[Solved] What will be the output of this code?import numpy as np x = np.array([[2, 4, 6], [8, 10, 12]]) y = np.array([1, 0, -1]) print(x - y) | NumPy

NumPy - Broadcasting

What will be the output of this code?

import numpy as np
x = np.array([[2, 4, 6], [8, 10, 12]])
y = np.array([1, 0, -1])
print(x - y)

A[[3 4 5] [7 10 13]]

B[[1 4 7] [9 10 11]]

C[[1 4 7] [7 10 11]]

D[[1 4 7] [7 10 13]]

Step-by-Step Solution

Solution:

Step 1: Understand shapes
x shape is (2, 3), y shape is (3,). Broadcasting subtracts y from each row of x.
Step 2: Perform element-wise subtraction
Row 1: [2-1, 4-0, 6-(-1)] = [1, 4, 7]
Row 2: [8-1, 10-0, 12-(-1)] = [7, 10, 13]
Step 3: Match output
[[1 4 7] [7 10 13]] matches the computed result exactly.
Final Answer:
[[1 4 7] [7 10 13]] -> Option D
Quick Check:
Subtract 1D array from each row element-wise. [OK]

Quick Trick: Subtract 1D array from each row of 2D array element-wise. [OK]

Common Mistakes:

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