[Solved] What will be the output of this PHP code?try { throw new Exception("Failed"); echo "This will not print"; } catch (Exception $e) { echo "Error: " . $e->getMessage(); } | PHP

PHP - Error and Exception Handling

What will be the output of this PHP code?

try {
    throw new Exception("Failed");
    echo "This will not print";
} catch (Exception $e) {
    echo "Error: " . $e->getMessage();
}

AError: This will not print

BThis will not print

CNo output

DError: Failed

Step-by-Step Solution

Solution:

Step 1: Analyze the try block
The throw statement raises an exception with message "Failed" and stops execution inside the try block immediately.
Step 2: Check code after throw
The echo statement after throw is never executed.
Step 3: Catch block execution
The catch block catches the exception and prints "Error: Failed".
Final Answer:
Error: Failed -> Option D
Quick Check:
Code after throw is skipped [OK]

Quick Trick: Code after throw inside try is skipped [OK]

Common Mistakes:

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