Common exception types in Python - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

What is the output of this code?

Look at the code below. What will it print when run?

Python

try:
    x = 5 / 0
except ZeroDivisionError:
    print("Error caught")

A ZeroDivisionError

B Error caught

C 5

D No output

💡 Hint

Think about what happens when you divide by zero in Python.

Dividing by zero raises a ZeroDivisionError. The except block catches it and prints "Error caught".

❓ Predict Output

intermediate

What error does this code raise?

What error will this code produce when run?

Python

my_list = [1, 2, 3]
print(my_list[5])

A IndexError

B KeyError

C TypeError

D ValueError

💡 Hint

Think about what happens when you try to access a list element with an invalid index.

Accessing an index that is out of range in a list raises an IndexError.

❓ Predict Output

advanced

What is the output of this code?

What will this code print?

Python

d = {'a': 1, 'b': 2}
try:
    print(d['c'])
except KeyError:
    print('Key not found')

A KeyError

B 1

C Key not found

D None

💡 Hint

What happens when you try to access a dictionary key that does not exist?

Accessing a missing key in a dictionary raises a KeyError, which is caught and prints 'Key not found'.

❓ Predict Output

advanced

What error does this code raise?

What error will this code produce?

Python

x = 'hello'
print(x + 5)

A TypeError

B ValueError

C NameError

D SyntaxError

💡 Hint

Think about adding a string and a number.

You cannot add a string and an integer directly, so Python raises a TypeError.

❓ Predict Output

expert

What is the output of this code?

What will this code print when run?

Python

try:
    a = int('abc')
except ValueError:
    print('Conversion failed')
else:
    print('Conversion succeeded')

A No output

B Conversion succeeded

C ValueError

D Conversion failed

💡 Hint

What happens when you try to convert a non-numeric string to int?

int('abc') raises a ValueError, so the except block runs and prints 'Conversion failed'.

Practice

1. Which exception is raised when you try to divide a number by zero in Python?

easy

A. ValueError

B. ZeroDivisionError

C. IndexError

D. TypeError

Solution

1. Step 1: Understand division by zero

   Dividing any number by zero is mathematically undefined and causes an error in Python.

2. Step 2: Identify the exception type

   Python raises a ZeroDivisionError when division by zero occurs.

3. Final Answer:

   ZeroDivisionError -> Option B

4. Quick Check:

   Division by zero = ZeroDivisionError [OK]

Hint: Division by zero always raises ZeroDivisionError [OK]

Common Mistakes:

• Confusing ZeroDivisionError with ValueError
• Thinking IndexError occurs for division
• Assuming TypeError is raised for zero division

2. Which of the following code snippets will raise a ValueError?

easy

A. open('file.txt')

B. 5 / 0

C. my_list[10] where my_list has 5 elements

D. int('abc')

Solution

1. Step 1: Analyze each option for ValueError

   int('abc') tries to convert a non-numeric string to int, which causes ValueError.

2. Step 2: Check other options for different exceptions

   5 / 0 causes ZeroDivisionError, C causes IndexError, A may cause FileNotFoundError.

3. Final Answer:

   int('abc') -> Option D

4. Quick Check:

   Invalid int conversion = ValueError [OK]

Hint: ValueError occurs when conversion or value is invalid [OK]

Common Mistakes:

• Confusing ZeroDivisionError with ValueError
• Assuming file open errors cause ValueError
• Mixing IndexError with ValueError

3. What will be the output of this code?

my_list = [1, 2, 3]
print(my_list[3])

medium

A. IndexError

B. 3

C. None

D. ValueError

Solution

1. Step 1: Understand list indexing

   List indices start at 0, so valid indices for my_list are 0, 1, 2.

2. Step 2: Accessing index 3

   Index 3 is out of range, so Python raises an IndexError.

3. Final Answer:

   IndexError -> Option A

4. Quick Check:

   Out of range index = IndexError [OK]

Hint: Accessing invalid list index raises IndexError [OK]

Common Mistakes:

• Thinking it returns last element
• Assuming None is returned for invalid index
• Confusing IndexError with ValueError

4. Identify the error in this code snippet:

try:
    x = int('hello')
except ZeroDivisionError:
    print('Cannot divide by zero')

medium

A. Wrong exception caught, should catch ValueError

B. SyntaxError due to missing colon

C. No error, code runs fine

D. ZeroDivisionError will be raised

Solution

1. Step 1: Analyze the try block

   int('hello') raises ValueError because 'hello' cannot convert to int.

2. Step 2: Check except block

   Except block catches ZeroDivisionError, which does not handle ValueError, so error is uncaught.

3. Final Answer:

   Wrong exception caught, should catch ValueError -> Option A

4. Quick Check:

   Exception type mismatch = catch correct exception [OK]

Hint: Catch the exact exception your code may raise [OK]

Common Mistakes:

• Catching wrong exception type
• Assuming code runs without error
• Confusing syntax errors with exception handling

5. You want to safely convert user input to an integer and print it. Which code correctly handles invalid input without crashing?

hard

A. try:
num = int(input())
except ZeroDivisionError:
print('Invalid number')

B. num = int(input())
print(num)

C. try:
num = int(input())
except ValueError:
print('Invalid number')

D. num = input()
print(int(num))

Solution

1. Step 1: Understand input conversion risks

   User input may not be a valid integer, causing ValueError on conversion.

2. Step 2: Check exception handling

   try: num = int(input()) except ValueError: print('Invalid number') uses try-except to catch ValueError and print a message, preventing crash.

3. Final Answer:

   try-except catching ValueError with message -> Option C

4. Quick Check:

   Handle invalid input with ValueError catch [OK]

Hint: Use try-except to catch ValueError on int conversion [OK]

Common Mistakes:

• Not catching exceptions causing program crash
• Catching wrong exception type like ZeroDivisionError
• Assuming input is always valid integer