String length and position functions in PostgreSQL - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ query_result

intermediate

Find the length of a string

What is the output of the following SQL query in PostgreSQL?

PostgreSQL

SELECT LENGTH('Hello, World!') AS length;

A Error

B 12

C 13

D 14

💡 Hint

The LENGTH function counts all characters including punctuation and spaces.

The string 'Hello, World!' has 13 characters including the comma and space.

❓ query_result

intermediate

Find position of a substring

What is the result of this query?

PostgreSQL

SELECT POSITION('cat' IN 'concatenate') AS pos;

A 4

B 3

C 1

D 0

💡 Hint

POSITION returns the starting index of the substring if found, else 0.

The substring 'cat' starts at the 4th character in 'concatenate'.

📝 Syntax

advanced

Identify the syntax error in string length query

Which option will cause a syntax error when trying to get the length of a string in PostgreSQL?

A SELECT LENGTH 'test string';

B SELECT LENGTH('test string');

C SELECT LENGTH('test string') AS len;

D SELECT LENGTH('test string')

💡 Hint

Check if the function call syntax is correct with parentheses.

Option A misses parentheses around the string argument, causing syntax error.

❓ query_result

advanced

Find position of substring not present

What does this query return?

PostgreSQL

SELECT POSITION('dog' IN 'concatenate') AS pos;

A 1

B 0

C NULL

D Error

💡 Hint

POSITION returns 0 if substring is not found.

Since 'dog' is not in 'concatenate', POSITION returns 0.

❓ optimization

expert

Optimize query to find length of trimmed string

Which query efficiently returns the length of a string after removing spaces from both ends?

A SELECT LENGTH(REPLACE(' example ', ' ', '')) AS len;

B SELECT LENGTH(' example ') - 2 AS len;

C SELECT LENGTH(LTRIM(RTRIM(' example '))) AS len;

D SELECT LENGTH(TRIM(' example ')) AS len;

💡 Hint

TRIM removes spaces from both ends in one step.

Option D uses TRIM which removes spaces from both ends efficiently and then measures length.

Practice

1. What does the LENGTH function do in PostgreSQL?

easy

A. Splits a string into an array

B. Finds the position of a substring inside a string

C. Converts a string to uppercase

D. Returns the number of characters in a string

Solution

1. Step 1: Understand LENGTH function purpose

   The LENGTH function counts how many characters are in a given string.

2. Step 2: Compare with other options

   POSITION finds substring location, UPPER changes case, SPLIT divides string. Only LENGTH counts characters.

3. Final Answer:

   Returns the number of characters in a string -> Option D

4. Quick Check:

   LENGTH = character count [OK]

Hint: LENGTH counts characters, POSITION finds substring start [OK]

Common Mistakes:

• Confusing LENGTH with POSITION
• Thinking LENGTH changes string case
• Assuming LENGTH splits strings

2. Which of the following is the correct syntax to find the position of substring 'cat' in string 'concatenate' using PostgreSQL?

easy

A. LENGTH('cat' IN 'concatenate')

B. POSITION('concatenate' IN 'cat')

C. POSITION('cat' IN 'concatenate')

D. FIND('cat', 'concatenate')

Solution

1. Step 1: Recall POSITION syntax

   POSITION(substring IN string) finds where substring starts in string.

2. Step 2: Check each option

   POSITION('cat' IN 'concatenate') matches syntax. POSITION('concatenate' IN 'cat') reverses arguments. LENGTH('cat' IN 'concatenate') uses LENGTH wrongly. FIND('cat', 'concatenate') uses non-existent FIND function.

3. Final Answer:

   POSITION('cat' IN 'concatenate') -> Option C

4. Quick Check:

   POSITION(substring IN string) correct syntax [OK]

Hint: Use POSITION('sub' IN 'string') to find substring start [OK]

Common Mistakes:

• Swapping substring and string arguments
• Using LENGTH instead of POSITION
• Using non-PostgreSQL functions like FIND

3. What is the result of this query?

SELECT POSITION('day' IN 'holiday') AS pos, LENGTH('holiday') AS len;

medium

A. pos = 4, len = 7

B. pos = 5, len = 7

C. pos = 0, len = 7

D. pos = 4, len = 6

Solution

1. Step 1: Find POSITION of 'day' in 'holiday'

   'holiday' positions: 1:'h', 2:'o', 3:'l', 4:'i', 5:'d', 6:'a', 7:'y'. 'day' matches positions 5('d')-6('a')-7('y'), so starts at 5 (1-based).

2. Step 2: Calculate LENGTH of 'holiday'

   'holiday' has 7 characters.

3. Final Answer:

   pos = 5, len = 7 -> Option B

4. Quick Check:

   POSITION('day' IN 'holiday') = 5, LENGTH('holiday') = 7 [OK]

Hint: Count characters carefully; POSITION is 1-based [OK]

Common Mistakes:

• Counting POSITION starting at 0
• Miscounting substring start
• Confusing LENGTH with POSITION

4. Identify the error in this query:

SELECT POSITION('test', 'contest') AS pos;

medium

A. Uses comma instead of IN keyword in POSITION function

B. Missing AS keyword for alias

C. POSITION does not accept string literals

D. Syntax is correct, no error

Solution

1. Step 1: Check POSITION function syntax

   POSITION requires syntax POSITION(substring IN string), not POSITION(substring, string).

2. Step 2: Identify error in query

   The query uses comma instead of IN keyword, causing syntax error.

3. Final Answer:

   Uses comma instead of IN keyword in POSITION function -> Option A

4. Quick Check:

   POSITION(substring IN string) correct syntax [OK]

Hint: Use IN keyword, not comma, in POSITION function [OK]

Common Mistakes:

• Using comma instead of IN in POSITION
• Assuming alias AS is mandatory (it's optional)
• Thinking POSITION can't use string literals

5. You want to find the position of the first space character in the string 'Find the position'. Which query will correctly return this position?

hard

A. SELECT POSITION(' ' IN 'Find the position');

B. SELECT LENGTH(' ' IN 'Find the position');

C. SELECT POSITION('space' IN 'Find the position');

D. SELECT POSITION(' ' FROM 'Find the position');

Solution

1. Step 1: Identify correct function usage for substring position

   POSITION(substring IN string) finds where substring starts. We want the space character ' '.

2. Step 2: Evaluate each option

   SELECT POSITION(' ' IN 'Find the position'); uses correct syntax and substring. SELECT LENGTH(' ' IN 'Find the position'); uses LENGTH wrongly. SELECT POSITION('space' IN 'Find the position'); searches for word 'space' which is not present. SELECT POSITION(' ' FROM 'Find the position'); uses FROM instead of IN, which is invalid syntax.

3. Final Answer:

   SELECT POSITION(' ' IN 'Find the position'); -> Option A

4. Quick Check:

   POSITION(' ' IN string) finds first space [OK]

Hint: Use POSITION(' ' IN string) to find first space [OK]

Common Mistakes:

• Using LENGTH instead of POSITION
• Searching for word 'space' instead of character
• Using FROM instead of IN in POSITION