Self JOIN in MySQL - Mini Project: Build & Apply

Understanding Self JOIN in MySQL

📖 Scenario: You work in a company database where employees have managers who are also employees. You want to find out who manages whom by linking employees to their managers.

🎯 Goal: Build a MySQL query using SELF JOIN to list employees alongside their managers' names.

📋 What You'll Learn

Create a table called employees with columns id, name, and manager_id

Insert the exact employee data with their manager IDs

Write a SELECT query using SELF JOIN to get employee names and their managers' names

Use table aliases e for employees and m for managers in the query

💡 Why This Matters

🌍 Real World

Companies often store employee and manager data in the same table. Self joins help find relationships within the same dataset.

💼 Career

Understanding self joins is essential for database roles that involve hierarchical data, reporting structures, or organizational charts.

1

Create the employees table

Write a MySQL statement to create a table called employees with columns: id as INT primary key, name as VARCHAR(50), and manager_id as INT that can be NULL.

MySQL

-- Create the employees table with id, name, and manager_id columns
-- Your code here

Hint

Use CREATE TABLE with the specified columns and types. manager_id can be NULL because some employees may not have managers.

2

Insert employee data

Insert these exact rows into the employees table: (1, 'Alice', NULL), (2, 'Bob', 1), (3, 'Charlie', 1), (4, 'David', 2). Use a single INSERT INTO statement.

MySQL

CREATE TABLE employees (
  id INT PRIMARY KEY,
  name VARCHAR(50),
  manager_id INT NULL
);
-- Insert the employee data below
-- Your code here

Hint

Use a single INSERT INTO statement with multiple rows separated by commas.

3

Write the SELF JOIN query

Write a SELECT query using SELF JOIN on the employees table with aliases e for employees and m for managers. Select e.name as employee and m.name as manager. Join on e.manager_id = m.id.

MySQL

CREATE TABLE employees (
  id INT PRIMARY KEY,
  name VARCHAR(50),
  manager_id INT NULL
);

INSERT INTO employees (id, name, manager_id) VALUES
(1, 'Alice', NULL),
(2, 'Bob', 1),
(3, 'Charlie', 1),
(4, 'David', 2);

-- Write the SELF JOIN query below
-- Your code here

Hint

Use JOIN on the same table with aliases and match e.manager_id to m.id.

4

Complete the query with ordering

Add an ORDER BY clause to the query to sort the results by employee name in ascending order.

MySQL

CREATE TABLE employees (
  id INT PRIMARY KEY,
  name VARCHAR(50),
  manager_id INT NULL
);

INSERT INTO employees (id, name, manager_id) VALUES
(1, 'Alice', NULL),
(2, 'Bob', 1),
(3, 'Charlie', 1),
(4, 'David', 2);

SELECT e.name AS employee, m.name AS manager
FROM employees e
JOIN employees m ON e.manager_id = m.id
-- Add ORDER BY clause below
-- Your code here

Hint

Use ORDER BY e.name ASC to sort employees alphabetically.

Practice

1. What is the main purpose of using a SELF JOIN in SQL?

easy

A. To combine rows from two tables without any condition

B. To join two different tables based on a common column

C. To join a table to itself to compare rows within the same table

D. To delete duplicate rows from a table

Solution

1. Step 1: Understand what a SELF JOIN does

   A SELF JOIN connects a table to itself using aliases to compare rows within the same table.

2. Step 2: Compare with other JOIN types

   Other joins combine different tables or rows but SELF JOIN specifically works on one table to find relationships inside it.

3. Final Answer:

   To join a table to itself to compare rows within the same table -> Option C

4. Quick Check:

   SELF JOIN = join table to itself [OK]

Hint: SELF JOIN means joining table to itself using aliases [OK]

Common Mistakes:

• Confusing SELF JOIN with JOIN between two different tables
• Thinking SELF JOIN deletes duplicates
• Assuming SELF JOIN combines unrelated tables

2. Which of the following is the correct syntax to perform a SELF JOIN on a table named employees with aliases e1 and e2 to find employees and their managers?

easy

A. SELECT * FROM employees e1 JOIN employees e2 ON e1.manager_id = e2.id;

B. SELECT * FROM employees JOIN employees ON employees.manager_id = employees.id;

C. SELECT * FROM employees e1 JOIN employees e2 WHERE e1.id = e2.manager_id;

D. SELECT * FROM employees e1 LEFT JOIN employees e2 ON e1.id = e2.id;

Solution

1. Step 1: Identify correct alias usage

   Using aliases e1 and e2 for the same table is required for SELF JOIN to distinguish rows.

2. Step 2: Check JOIN condition syntax

   The condition e1.manager_id = e2.id correctly links employees to their managers.

3. Final Answer:

   SELECT * FROM employees e1 JOIN employees e2 ON e1.manager_id = e2.id; -> Option A

4. Quick Check:

   Correct alias and ON condition = SELECT * FROM employees e1 JOIN employees e2 ON e1.manager_id = e2.id; [OK]

Hint: Use aliases and ON clause for SELF JOIN syntax [OK]

Common Mistakes:

• Not using aliases for the same table
• Missing ON clause or wrong condition
• Using comma join without condition

3. Given the table employees with columns id, name, and manager_id, what will this query return?

SELECT e1.name AS Employee, e2.name AS Manager FROM employees e1 LEFT JOIN employees e2 ON e1.manager_id = e2.id;

medium

A. List of employees with their managers' names; NULL if no manager

B. List of managers with their employees' names

C. List of employees with their own names repeated

D. Syntax error due to missing WHERE clause

Solution

1. Step 1: Understand LEFT JOIN with SELF JOIN

   The query joins employees to themselves matching manager_id to id, showing employee and manager names.

2. Step 2: Interpret NULL values

   If an employee has no manager (manager_id is NULL), LEFT JOIN keeps employee row with manager name as NULL.

3. Final Answer:

   List of employees with their managers' names; NULL if no manager -> Option A

4. Quick Check:

   LEFT JOIN keeps all employees, shows manager or NULL [OK]

Hint: LEFT JOIN keeps all employees, shows NULL for missing managers [OK]

Common Mistakes:

• Confusing employee and manager roles
• Expecting only matched rows (INNER JOIN behavior)
• Thinking query has syntax error

4. Identify the error in this SELF JOIN query:

SELECT e1.name, e2.name FROM employees e1 JOIN employees e2 ON e1.id = e2.manager_id WHERE e1.manager_id = NULL;

medium

A. JOIN condition is reversed

B. Missing alias for employees table

C. Using JOIN instead of LEFT JOIN causes error

D. Incorrect use of NULL comparison in WHERE clause

Solution

1. Step 1: Check WHERE clause for NULL comparison

   Using = NULL is incorrect; SQL requires IS NULL to check NULL values.

2. Step 2: Verify other parts of query

   Aliases are correct, JOIN condition is valid, and JOIN type is allowed.

3. Final Answer:

   Incorrect use of NULL comparison in WHERE clause -> Option D

4. Quick Check:

   Use IS NULL, not = NULL for NULL checks [OK]

Hint: Use IS NULL, not = NULL to check NULL values [OK]

Common Mistakes:

• Using = NULL instead of IS NULL
• Confusing JOIN condition direction
• Assuming JOIN type causes error

5. You have a table employees with columns id, name, and manager_id. Write a query using SELF JOIN to find all employees who are also managers of others. Which query correctly returns the names of employees who manage at least one other employee?

hard

A. SELECT e1.name FROM employees e1 LEFT JOIN employees e2 ON e1.id = e2.manager_id WHERE e2.id IS NULL;

B. SELECT DISTINCT e1.name FROM employees e1 JOIN employees e2 ON e1.id = e2.manager_id;

C. SELECT e2.name FROM employees e1 JOIN employees e2 ON e1.manager_id = e2.id;

D. SELECT e1.name FROM employees e1 JOIN employees e2 ON e1.manager_id = e2.id WHERE e1.id = e2.id;

Solution

1. Step 1: Understand the requirement

   We want employees who appear as managers (their id is manager_id for others).

2. Step 2: Analyze each query

   SELECT DISTINCT e1.name FROM employees e1 JOIN employees e2 ON e1.id = e2.manager_id; joins employees to those they manage and selects distinct manager names correctly. SELECT e1.name FROM employees e1 LEFT JOIN employees e2 ON e1.id = e2.manager_id WHERE e2.id IS NULL; finds employees with no subordinates (wrong). SELECT e2.name FROM employees e1 JOIN employees e2 ON e1.manager_id = e2.id; returns manager names duplicated for each subordinate (wrong). SELECT e1.name FROM employees e1 JOIN employees e2 ON e1.manager_id = e2.id WHERE e1.id = e2.id; has incorrect condition and will return no rows.

3. Final Answer:

   SELECT DISTINCT e1.name FROM employees e1 JOIN employees e2 ON e1.id = e2.manager_id; -> Option B

4. Quick Check:

   Managers have others with manager_id = their id [OK]

Hint: Join on e1.id = e2.manager_id to find managers [OK]

Common Mistakes:

• Selecting employees without subordinates
• Reversing join condition
• Using wrong WHERE clause filters