Concept Flow - Membership operators (in, not in)
Start
Check if element in collection
Return True
End
The program checks if an element exists inside a collection and returns True if found, otherwise False.
Jump into concepts and practice - no test required
fruits = ['apple', 'banana', 'cherry'] print('banana' in fruits) print('grape' not in fruits)
| Step | Expression | Evaluation | Result | Output |
|---|---|---|---|---|
| 1 | 'banana' in fruits | 'banana' found in ['apple', 'banana', 'cherry'] | True | True |
| 2 | 'grape' not in fruits | 'grape' not found in ['apple', 'banana', 'cherry'] | True | True |
| Variable | Start | After Step 1 | After Step 2 | Final |
|---|---|---|---|---|
| fruits | ['apple', 'banana', 'cherry'] | ['apple', 'banana', 'cherry'] | ['apple', 'banana', 'cherry'] | ['apple', 'banana', 'cherry'] |
Membership operators check if an element is inside a collection. Use 'in' to test presence (returns True if found). Use 'not in' to test absence (returns True if not found). Commonly used with lists, strings, sets. Example: 'x in list' or 'x not in list'.
in operator do in Python?inin operator is used to check if a value is present inside a collection like a list, string, or tuple.in means membership check [OK]in means 'is inside' [OK]in with adding or removing itemsin changes the collectionin with comparison operators'apple' is NOT in the list fruits?not invalue not in collection.in. if not 'apple' fruits: misses in. if 'apple' !in fruits: uses invalid operator !in.not in as two words [OK]not in as two words, no symbols [OK]!in instead of not inin after notnot 'value' in which is valid but less clearletters = ['a', 'b', 'c']
print('d' in letters)
print('a' not in letters)'d' in letters is False.'a' not in letters is False, so print('a' not in letters) prints False.False
False which matches False\nFalse.'d' in letters = False, 'a' not in letters = False [OK]in and not in resultsitems = ['pen', 'pencil', 'eraser']
if 'pen' not items:
print('Pen is missing')value not in collection. The code misses in after not.in.in after not -> Option Cnot in together [OK]not in together [OK]not items instead of not in itemsin keywordnot alone checks membershipwords = ['cat', 'dog', 'bird']. You want to print all words that are NOT in the string text = 'I have a dog and a cat'. Which code correctly does this?text.if w not in text, which correctly checks absence. for w in words:
if w in text:
print(w) prints words that ARE in text, opposite of goal. for w in words:
if not w text:
print(w) has syntax error, missing in after w. for w in words:
if w not text:
print(w) has syntax error missing in.not in for absence check [OK]if w not in text to find missing words [OK]in keyword in various positionsin keyword