[Solved] What is the output of the following code?import numpy as np A = np.array([[1], [2], [3]]) B = np.array([10, 20, 30]) C = A + B print(C) | NumPy

NumPy - Broadcasting

What is the output of the following code?

import numpy as np
A = np.array([[1], [2], [3]])
B = np.array([10, 20, 30])
C = A + B
print(C)

A[[11 21 31] [12 22 32] [13 23 33]]

B[[11 12 13] [21 22 23] [31 32 33]]

C[[10 20 30] [10 20 30] [10 20 30]]

DError due to shape mismatch

Step-by-Step Solution

Solution:

Step 1: Analyze shapes of A and B
A shape is (3,1), B shape is (3,). B broadcasts to (1,3), A broadcasts to (3,3).
Step 2: Perform broadcasting addition
Each element of A's column is added to each element of B's row, resulting in a (3,3) array.
Final Answer:
[[11 12 13] [21 22 23] [31 32 33]] -> Option B
Quick Check:
Broadcast shapes (3,1) + (3,) = (3,3) [OK]

Quick Trick: Broadcast smaller dims to match larger dims for addition [OK]

Common Mistakes:

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