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How can you check if none of the elements in list nums = [0, '', None] are present in another list check = [1, 2, 3] using membership operators?

hard📝 Application Q9 of 15
Python - Operators and Expression Evaluation
How can you check if none of the elements in list nums = [0, '', None] are present in another list check = [1, 2, 3] using membership operators?
Acheck not in nums
Bany(x in check for x in nums)
Cnums not in check
Dall(x not in check for x in nums)
Step-by-Step Solution
Solution:
  1. Step 1: Understand the problem

    We want to confirm no element of nums is in check.
  2. Step 2: Use membership in a generator with all()

    all(x not in check for x in nums) returns True if every element of nums is not in check.
  3. Final Answer:

    all(x not in check for x in nums) -> Option D
  4. Quick Check:

    Use all() with 'not in' for none present check [OK]
Quick Trick: Use all() with 'not in' to check absence of all items [OK]
Common Mistakes:
MISTAKES
  • Using 'any' instead of 'all'
  • Wrong operand order
  • Trying 'not in' on whole list

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