[Solved] What will this PHP code output?<?php session_start(); if(!isset($_SESSION['visits'])) { $_SESSION['visits'] = 1; } else { $_SESSION['visits'] += 1; } echo $_SESSION['visits']; ?> | PHP

PHP - Sessions and Cookies

What will this PHP code output?

<?php
session_start();
if(!isset($_SESSION['visits'])) {
  $_SESSION['visits'] = 1;
} else {
  $_SESSION['visits'] += 1;
}
echo $_SESSION['visits'];
?>

A1 on first visit, increments on reload

BAlways 0

CSyntax error

DUndefined variable error

Step-by-Step Solution

Solution:

Step 1: Check if session variable 'visits' exists
On first run, it does not exist, so it is set to 1.
Step 2: On reload, 'visits' increments by 1
Each reload increases the count by 1.
Final Answer:
1 on first visit, increments on reload -> Option A
Quick Check:
Session counter increments correctly [OK]

Quick Trick: Use isset() to check session variable existence [OK]

Common Mistakes:

Expecting zero output
Thinking code errors
Ignoring session persistence

Master "Sessions and Cookies" in PHP

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Time

More PHP Quizzes

What will this PHP code output?

Step 1: Check if session variable 'visits' exists

Step 2: On reload, 'visits' increments by 1

Final Answer:

Quick Check:

Want More Practice?