[Solved] What will happen when the following PHP code runs?class Vehicle {} class Bike {} function ride(Vehicle $v) { echo "Riding vehicle"; } $bike = new Bike(); ride($bike); | PHP

PHP - Inheritance and Polymorphism

What will happen when the following PHP code runs?

class Vehicle {}
class Bike {}

function ride(Vehicle $v) {
    echo "Riding vehicle";
}

$bike = new Bike();
ride($bike);

ARiding vehicle

BFatal error: Argument must be instance of Vehicle

CNo output

DWarning but continues execution

Step-by-Step Solution

Solution:

Step 1: Analyze type hint and argument
The function ride requires a Vehicle object, but $bike is an instance of Bike, unrelated to Vehicle.
Step 2: Understand PHP behavior on type mismatch
Passing an object not matching the type hint causes a fatal error.
Final Answer:
Fatal error: Argument must be instance of Vehicle -> Option B
Quick Check:
Type hint mismatch causes fatal error [OK]

Quick Trick: Type hint mismatch causes fatal error, no warnings [OK]

Common Mistakes:

Master "Inheritance and Polymorphism" in PHP

9 interactive learning modes - each teaches the same concept differently

More PHP Quizzes

What will happen when the following PHP code runs?