String length and position functions in PostgreSQL - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does the length() function do in PostgreSQL?

The length() function returns the number of characters in a string. For example, length('hello') returns 5.

beginner

How do you find the position of a substring inside a string in PostgreSQL?

Use the position(substring IN string) function. It returns the starting index of the substring or 0 if not found. For example, position('cat' IN 'concatenate') returns 4.

beginner

What will length('') return?

It returns 0 because the string is empty and has no characters.

beginner

If position('x' IN 'example') returns 2, what does that mean?

It means the letter 'x' first appears at the 2nd character position in the string 'example'.

intermediate

What is the difference between length() and char_length() in PostgreSQL?

Both return the number of characters in a string. They are synonyms and behave the same for normal text strings.

What does length('database') return?

A 8

B 7

C 9

D 0

length() counts all characters. 'database' has 8 letters.

What is the result of position('sql' IN 'postgresql')?

A 7

B 5

C 0

D 8

The substring 'sql' starts at the 8th character in 'postgresql'.

If a substring is not found, what does position() return?

A -1

B NULL

C 0

D 1

position() returns 0 when the substring is not found.

Which function can be used to get the number of characters in a string?

A length()

B position()

C substring()

D trim()

length() returns the count of characters in a string.

What does length(' ') return for a string with a single space?

A 0

B 1

C 2

D NULL

A space is a character, so length returns 1.

Explain how to find the position of a substring within a string in PostgreSQL and what the result means.

Think about how you look for a word inside a sentence and find where it starts.

Describe how to get the length of a string and what the length represents.

Imagine counting letters in a word or sentence.

Practice

1. What does the LENGTH function do in PostgreSQL?

easy

A. Splits a string into an array

B. Finds the position of a substring inside a string

C. Converts a string to uppercase

D. Returns the number of characters in a string

Solution

1. Step 1: Understand LENGTH function purpose

   The LENGTH function counts how many characters are in a given string.

2. Step 2: Compare with other options

   POSITION finds substring location, UPPER changes case, SPLIT divides string. Only LENGTH counts characters.

3. Final Answer:

   Returns the number of characters in a string -> Option D

4. Quick Check:

   LENGTH = character count [OK]

Hint: LENGTH counts characters, POSITION finds substring start [OK]

Common Mistakes:

• Confusing LENGTH with POSITION
• Thinking LENGTH changes string case
• Assuming LENGTH splits strings

2. Which of the following is the correct syntax to find the position of substring 'cat' in string 'concatenate' using PostgreSQL?

easy

A. LENGTH('cat' IN 'concatenate')

B. POSITION('concatenate' IN 'cat')

C. POSITION('cat' IN 'concatenate')

D. FIND('cat', 'concatenate')

Solution

1. Step 1: Recall POSITION syntax

   POSITION(substring IN string) finds where substring starts in string.

2. Step 2: Check each option

   POSITION('cat' IN 'concatenate') matches syntax. POSITION('concatenate' IN 'cat') reverses arguments. LENGTH('cat' IN 'concatenate') uses LENGTH wrongly. FIND('cat', 'concatenate') uses non-existent FIND function.

3. Final Answer:

   POSITION('cat' IN 'concatenate') -> Option C

4. Quick Check:

   POSITION(substring IN string) correct syntax [OK]

Hint: Use POSITION('sub' IN 'string') to find substring start [OK]

Common Mistakes:

• Swapping substring and string arguments
• Using LENGTH instead of POSITION
• Using non-PostgreSQL functions like FIND

3. What is the result of this query?

SELECT POSITION('day' IN 'holiday') AS pos, LENGTH('holiday') AS len;

medium

A. pos = 4, len = 7

B. pos = 5, len = 7

C. pos = 0, len = 7

D. pos = 4, len = 6

Solution

1. Step 1: Find POSITION of 'day' in 'holiday'

   'holiday' positions: 1:'h', 2:'o', 3:'l', 4:'i', 5:'d', 6:'a', 7:'y'. 'day' matches positions 5('d')-6('a')-7('y'), so starts at 5 (1-based).

2. Step 2: Calculate LENGTH of 'holiday'

   'holiday' has 7 characters.

3. Final Answer:

   pos = 5, len = 7 -> Option B

4. Quick Check:

   POSITION('day' IN 'holiday') = 5, LENGTH('holiday') = 7 [OK]

Hint: Count characters carefully; POSITION is 1-based [OK]

Common Mistakes:

• Counting POSITION starting at 0
• Miscounting substring start
• Confusing LENGTH with POSITION

4. Identify the error in this query:

SELECT POSITION('test', 'contest') AS pos;

medium

A. Uses comma instead of IN keyword in POSITION function

B. Missing AS keyword for alias

C. POSITION does not accept string literals

D. Syntax is correct, no error

Solution

1. Step 1: Check POSITION function syntax

   POSITION requires syntax POSITION(substring IN string), not POSITION(substring, string).

2. Step 2: Identify error in query

   The query uses comma instead of IN keyword, causing syntax error.

3. Final Answer:

   Uses comma instead of IN keyword in POSITION function -> Option A

4. Quick Check:

   POSITION(substring IN string) correct syntax [OK]

Hint: Use IN keyword, not comma, in POSITION function [OK]

Common Mistakes:

• Using comma instead of IN in POSITION
• Assuming alias AS is mandatory (it's optional)
• Thinking POSITION can't use string literals

5. You want to find the position of the first space character in the string 'Find the position'. Which query will correctly return this position?

hard

A. SELECT POSITION(' ' IN 'Find the position');

B. SELECT LENGTH(' ' IN 'Find the position');

C. SELECT POSITION('space' IN 'Find the position');

D. SELECT POSITION(' ' FROM 'Find the position');

Solution

1. Step 1: Identify correct function usage for substring position

   POSITION(substring IN string) finds where substring starts. We want the space character ' '.

2. Step 2: Evaluate each option

   SELECT POSITION(' ' IN 'Find the position'); uses correct syntax and substring. SELECT LENGTH(' ' IN 'Find the position'); uses LENGTH wrongly. SELECT POSITION('space' IN 'Find the position'); searches for word 'space' which is not present. SELECT POSITION(' ' FROM 'Find the position'); uses FROM instead of IN, which is invalid syntax.

3. Final Answer:

   SELECT POSITION(' ' IN 'Find the position'); -> Option A

4. Quick Check:

   POSITION(' ' IN string) finds first space [OK]

Hint: Use POSITION(' ' IN string) to find first space [OK]

Common Mistakes:

• Using LENGTH instead of POSITION
• Searching for word 'space' instead of character
• Using FROM instead of IN in POSITION