Comparison magic methods in Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define the method that checks if two objects are equal.

Python

class Box:
    def __eq__(self, other):
        return self.size [1] other.size

Drag options to blanks, or click blank then click option'

A!=

B=

C==

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using a single '=' which is assignment, not comparison.

Using '!=' which checks for inequality.

The __eq__ method should return True if the sizes are equal, so we use the == operator.

2fill in blank

medium

Complete the code to define the method that checks if one object is less than another.

Python

class Box:
    def __lt__(self, other):
        return self.weight [1] other.weight

Drag options to blanks, or click blank then click option'

A<

B>

C==

D>=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' which means greater than.

Using '==' which means equal.

The __lt__ method means 'less than', so we use the < operator.

3fill in blank

hard

Fix the error in the method that checks if one object is greater than or equal to another.

Python

class Box:
    def __ge__(self, other):
        return self.height [1] other.height

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A<=

B>=

C=>

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=>' which is not a valid Python operator.

Using '<=' which means less than or equal.

The correct operator for 'greater than or equal to' is >=. The symbol => is invalid in Python.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if the length is greater than 3.

Python

words = ['apple', 'bat', 'carrot', 'dog']
lengths = {word: [1] for word in words if len(word) [2] 3}

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Alen(word)

B>

C<

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length.

Using '<' instead of '>' in the condition.

The dictionary maps each word to its length, so the value is len(word). The condition keeps words longer than 3, so the operator is >.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase keys to values only if the value is positive.

Python

data = {'a': 1, 'b': -2, 'c': 3}
result = { [1]: [2] for k, v in data.items() if v [3] 0 }

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Ak.upper()

Bv

C>

Dk

Attempts:

3 left

💡 Hint

Common Mistakes

Using original keys without uppercase.

Using '<' instead of '>' in the condition.

Swapping keys and values.

The keys are converted to uppercase with k.upper(). The values are v. The condition keeps values greater than 0, so the operator is >.