'file.txt'

B. Path('folder') / 'file.txt'

C. Path('folder').join('file.txt')

D. Path('folder').append('file.txt')

Solution

1. Step 1: Understand pathlib path joining

   In pathlib, the slash operator / is overloaded to join paths safely.

2. Step 2: Check each option

   Path('folder') / 'file.txt' uses / correctly. Path('folder') + 'file.txt' uses + which is invalid. The .append() and .join() methods do not exist on Path objects.

3. Final Answer:

   Path('folder') / 'file.txt' -> Option B

4. Quick Check:

   Use slash (/) to join paths [OK]

Hint: Use / operator to join pathlib paths [OK]

Common Mistakes:

• Using + to join paths
• Calling non-existent join or append methods
• Forgetting to import pathlib

3. What will be the output of this code?

from pathlib import Path
p = Path('folder') / 'subfolder' / 'file.txt'
print(p.parts)

medium

A. ('folder/subfolder/file.txt',)

B. ['folder', 'subfolder', 'file.txt']

C. ['folder/subfolder/file.txt']

D. ('folder', 'subfolder', 'file.txt')

Solution

1. Step 1: Understand Path.parts attribute

   The parts attribute returns a tuple of each part of the path as separate strings.

2. Step 2: Analyze the given path

   The path is 'folder/subfolder/file.txt', so parts will be ('folder', 'subfolder', 'file.txt').

3. Final Answer:

   ('folder', 'subfolder', 'file.txt') -> Option D

4. Quick Check:

   Path.parts returns tuple of path parts [OK]

Hint: Path.parts returns a tuple of path components [OK]

Common Mistakes:

• Expecting a list instead of tuple
• Getting full path as one string
• Confusing parts with name or stem

4. What is wrong with this code snippet?

from pathlib import Path
p = Path('folder') + 'file.txt'
print(p)

medium

A. Using + operator to join paths causes TypeError

B. Missing import statement for os module

C. Path object cannot be printed directly

D. The path string should use backslashes instead of forward slashes

Solution

1. Step 1: Check path joining method

   The code uses + operator to join a Path object and a string, which is not supported and raises a TypeError.

2. Step 2: Verify other options

   Import is correct, Path objects can be printed, and forward slashes are valid on most systems.

3. Final Answer:

   Using + operator to join paths causes TypeError -> Option A

4. Quick Check:

   Use /, not +, to join pathlib paths [OK]

Hint: Never use + to join pathlib paths; use / instead [OK]

Common Mistakes:

• Using + operator for path joining
• Thinking Path can't be printed
• Confusing path separators

5. You want to check if a file named data.csv exists inside a folder reports before reading it. Which code correctly does this using pathlib?

hard

A. p = Path('reports') + 'data.csv'
if p.is_file():
print('File found')

B. p = 'reports/data.csv'
if os.path.exists(p):
print('File found')

C. p = Path('reports') / 'data.csv'
if p.exists():
print('File found')

D. p = Path('reports/data.csv')
if p.is_dir():
print('File found')

Solution

1. Step 1: Create path using pathlib and join correctly

   p = Path('reports') / 'data.csv' if p.exists(): print('File found') uses Path('reports') / 'data.csv' which correctly joins folder and file.

2. Step 2: Check if file exists

   p = Path('reports') / 'data.csv' if p.exists(): print('File found') uses p.exists() to check if the file exists before reading, which is correct.

3. Final Answer:

   p = Path('reports') / 'data.csv'\nif p.exists():\n print('File found') -> Option C

4. Quick Check:

   Use pathlib with / and exists() to check files [OK]

Hint: Use Path(...) / filename and exists() to check files [OK]

Common Mistakes:

• Using + to join paths
• Using os.path without import
• Checking is_dir() instead of exists() or is_file()