[Solved] Find the error in this code:value = 5 if type(value) = int: print("Integer") — Ans: Use '==' instead of '=' in the if condition | Python

Python - Variables and Dynamic Typing

Find the error in this code:

value = 5
if type(value) = int:
    print("Integer")

AUse 'is' instead of '=' in the if condition

BUse '==' instead of '=' in the if condition

CUse '!=' instead of '=' in the if condition

DNo error, code is correct

Step-by-Step Solution

Solution:

Step 1: Identify the operator in the if condition
The code uses single equals = which is assignment, not comparison.
Step 2: Correct the operator for comparison
To compare types, use double equals == in the if condition.
Final Answer:
Use '==' instead of '=' in the if condition -> Option B
Quick Check:
Comparison needs '==' not '=' [OK]

Quick Trick: Use '==' for comparisons, '=' is assignment [OK]

Common Mistakes:

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