Bird
Raised Fist0
MySQLquery~10 mins

RIGHT JOIN in MySQL - Interactive Code Practice

Choose your learning style10 modes available
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to select all records from the right table and matching records from the left table using RIGHT JOIN.

MySQL
SELECT employees.name, departments.department_name FROM employees [1] departments ON employees.department_id = departments.id;
Drag options to blanks, or click blank then click option'
ARIGHT JOIN
BLEFT JOIN
CINNER JOIN
DFULL JOIN
Attempts:
3 left
💡 Hint
Common Mistakes
Using LEFT JOIN instead of RIGHT JOIN.
Using INNER JOIN which only returns matching rows.
2fill in blank
medium

Complete the code to get all departments and their employees, including departments with no employees.

MySQL
SELECT departments.department_name, employees.name FROM departments [1] employees ON departments.id = employees.department_id;
Drag options to blanks, or click blank then click option'
AINNER JOIN
BCROSS JOIN
CRIGHT JOIN
DLEFT JOIN
Attempts:
3 left
💡 Hint
Common Mistakes
Using RIGHT JOIN when departments is the left table.
Using INNER JOIN which excludes departments without employees.
3fill in blank
hard

Fix the error in the query to correctly use RIGHT JOIN to get all departments and their employees.

MySQL
SELECT employees.name, departments.department_name FROM employees [1] departments ON employees.department_id = departments.id;
Drag options to blanks, or click blank then click option'
ARIGHT JOIN
BINNER JOIN
CJOIN
DLEFT JOIN
Attempts:
3 left
💡 Hint
Common Mistakes
Using INNER JOIN which excludes unmatched rows.
Using LEFT JOIN which includes all left table rows instead.
4fill in blank
hard

Fill both blanks to select all employees and their departments, including employees without departments.

MySQL
SELECT employees.name, departments.department_name FROM employees [1] departments ON employees.department_id [2] departments.id;
Drag options to blanks, or click blank then click option'
ALEFT JOIN
B=
CRIGHT JOIN
D!=
Attempts:
3 left
💡 Hint
Common Mistakes
Using RIGHT JOIN which excludes employees without departments.
Using '!=' in ON condition which is invalid for joins.
5fill in blank
hard

Fill all three blanks to select all departments and their employees, including departments with no employees, and order by department name.

MySQL
SELECT departments.department_name, employees.name FROM departments [1] employees ON departments.id [2] employees.department_id ORDER BY departments.department_name [3];
Drag options to blanks, or click blank then click option'
ALEFT JOIN
B=
CASC
DDESC
Attempts:
3 left
💡 Hint
Common Mistakes
Using RIGHT JOIN which excludes departments without employees.
Using DESC which orders in reverse alphabetical order.

Practice

(1/5)
1. What does a RIGHT JOIN do in SQL?
easy
A. Returns all rows from the right table and matching rows from the left table.
B. Returns all rows from the left table and matching rows from the right table.
C. Returns only rows that have matching values in both tables.
D. Returns all rows from both tables, matching where possible.

Solution

  1. Step 1: Understand the direction of RIGHT JOIN

    A RIGHT JOIN returns all rows from the right table regardless of matches in the left table.
  2. Step 2: Identify matching rows from the left table

    It includes matching rows from the left table and fills NULL where no match exists.
  3. Final Answer:

    Returns all rows from the right table and matching rows from the left table. -> Option A
  4. Quick Check:

    RIGHT JOIN = all right table rows + matched left rows [OK]
Hint: RIGHT JOIN keeps all right table rows, left table may have NULLs [OK]
Common Mistakes:
  • Confusing RIGHT JOIN with LEFT JOIN
  • Thinking RIGHT JOIN returns only matching rows
  • Assuming RIGHT JOIN returns all rows from left table
2. Which of the following is the correct syntax for a RIGHT JOIN in MySQL?
easy
A. SELECT * FROM table1 RIGHT OUTER JOIN table2 WHERE table1.id = table2.id;
B. SELECT * FROM table1 JOIN RIGHT table2 ON table1.id = table2.id;
C. SELECT * FROM table1 RIGHT JOIN table2 ON table1.id = table2.id;
D. SELECT * FROM table1 RIGHT JOIN table2 USING id;

Solution

  1. Step 1: Check standard RIGHT JOIN syntax

    The correct syntax is SELECT ... FROM table1 RIGHT JOIN table2 ON condition;.
  2. Step 2: Validate each option

    SELECT * FROM table1 RIGHT JOIN table2 ON table1.id = table2.id; uses correct syntax with ON clause. SELECT * FROM table1 JOIN RIGHT table2 ON table1.id = table2.id; has wrong keyword order. SELECT * FROM table1 RIGHT OUTER JOIN table2 WHERE table1.id = table2.id; uses WHERE instead of ON. SELECT * FROM table1 RIGHT JOIN table2 USING id; uses invalid syntax (parentheses required: USING (id)).
  3. Final Answer:

    SELECT * FROM table1 RIGHT JOIN table2 ON table1.id = table2.id; -> Option C
  4. Quick Check:

    RIGHT JOIN syntax = FROM table1 RIGHT JOIN table2 ON condition [OK]
Hint: RIGHT JOIN needs ON clause, USING only if columns match exactly [OK]
Common Mistakes:
  • Using WHERE instead of ON for join condition
  • Incorrect keyword order like JOIN RIGHT
  • Confusing RIGHT JOIN with RIGHT OUTER JOIN (both valid but syntax matters)
3. Given these tables:

Employees
id | name
1 | Alice
2 | Bob

Departments
id | dept_name
2 | Sales
3 | Marketing

What is the result of:
SELECT Employees.name, Departments.dept_name FROM Employees RIGHT JOIN Departments ON Employees.id = Departments.id;
medium
A. [('Bob', 'Sales')]
B. [('Alice', NULL), ('Bob', 'Sales')]
C. [('Alice', NULL), ('Bob', 'Sales'), (NULL, 'Marketing')]
D. [('Bob', 'Sales'), (NULL, 'Marketing')]

Solution

  1. Step 1: Identify RIGHT JOIN behavior with given tables

    RIGHT JOIN keeps all rows from Departments (right table). Departments have ids 2 and 3.
  2. Step 2: Match Employees.id to Departments.id

    Employees with id=2 is Bob, matches Sales. No employee with id=3, so NULL for name and Marketing for dept_name.
  3. Final Answer:

    [('Bob', 'Sales'), (NULL, 'Marketing')] -> Option D
  4. Quick Check:

    RIGHT JOIN keeps all right rows, unmatched left = NULL [OK]
Hint: RIGHT JOIN shows all right rows, NULL for unmatched left [OK]
Common Mistakes:
  • Expecting all employees instead of all departments
  • Including unmatched left rows only
  • Confusing LEFT JOIN with RIGHT JOIN results
4. Consider this query:

SELECT a.id, b.value FROM tableA a RIGHT JOIN tableB b ON a.id = b.id;

It returns no rows even though tableB has data. What is the most likely cause?
medium
A. The join condition is incorrect or mismatched column names.
B. RIGHT JOIN does not return any rows if left table is empty.
C. RIGHT JOIN requires WHERE clause to filter rows.
D. The query syntax is invalid and causes an error.

Solution

  1. Step 1: Understand RIGHT JOIN behavior

    RIGHT JOIN returns all rows from right table even if left table has no matching rows.
  2. Step 2: Analyze why no rows returned

    If no rows appear, likely the join condition a.id = b.id does not match any rows due to wrong column names or data mismatch.
  3. Final Answer:

    The join condition is incorrect or mismatched column names. -> Option A
  4. Quick Check:

    No rows means join condition mismatch [OK]
Hint: No rows? Check join condition and column names first [OK]
Common Mistakes:
  • Assuming RIGHT JOIN needs WHERE clause
  • Thinking RIGHT JOIN returns no rows if left table empty
  • Believing syntax error causes no rows instead of error
5. You have two tables:

Orders
order_id | customer_id
1 | 101
2 | 102

Customers
customer_id | name
101 | John
103 | Alice

You want to list all customers and their orders if any. Which query using RIGHT JOIN gives the correct result?
hard
A. SELECT Customers.name, Orders.order_id FROM Customers RIGHT JOIN Orders ON Customers.customer_id = Orders.customer_id;
B. SELECT Customers.name, Orders.order_id FROM Orders RIGHT JOIN Customers ON Orders.customer_id = Customers.customer_id;
C. SELECT Customers.name, Orders.order_id FROM Orders LEFT JOIN Customers ON Orders.customer_id = Customers.customer_id;
D. SELECT Customers.name, Orders.order_id FROM Customers LEFT JOIN Orders ON Customers.customer_id = Orders.customer_id;

Solution

  1. Step 1: Identify which table is right to keep all customers

    We want all customers, so Customers must be the right table in RIGHT JOIN.
  2. Step 2: Check join condition and table order

    SELECT Customers.name, Orders.order_id FROM Orders RIGHT JOIN Customers ON Orders.customer_id = Customers.customer_id; uses Orders RIGHT JOIN Customers ON matching customer_id, so all Customers appear with matching Orders or NULL.
  3. Final Answer:

    SELECT Customers.name, Orders.order_id FROM Orders RIGHT JOIN Customers ON Orders.customer_id = Customers.customer_id; -> Option B
  4. Quick Check:

    RIGHT JOIN keeps all right table rows (Customers) [OK]
Hint: Put table with all rows as right table in RIGHT JOIN [OK]
Common Mistakes:
  • Swapping table order and losing all customers
  • Using LEFT JOIN instead of RIGHT JOIN incorrectly
  • Confusing join condition direction
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard