Common broadcasting patterns in NumPy - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to add a 1D array to each row of a 2D array using broadcasting.

NumPy

import numpy as np
arr2d = np.array([[1, 2, 3], [4, 5, 6]])
arr1d = np.array([10, 20, 30])
result = arr2d [1] arr1d
print(result)

Drag options to blanks, or click blank then click option'

A*

B-

C/

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using subtraction or multiplication instead of addition.

Trying to add arrays of incompatible shapes without broadcasting.

Using the plus operator (+) adds the 1D array to each row of the 2D array by broadcasting.

2fill in blank

medium

Complete the code to multiply a 2D array by a column vector using broadcasting.

NumPy

import numpy as np
arr2d = np.array([[1, 2, 3], [4, 5, 6]])
col_vec = np.array([[10], [20]])
result = arr2d [1] col_vec
print(result)

Drag options to blanks, or click blank then click option'

A-

B+

C*

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using addition instead of multiplication.

Not reshaping the column vector properly.

The multiplication operator (*) broadcasts the column vector across each row of the 2D array.

3fill in blank

hard

Fix the error in the code to subtract a 1D array from each column of a 2D array using broadcasting.

NumPy

import numpy as np
arr2d = np.array([[5, 10], [15, 20], [25, 30]])
arr1d = np.array([1, 2, 3])
result = arr2d - arr1d[1]
print(result)

Drag options to blanks, or click blank then click option'

A.reshape(3,)

B.reshape(1, 3)

C.reshape(3, 1)

D.reshape(1, 1)

Attempts:

3 left

💡 Hint

Common Mistakes

Reshaping to (3,1) which aligns as a column vector, not row.

Not reshaping at all causing shape mismatch error.

Reshaping arr1d to (1,3) aligns it as a row vector to subtract from each column of arr2d by broadcasting.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if the length is greater than 3.

NumPy

words = ['apple', 'bat', 'carrot', 'dog']
lengths = {word: [1] for word in words if [2]

Drag options to blanks, or click blank then click option'

Alen(word)

Blen(word) > 3

Clen(word) < 3

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as the value instead of its length.

Using the wrong condition for filtering.

The dictionary comprehension maps each word to its length (len(word)) only if the length is greater than 3 (len(word) > 3).

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase words to their lengths only if the length is greater than 2.

NumPy

words = ['hi', 'hello', 'yes', 'no']
result = { [1]: [2] for word in words if [3] }

Drag options to blanks, or click blank then click option'

Aword.upper()

Blen(word)

Clen(word) > 2

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.lower() instead of word.upper().

Not filtering words by length properly.

The comprehension maps the uppercase version of each word (word.upper()) to its length (len(word)) only if the length is greater than 2 (len(word) > 2).

Practice

1. What does broadcasting in NumPy allow you to do?

easy

A. Perform operations on arrays of different shapes without explicit loops

B. Only add arrays of the exact same shape

C. Convert arrays into lists automatically

D. Sort arrays in ascending order

Solution

1. Step 1: Understand broadcasting concept

   Broadcasting lets NumPy perform element-wise operations on arrays with different shapes by automatically expanding the smaller array.

2. Step 2: Compare options

   Only Perform operations on arrays of different shapes without explicit loops correctly describes this feature. Options A, B, and C describe unrelated behaviors.

3. Final Answer:

   Perform operations on arrays of different shapes without explicit loops -> Option A

4. Quick Check:

   Broadcasting = operations on different shapes [OK]

Hint: Broadcasting means math on different shaped arrays without loops [OK]

Common Mistakes:

• Thinking broadcasting requires arrays to have the same shape
• Confusing broadcasting with sorting or type conversion
• Assuming broadcasting changes array data types

2. Which of the following is the correct way to add a 1D array to each row of a 2D array using broadcasting?

easy

A. result = matrix + vector.T where matrix.shape = (3,4) and vector.shape = (4,)

B. result = matrix + vector where matrix.shape = (3,4) and vector.shape = (3,)

C. result = matrix + vector where matrix.shape = (3,4) and vector.shape = (4,)

D. result = matrix + vector.reshape(3,1) where matrix.shape = (3,4) and vector.shape = (4,)

Solution

1. Step 1: Check shapes for broadcasting

   Adding a 1D array of shape (4,) to each row of a (3,4) matrix works because the vector matches the number of columns.

2. Step 2: Evaluate options

   result = matrix + vector where matrix.shape = (3,4) and vector.shape = (4,) matches this pattern. result = matrix + vector where matrix.shape = (3,4) and vector.shape = (3,) tries to add a (3,) vector to (3,4) matrix which fails. result = matrix + vector.T where matrix.shape = (3,4) and vector.shape = (4,) uses transpose incorrectly. result = matrix + vector.reshape(3,1) where matrix.shape = (3,4) and vector.shape = (4,) reshapes vector wrongly.

3. Final Answer:

   result = matrix + vector where matrix.shape = (3,4) and vector.shape = (4,) -> Option C

4. Quick Check:

   Vector shape matches columns for row-wise addition [OK]

Hint: Add vector matching columns to matrix rows for broadcasting [OK]

Common Mistakes:

• Using vector shape matching rows instead of columns
• Trying to transpose 1D vector which has no effect
• Reshaping vector incorrectly before addition

3. What is the output of the following code?

import numpy as np
A = np.array([[1, 2, 3], [4, 5, 6]])
B = np.array([10, 20, 30])
C = A + B
print(C)

medium

A. [[11 22 33]
[14 25 36]]

B. [[11 22 33]
[14 25 36]
[10 20 30]]

C. [[10 20 30]
[10 20 30]]

D. ValueError due to shape mismatch

Solution

1. Step 1: Understand shapes of A and B

   A has shape (2,3), B has shape (3,). B will broadcast across rows of A.

2. Step 2: Perform element-wise addition

   Each row of A adds B: [1+10, 2+20, 3+30] = [11, 22, 33], [4+10, 5+20, 6+30] = [14, 25, 36].

3. Final Answer:

   [[11 22 33] [14 25 36]] -> Option A

4. Quick Check:

   Broadcast adds vector to each matrix row [OK]

Hint: Add vector to each matrix row when vector shape matches columns [OK]

Common Mistakes:

• Expecting an extra row in output
• Confusing broadcasting with stacking arrays
• Thinking shape mismatch causes error here

4. Identify the error in this code snippet:

import numpy as np
X = np.array([[1, 2], [3, 4], [5, 6]])
y = np.array([10, 20, 30])
result = X + y

medium

A. y should be reshaped to (3,1) before addition

B. No error, code runs fine

C. X and y must have the same number of columns

D. Shapes (3,2) and (3,) cannot broadcast together

Solution

1. Step 1: Check shapes of X and y

   X shape is (3,2), y shape is (3,). Broadcasting rules require trailing dimensions to match or be 1.

2. Step 2: Analyze broadcasting compatibility

   Here, last dims are 2 (X) and 1 (y) after broadcasting rules, so y broadcasts along columns. The addition works without error.

3. Final Answer:

   No error, code runs fine -> Option B

4. Quick Check:

   Broadcasting allows (3,2) + (3,) by treating (3,) as (3,1) [OK]

Hint: Trailing dimensions must match or be 1 for broadcasting [OK]

Common Mistakes:

• Assuming broadcasting works if first dims match
• Not checking trailing dimension compatibility
• Thinking reshaping y to (3,1) fixes addition here

5. Given a 2D array M of shape (4,3) and a 1D array v of shape (4,), how can you add v to each column of M using broadcasting?

hard

A. M + v.T

B. M + v

C. M + v.reshape(1,4)

D. M + v.reshape(4,1)

Solution

1. Step 1: Understand shapes and desired operation

   M is (4,3), v is (4,). To add v to each column, v must be reshaped to (4,1) to broadcast along columns.

2. Step 2: Check each option

   M + v.reshape(4,1) reshapes v to (4,1), allowing broadcasting with M (4,3). M + v tries to add (4,) to (4,3) which broadcasts incorrectly. M + v.reshape(1,4) reshapes v to (1,4), incompatible. M + v.T uses transpose on 1D array which has no effect.

3. Final Answer:

   M + v.reshape(4,1) -> Option D

4. Quick Check:

   Reshape vector to (rows,1) to add to columns [OK]

Hint: Reshape vector to (rows,1) to add to matrix columns [OK]

Common Mistakes:

• Adding vector without reshaping when shapes differ
• Using reshape(1, rows) instead of (rows,1)
• Assuming transpose changes 1D array shape