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Pythonprogramming~10 mins

Membership operators (in, not in) in Python - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to check if 'apple' is in the list.

Python
fruits = ['apple', 'banana', 'cherry']
if 'apple' [1] fruits:
    print('Found apple!')
Drag options to blanks, or click blank then click option'
Anot in
Bcontains
Cin
Dhas
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'not in' instead of 'in'.
Using 'contains' which is not a Python operator.
2fill in blank
medium

Complete the code to check if 'dog' is NOT in the list.

Python
animals = ['cat', 'bird', 'fish']
if 'dog' [1] animals:
    print('Dog is not here!')
Drag options to blanks, or click blank then click option'
Acontains
Bnot in
Cin
Dhas
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'in' instead of 'not in'.
Using 'contains' which is not a Python operator.
3fill in blank
hard

Fix the error in the code to check membership correctly.

Python
colors = ['red', 'green', 'blue']
if 'yellow' [1] colors:
    print('Yellow is in the list')
else:
    print('Yellow is not in the list')
Drag options to blanks, or click blank then click option'
Ain
Bnot in
Cinside
Dhas
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'not in' when the logic requires 'in'.
Using invalid operators like 'inside' or 'has'.
4fill in blank
hard

Fill both blanks to create a dictionary of words and their lengths only if length is greater than 3.

Python
words = ['sun', 'moon', 'star', 'sky']
lengths = {word: [1] for word in words if len(word) [2] 3}
Drag options to blanks, or click blank then click option'
Alen(word)
B>
C<
Dword
Attempts:
3 left
💡 Hint
Common Mistakes
Using '<' instead of '>'.
Using 'word' instead of 'len(word)'.
5fill in blank
hard

Fill all three blanks to create a dictionary with uppercase keys and values only if value is not in the list.

Python
values = ['a', 'b', 'c']
result = { [1]: [2] for [3] in values if [2] not in ['b', 'c']}
Drag options to blanks, or click blank then click option'
Av.upper()
Bv
Dk
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'k' as loop variable when it is not defined.
Mixing keys and values incorrectly.

Practice

(1/5)
1. What does the in operator do in Python?
easy
A. Creates a new collection
B. Adds a value to a collection
C. Removes a value from a collection
D. Checks if a value exists inside a collection

Solution

  1. Step 1: Understand the purpose of in

    The in operator is used to check if a value is present inside a collection like a list, string, or tuple.
  2. Step 2: Compare with other options

    Options A, B, and C describe actions unrelated to membership checking.
  3. Final Answer:

    Checks if a value exists inside a collection -> Option D
  4. Quick Check:

    in means membership check [OK]
Hint: Remember: in means 'is inside' [OK]
Common Mistakes:
  • Confusing in with adding or removing items
  • Thinking in changes the collection
  • Mixing in with comparison operators
2. Which of the following is the correct syntax to check if the string 'apple' is NOT in the list fruits?
easy
A. if 'apple' not in fruits:
B. if 'apple' not fruits:
C. if not 'apple' fruits:
D. if 'apple' !in fruits:

Solution

  1. Step 1: Recall correct syntax for not in

    The correct syntax to check absence is value not in collection.
  2. Step 2: Evaluate each option

    if 'apple' not in fruits: matches correct syntax. if 'apple' not fruits: misses in. if not 'apple' fruits: misses in. if 'apple' !in fruits: uses invalid operator !in.
  3. Final Answer:

    if 'apple' not in fruits: -> Option A
  4. Quick Check:

    Use not in as two words [OK]
Hint: Use not in as two words, no symbols [OK]
Common Mistakes:
  • Writing !in instead of not in
  • Omitting in after not
  • Using not 'value' in which is valid but less clear
3. What is the output of this code?
letters = ['a', 'b', 'c']
print('d' in letters)
print('a' not in letters)
medium
A. True\nTrue
B. False\nTrue
C. False\nFalse
D. True\nFalse

Solution

  1. Step 1: Check if 'd' is in the list

    'd' is not in ['a', 'b', 'c'], so 'd' in letters is False.
  2. Step 2: Check if 'a' is not in the list

    'a' is in the list, so 'a' not in letters is False, so print('a' not in letters) prints False.
  3. Final Answer:

    False False is incorrect because the second print outputs False, but the first print outputs False, so the correct output is False False which matches False\nFalse.
  4. Quick Check:

    'd' in letters = False, 'a' not in letters = False [OK]
Hint: Check each membership separately [OK]
Common Mistakes:
  • Assuming 'd' is in the list
  • Mixing up in and not in results
  • Confusing True/False outputs
4. Find the error in this code snippet:
items = ['pen', 'pencil', 'eraser']
if 'pen' not items:
    print('Pen is missing')
medium
A. Incorrect print statement syntax
B. Wrong list name
C. Missing in after not
D. No error, code is correct

Solution

  1. Step 1: Check the membership syntax

    The correct syntax for checking absence is value not in collection. The code misses in after not.
  2. Step 2: Verify other parts

    List name and print statement are correct. The only error is missing in.
  3. Final Answer:

    Missing in after not -> Option C
  4. Quick Check:

    Use not in together [OK]
Hint: Always write not in together [OK]
Common Mistakes:
  • Writing not items instead of not in items
  • Forgetting in keyword
  • Assuming not alone checks membership
5. You have a list words = ['cat', 'dog', 'bird']. You want to print all words that are NOT in the string text = 'I have a dog and a cat'. Which code correctly does this?
hard
A. for w in words: if w not in text: print(w)
B. for w in words: if w in text: print(w)
C. for w in words: if not w text: print(w)
D. for w in words: if w not text: print(w)

Solution

  1. Step 1: Understand the goal

    We want to print words from the list that are NOT found inside the string text.
  2. Step 2: Check each option's logic

    for w in words: if w not in text: print(w) uses if w not in text, which correctly checks absence. for w in words: if w in text: print(w) prints words that ARE in text, opposite of goal. for w in words: if not w text: print(w) has syntax error, missing in after w. for w in words: if w not text: print(w) has syntax error missing in.
  3. Final Answer:

    for w in words: if w not in text: print(w) -> Option A
  4. Quick Check:

    Use not in for absence check [OK]
Hint: Use if w not in text to find missing words [OK]
Common Mistakes:
  • Omitting in keyword in various positions
  • Forgetting in keyword
  • Printing words that are present instead of absent