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PostgreSQLquery~5 mins

Date arithmetic with intervals in PostgreSQL

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Introduction
Date arithmetic helps you add or subtract time from dates to find new dates easily.
Calculate a due date by adding days to a start date.
Find the date 3 months before a given date.
Determine how many days are left until an event.
Adjust timestamps by adding hours or minutes.
Create reports that compare dates with intervals.
Syntax
PostgreSQL
date + interval 'amount unit'
date - interval 'amount unit'
The interval is written as a string with a number and a time unit like '5 days' or '2 months'.
You can add or subtract intervals from dates or timestamps.
Examples
Adds 10 days to June 1, 2024, resulting in June 11, 2024.
PostgreSQL
SELECT DATE '2024-06-01' + INTERVAL '10 days';
Subtracts 1 month from June 1, 2024, resulting in May 1, 2024.
PostgreSQL
SELECT DATE '2024-06-01' - INTERVAL '1 month';
Adds 3 hours to the timestamp, resulting in 3 PM on June 1, 2024.
PostgreSQL
SELECT TIMESTAMP '2024-06-01 12:00' + INTERVAL '3 hours';
Finds the date 7 days from today.
PostgreSQL
SELECT CURRENT_DATE + INTERVAL '7 days';
Sample Program
This query shows adding 5 days, subtracting 2 months, and adding 4 hours to given dates and timestamps.
PostgreSQL
SELECT
  DATE '2024-06-15' + INTERVAL '5 days' AS plus_five_days,
  DATE '2024-06-15' - INTERVAL '2 months' AS minus_two_months,
  TIMESTAMP '2024-06-15 08:00' + INTERVAL '4 hours' AS plus_four_hours;
OutputSuccess
Important Notes
You can combine multiple intervals by adding them together, like INTERVAL '1 day' + INTERVAL '2 hours'.
Be careful with months and years because they vary in length; PostgreSQL handles this correctly.
Intervals can be negative to subtract time.
Summary
Date arithmetic lets you add or subtract time easily using intervals.
Intervals are written as strings with a number and a unit like 'days', 'months', or 'hours'.
You can use this to calculate new dates or times based on existing ones.

Practice

(1/5)
1. What does the following PostgreSQL expression do?
SELECT CURRENT_DATE + INTERVAL '5 days';
easy
A. Returns the current date without change
B. Subtracts 5 days from the current date
C. Causes a syntax error
D. Adds 5 days to the current date

Solution

  1. Step 1: Understand the CURRENT_DATE keyword

    CURRENT_DATE returns today's date without time.
  2. Step 2: Add interval of 5 days

    Adding INTERVAL '5 days' increases the date by 5 days.
  3. Final Answer:

    Adds 5 days to the current date -> Option D
  4. Quick Check:

    Adding interval '5 days' = date + 5 days [OK]
Hint: Adding INTERVAL 'X days' shifts date forward by X days [OK]
Common Mistakes:
  • Confusing addition with subtraction
  • Thinking CURRENT_DATE includes time
  • Using wrong interval syntax
2. Which of the following is the correct syntax to subtract 3 months from a date column named order_date?
easy
A. order_date - '3 months'
B. order_date - INTERVAL '3 months'
C. order_date - INTERVAL 3 months
D. order_date - INTERVAL '3 month'

Solution

  1. Step 1: Identify correct interval syntax

    INTERVAL must be followed by a quoted string with number and unit, e.g., '3 months'.
  2. Step 2: Check subtraction from date column

    Subtracting INTERVAL '3 months' from order_date is valid syntax.
  3. Final Answer:

    order_date - INTERVAL '3 months' -> Option B
  4. Quick Check:

    Subtract INTERVAL '3 months' with quotes [OK]
Hint: Always quote interval value like '3 months' [OK]
Common Mistakes:
  • Omitting quotes around interval string
  • Using singular 'month' instead of plural 'months'
  • Trying to subtract string without INTERVAL keyword
3. What is the result of this query if today is 2024-06-15?
SELECT (DATE '2024-06-15' + INTERVAL '1 month' - INTERVAL '10 days')::date AS new_date;
medium
A. 2024-07-25
B. 2024-05-25
C. 2024-07-05
D. 2024-06-05

Solution

  1. Step 1: Add 1 month to 2024-06-15

    Adding 1 month results in 2024-07-15.
  2. Step 2: Subtract 10 days from 2024-07-15

    Subtracting 10 days gives 2024-07-05.
  3. Final Answer:

    2024-07-05 -> Option C
  4. Quick Check:

    2024-06-15 + 1 month - 10 days = 2024-07-05 [OK]
Hint: Add then subtract intervals stepwise for correct date [OK]
Common Mistakes:
  • Subtracting before adding
  • Confusing day and month units
  • Not casting to date and including time
4. Identify the error in this query:
SELECT CURRENT_DATE + INTERVAL 5 days;
medium
A. Missing quotes around interval value
B. CURRENT_DATE cannot be used with intervals
C. INTERVAL keyword is misspelled
D. Adding intervals to dates is not allowed

Solution

  1. Step 1: Check INTERVAL syntax

    INTERVAL requires the value to be a quoted string, e.g., '5 days'.
  2. Step 2: Identify missing quotes error

    The query lacks quotes around 5 days, causing syntax error.
  3. Final Answer:

    Missing quotes around interval value -> Option A
  4. Quick Check:

    INTERVAL '5 days' needs quotes [OK]
Hint: Always put interval value in single quotes [OK]
Common Mistakes:
  • Writing INTERVAL 5 days without quotes
  • Assuming CURRENT_DATE can't be used with intervals
  • Confusing INTERVAL keyword spelling
5. You want to find all orders from a table orders where the order_date is within the last 3 months from today. Which query correctly uses date arithmetic with intervals?
hard
A. SELECT * FROM orders WHERE order_date >= CURRENT_DATE - INTERVAL '3 months';
B. SELECT * FROM orders WHERE order_date <= CURRENT_DATE + INTERVAL '3 months';
C. SELECT * FROM orders WHERE order_date > CURRENT_DATE + INTERVAL '3 months';
D. SELECT * FROM orders WHERE order_date < CURRENT_DATE - INTERVAL '3 months';

Solution

  1. Step 1: Understand the requirement

    We want orders from the last 3 months, so order_date should be after (or equal to) 3 months ago.
  2. Step 2: Use CURRENT_DATE minus 3 months

    Subtracting INTERVAL '3 months' from CURRENT_DATE gives the date 3 months ago.
  3. Step 3: Write condition for order_date

    order_date >= CURRENT_DATE - INTERVAL '3 months' selects orders within last 3 months.
  4. Final Answer:

    SELECT * FROM orders WHERE order_date >= CURRENT_DATE - INTERVAL '3 months'; -> Option A
  5. Quick Check:

    Filter dates after CURRENT_DATE - 3 months [OK]
Hint: Use >= CURRENT_DATE - INTERVAL 'X months' for recent dates [OK]
Common Mistakes:
  • Using + INTERVAL instead of - INTERVAL
  • Using < instead of >= for filtering recent dates
  • Confusing direction of date comparison
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