Multiple table JOINs in MySQL - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to join two tables on the customer ID.

MySQL

SELECT customers.name, orders.order_date FROM customers [1] orders ON customers.id = orders.customer_id;

Drag options to blanks, or click blank then click option'

AJOIN

BSELECT

CWHERE

DGROUP BY

Attempts:

3 left

💡 Hint

Common Mistakes

Using SELECT instead of JOIN to combine tables.

Using WHERE without JOIN for table combination.

The JOIN keyword is used to combine rows from two tables based on a related column.

2fill in blank

medium

Complete the code to join three tables: customers, orders, and products.

MySQL

SELECT customers.name, products.product_name FROM customers JOIN orders ON customers.id = orders.customer_id [1] products ON orders.product_id = products.id;

Drag options to blanks, or click blank then click option'

AWHERE

BGROUP BY

CJOIN

DORDER BY

Attempts:

3 left

💡 Hint

Common Mistakes

Using WHERE instead of JOIN for additional tables.

Forgetting the ON condition for the second join.

To join multiple tables, use JOIN for each additional table with the appropriate ON condition.

3fill in blank

hard

Fix the error in the JOIN clause to correctly join customers and orders.

MySQL

SELECT customers.name, orders.order_date FROM customers JOIN orders [1] customers.id = orders.customer_id;

Drag options to blanks, or click blank then click option'

AWHERE

BON

CUSING

DGROUP BY

Attempts:

3 left

💡 Hint

Common Mistakes

Using WHERE instead of ON in JOIN clause.

Omitting the ON keyword entirely.

The ON keyword specifies the condition for joining tables.

4fill in blank

hard

Fill both blanks to join customers, orders, and products with correct conditions.

MySQL

SELECT customers.name, orders.order_date, products.product_name FROM customers [1] orders [2] customers.id = orders.customer_id JOIN products ON orders.product_id = products.id;

Drag options to blanks, or click blank then click option'

AJOIN

BWHERE

CON

DGROUP BY

Attempts:

3 left

💡 Hint

Common Mistakes

Using WHERE instead of ON for join conditions.

Using GROUP BY instead of JOIN.

Use JOIN to add the orders table and ON to specify the join condition.

5fill in blank

hard

Fill all three blanks to join customers, orders, and products with aliases and conditions.

MySQL

SELECT c.name, o.order_date, p.product_name FROM customers c [1] orders o [2] c.id = o.customer_id JOIN products p [3] o.product_id = p.id;

Drag options to blanks, or click blank then click option'

AJOIN

BON

CAS

DWHERE

Attempts:

3 left

💡 Hint

Common Mistakes

Using WHERE instead of ON for join conditions.

Using AS incorrectly for aliases.

Use JOIN to add tables, ON to specify join conditions, and AS is not needed here because aliases are given directly.

Practice

1. What is the main purpose of using JOIN with multiple tables in MySQL?

easy

A. To delete rows from multiple tables at once

B. To combine rows from two or more tables based on a related column

C. To create a new table from existing tables

D. To update multiple tables simultaneously

Solution

1. Step 1: Understand the role of JOIN

   JOIN is used to combine rows from two or more tables based on a related column, allowing us to see related data together.

2. Step 2: Compare with other options

   Deleting, creating, or updating tables are different SQL operations and not the main purpose of JOIN.

3. Final Answer:

   To combine rows from two or more tables based on a related column -> Option B

4. Quick Check:

   JOIN combines tables = To combine rows [OK]

Hint: JOIN connects tables by matching columns [OK]

Common Mistakes:

• Confusing JOIN with DELETE or UPDATE operations
• Thinking JOIN creates new tables permanently
• Assuming JOIN works without specifying related columns

2. Which of the following is the correct syntax to join two tables employees and departments on the column department_id?

easy

A. SELECT * FROM employees JOIN departments ON employees.department_id = departments.department_id;

B. SELECT * FROM employees JOIN departments WHERE employees.department_id = departments.department_id;

C. SELECT * FROM employees, departments ON employees.department_id = departments.department_id;

D. SELECT * FROM employees JOIN departments USING employees.department_id;

Solution

1. Step 1: Check JOIN syntax with ON clause

   The correct syntax uses JOIN followed by ON to specify the matching columns: JOIN departments ON employees.department_id = departments.department_id.

2. Step 2: Identify errors in other options

   SELECT * FROM employees JOIN departments WHERE employees.department_id = departments.department_id; uses WHERE instead of ON, which is incorrect for JOIN conditions. SELECT * FROM employees, departments ON employees.department_id = departments.department_id; uses ON without JOIN keyword properly. SELECT * FROM employees JOIN departments USING employees.department_id; uses USING incorrectly with full column name.

3. Final Answer:

   SELECT * FROM employees JOIN departments ON employees.department_id = departments.department_id; -> Option A

4. Quick Check:

   JOIN with ON = SELECT * FROM employees JOIN departments ON employees.department_id = departments.department_id; [OK]

Hint: JOIN needs ON, not WHERE, to link tables [OK]

Common Mistakes:

• Using WHERE instead of ON for JOIN condition
• Using USING with full table.column syntax
• Omitting JOIN keyword or ON clause

3. Given the tables:
students(id, name, class_id)
classes(id, class_name)
What is the output of this query?

SELECT students.name, classes.class_name FROM students JOIN classes ON students.class_id = classes.id WHERE classes.class_name = 'Math';

medium

A. Empty result because of missing WHERE clause

B. List of all students with their class names

C. List of class names only

D. List of student names who are in the Math class

Solution

1. Step 1: Understand the JOIN and WHERE clause

   The JOIN connects students with their classes by matching class_id and id. The WHERE clause filters only classes named 'Math'.

2. Step 2: Determine the output columns and rows

   The SELECT returns student names and class names only for students in 'Math' class, so the output is a list of those students with 'Math' as class_name.

3. Final Answer:

   List of student names who are in the Math class -> Option D

4. Quick Check:

   JOIN + WHERE filters = students in Math [OK]

Hint: WHERE filters after JOIN to limit rows [OK]

Common Mistakes:

• Thinking it returns all students regardless of class
• Confusing output columns with only class names
• Assuming WHERE is missing and causes empty result

4. Identify the error in this query joining orders and customers:

SELECT orders.id, customers.name FROM orders JOIN customers WHERE orders.customer_id = customers.id;

medium

A. Missing ON keyword before join condition

B. Using WHERE instead of HAVING

C. Incorrect table names

D. Missing SELECT keyword

Solution

1. Step 1: Check JOIN syntax

   The JOIN clause must be followed by ON to specify the join condition. Here, WHERE is incorrectly used instead of ON.

2. Step 2: Confirm other parts are correct

   Table names and SELECT keyword are correct. HAVING is not used for join conditions.

3. Final Answer:

   Missing ON keyword before join condition -> Option A

4. Quick Check:

   JOIN needs ON, not WHERE [OK]

Hint: JOIN requires ON before condition, not WHERE [OK]

Common Mistakes:

• Replacing ON with WHERE in JOIN
• Confusing WHERE with HAVING clause
• Ignoring syntax errors in JOIN statements

5. You have three tables:
products(id, name, category_id)
categories(id, category_name)
sales(product_id, quantity)
Which query correctly lists each product's name, its category name, and total quantity sold?

hard

A. SELECT p.name, c.category_name, SUM(s.quantity) FROM products p LEFT JOIN categories c ON p.category_id = c.id LEFT JOIN sales s ON p.id = s.product_id GROUP BY p.name;

B. SELECT p.name, c.category_name, s.quantity FROM products p JOIN categories c ON p.category_id = c.id JOIN sales s ON p.id = s.product_id;

C. SELECT p.name, c.category_name, SUM(s.quantity) FROM products p JOIN categories c ON p.category_id = c.id JOIN sales s ON p.id = s.product_id GROUP BY p.name, c.category_name;

D. SELECT p.name, c.category_name, SUM(s.quantity) FROM products p, categories c, sales s WHERE p.category_id = c.id AND p.id = s.product_id;

Solution

1. Step 1: Understand the requirement

   We need product name, category name, and total quantity sold (sum of sales.quantity) grouped by product and category.

2. Step 2: Analyze each option

   SELECT p.name, c.category_name, SUM(s.quantity) FROM products p JOIN categories c ON p.category_id = c.id JOIN sales s ON p.id = s.product_id GROUP BY p.name, c.category_name; uses JOINs with ON clauses correctly and groups by product and category names, summing quantity. SELECT p.name, c.category_name, s.quantity FROM products p JOIN categories c ON p.category_id = c.id JOIN sales s ON p.id = s.product_id; misses aggregation. SELECT p.name, c.category_name, SUM(s.quantity) FROM products p, categories c, sales s WHERE p.category_id = c.id AND p.id = s.product_id; uses implicit joins but misses GROUP BY. SELECT p.name, c.category_name, SUM(s.quantity) FROM products p LEFT JOIN categories c ON p.category_id = c.id LEFT JOIN sales s ON p.id = s.product_id GROUP BY p.name; uses LEFT JOIN but groups only by product name, missing category grouping.

3. Final Answer:

   SELECT p.name, c.category_name, SUM(s.quantity) FROM products p JOIN categories c ON p.category_id = c.id JOIN sales s ON p.id = s.product_id GROUP BY p.name, c.category_name; -> Option C

4. Quick Check:

   JOIN + GROUP BY + SUM = SELECT p.name, c.category_name, SUM(s.quantity) FROM products p JOIN categories c ON p.category_id = c.id JOIN sales s ON p.id = s.product_id GROUP BY p.name, c.category_name; [OK]

Hint: Use JOIN with GROUP BY and SUM for totals [OK]

Common Mistakes:

• Missing GROUP BY when using SUM
• Using WHERE instead of JOIN ON
• Grouping by only one column when multiple needed