Given two arrays a = np.array([1, 2, 3]) and b = np.array([4, 5, 6]), how can you use np.where() to create an array that takes elements from a if they are even, otherwise from b?

hard📝 Application Q9 of 15

NumPy - Indexing and Slicing

Given two arrays a = np.array([1, 2, 3]) and b = np.array([4, 5, 6]), how can you use np.where() to create an array that takes elements from a if they are even, otherwise from b?

Anp.where(a % 2 == 0, a, b)

Bnp.where(b % 2 == 0, a, b)

Cnp.where(a % 2 != 0, a, b)

Dnp.where(a == b, a, b)

Step-by-Step Solution

Solution:

Step 1: Identify condition for even elements in a
Condition is a % 2 == 0 to check even numbers in a.
Step 2: Use np.where to select from a or b
Use np.where(a % 2 == 0, a, b) to pick from a if even, else from b.
Final Answer:
np.where(a % 2 == 0, a, b) -> Option A
Quick Check:
np.where(condition, a, b) picks based on condition [OK]

Quick Trick: Condition on a, pick from a or b accordingly [OK]

Common Mistakes:

Checking condition on wrong array
Using != instead of == for even check
Confusing which array to pick from

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More NumPy Quizzes

Given two arrays a = np.array([1, 2, 3]) and b = np.array([4, 5, 6]), how can you use np.where() to create an array that takes elements from a if they are even, otherwise from b?

Step 1: Identify condition for even elements in a

Step 2: Use np.where to select from a or b

Final Answer:

Quick Check:

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