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Pythonprogramming~10 mins

Automatic resource cleanup in Python - Interactive Code Practice

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Test this pattern10 questions across easy, medium, and hard to know if this pattern is strong
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to open a file using a context manager.

Python
with open('example.txt', [1]) as file:
    content = file.read()
Drag options to blanks, or click blank then click option'
A'open'
B'r'
C'write'
D'close'
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'write' instead of 'r' causes the file to open for writing, which may overwrite content.
Using 'open' or 'close' as mode strings are invalid.
2fill in blank
medium

Complete the code to automatically close the file after reading.

Python
with open('data.txt', 'r') as [1]:
    data = file.read()
Drag options to blanks, or click blank then click option'
Afile
Bread
Copen
Df
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'open' or 'read' as variable names causes errors.
Using 'f' is common but here 'file' matches the code below.
3fill in blank
hard

Fix the error in the code to ensure the file is closed automatically.

Python
file = open('log.txt', 'r')
try:
    content = [1].read()
finally:
    file.close()
Drag options to blanks, or click blank then click option'
Afile
Bopen
Cread
Dclose
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'open.read()' causes an error because open is a function, not the file object.
Using 'read.read()' or 'close.read()' are invalid.
4fill in blank
hard

Fill both blanks to create a dictionary with word lengths for words longer than 3 characters.

Python
lengths = {word: [1] for word in words if len(word) [2] 3}
Drag options to blanks, or click blank then click option'
Alen(word)
B>
C<
Dword
Attempts:
3 left
💡 Hint
Common Mistakes
Using '<' instead of '>' filters shorter words.
Using 'word' instead of len(word) gives the word itself, not its length.
5fill in blank
hard

Fill all three blanks to create a dictionary with uppercase keys and values greater than zero.

Python
result = [1]: [2] for k, v in data.items() if v [3] 0}
Drag options to blanks, or click blank then click option'
Ak.upper()
Bv
C>
Dk
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'k' instead of 'k.upper()' keeps keys as original case.
Using '<' instead of '>' filters values less than zero.
Using 'k' or 'v' incorrectly in keys or values.

Practice

(1/5)
1. What is the main purpose of using the with statement in Python for resource management?
easy
A. To create infinite loops easily
B. To automatically release resources like files or locks after use
C. To define functions inside other functions
D. To import modules dynamically

Solution

  1. Step 1: Understand resource management

    The with statement is designed to handle resources such as files or locks safely.
  2. Step 2: Identify automatic cleanup

    It ensures resources are released automatically after the block finishes, preventing leaks.
  3. Final Answer:

    To automatically release resources like files or locks after use -> Option B
  4. Quick Check:

    Automatic cleanup = To automatically release resources like files or locks after use [OK]
Hint: Think: with = automatic resource release [OK]
Common Mistakes:
  • Confusing with loops or function definitions
  • Thinking it imports modules
  • Assuming manual cleanup is still needed
2. Which of the following is the correct syntax to open a file for reading using automatic resource cleanup?
easy
A. open with('file.txt', 'r') as f:
B. with open('file.txt', 'r') f:
C. with open('file.txt', 'r') as f:
D. open('file.txt', 'r') with as f:

Solution

  1. Step 1: Recall correct with syntax

    The correct syntax starts with with, followed by the resource expression, then as and a variable.
  2. Step 2: Match syntax to options

    with open('file.txt', 'r') as f: matches the correct pattern: with open('file.txt', 'r') as f:
  3. Final Answer:

    with open('file.txt', 'r') as f: -> Option C
  4. Quick Check:

    Correct with syntax = with open('file.txt', 'r') as f: [OK]
Hint: Remember: with + resource + as + variable [OK]
Common Mistakes:
  • Misplacing 'with' keyword
  • Omitting 'as' keyword
  • Wrong order of keywords
3. What will be the output of this code?
with open('test.txt', 'w') as f:
    f.write('Hello')
print(f.closed)
medium
A. Error: f is not defined
B. False
C. Hello
D. True

Solution

  1. Step 1: Understand the with block effect

    The file is opened and written inside the with block, which automatically closes the file after the block ends.
  2. Step 2: Check the f.closed property after block

    After the block, the variable f is out of scope and not defined, so accessing f.closed raises a NameError.
  3. Final Answer:

    Error: f is not defined -> Option A
  4. Quick Check:

    Variable f is local to with block, so f.closed access outside causes error [OK]
Hint: f is only defined inside with block; outside it is undefined [OK]
Common Mistakes:
  • Thinking file stays open after with block
  • Expecting file content as output
  • Assuming f is defined outside with
4. Identify the error in this code snippet:
with open('data.txt', 'r') as file:
    content = file.read()
file.close()
medium
A. No error, code is correct
B. Missing colon after with statement
C. Indentation error on content assignment
D. Calling file.close() is unnecessary and causes an error

Solution

  1. Step 1: Understand automatic closing with with

    The with statement automatically closes the file after the block ends.
  2. Step 2: Check explicit close call

    Calling file.close() outside the block is unnecessary, but Python file objects handle multiple calls to close() gracefully without raising an error.
  3. Final Answer:

    No error, code is correct -> Option A
  4. Quick Check:

    Explicit close after with = no error [OK]
Hint: with handles closing; extra close() is harmless [OK]
Common Mistakes:
  • Believing file.close() causes an error after with
  • Looking for syntax errors like missing colon
  • Suspecting indentation problems
5. You want to safely acquire and release a lock using automatic resource cleanup. Which code snippet correctly uses with for this purpose?
import threading
lock = threading.Lock()

# Choose the correct usage
A) with lock.acquire():
       print('Lock acquired')
B) with lock.acquire:
       print('Lock acquired')
C) with lock:
       print('Lock acquired')
D) with lock.lock():
       print('Lock acquired')
hard
A. with lock.acquire():
B. with lock.acquire:
C. with lock.lock():
D. with lock:

Solution

  1. Step 1: Understand lock context management

    Python's threading.Lock supports the context manager protocol, so you can use with lock: to acquire and release automatically.
  2. Step 2: Analyze options

    with lock: uses with lock:, which is correct. Other options misuse the acquire method or call non-existent methods.
  3. Final Answer:

    with lock: -> Option D
  4. Quick Check:

    Use lock directly in with = with lock: [OK]
Hint: Use 'with lock:' to auto acquire and release locks [OK]
Common Mistakes:
  • Calling lock.acquire() inside with
  • Using wrong method names
  • Not knowing Lock supports context manager