MIN and MAX functions in MySQL - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to find the smallest price from the products table.

MySQL

SELECT [1](price) FROM products;

Drag options to blanks, or click blank then click option'

AMIN

BMAX

CSUM

DCOUNT

Attempts:

3 left

💡 Hint

Common Mistakes

Using MAX instead of MIN.

Using SUM or COUNT which do not return minimum values.

The MIN function returns the smallest value in a column.

2fill in blank

medium

Complete the code to find the highest score from the scores table.

MySQL

SELECT [1](score) FROM scores;

Drag options to blanks, or click blank then click option'

AMIN

BCOUNT

CAVG

DMAX

Attempts:

3 left

💡 Hint

Common Mistakes

Using MIN instead of MAX.

Using AVG or COUNT which do not return maximum values.

The MAX function returns the largest value in a column.

3fill in blank

hard

Fix the error in the query to get the maximum age from the users table.

MySQL

SELECT [1]age) FROM users;

Drag options to blanks, or click blank then click option'

AMAX

BMIN(

CMAX(

DMIN

Attempts:

3 left

💡 Hint

Common Mistakes

Omitting parentheses after MAX or MIN.

Using MIN instead of MAX.

The function call must include parentheses around the column name, so MAX(age) is correct.

4fill in blank

hard

Fill both blanks to find the smallest and largest salary from the employees table.

MySQL

SELECT [1](salary) AS min_salary, [2](salary) AS max_salary FROM employees;

Drag options to blanks, or click blank then click option'

AMIN

BMAX

CSUM

DCOUNT

Attempts:

3 left

💡 Hint

Common Mistakes

Swapping MIN and MAX.

Using SUM or COUNT instead of MIN or MAX.

Use MIN to get the smallest salary and MAX to get the largest salary.

5fill in blank

hard

Fill all three blanks to find the minimum, maximum, and average rating from the reviews table.

MySQL

SELECT [1](rating) AS min_rating, [2](rating) AS max_rating, [3](rating) AS avg_rating FROM reviews;

Drag options to blanks, or click blank then click option'

AMIN

BMAX

CAVG

DCOUNT

Attempts:

3 left

💡 Hint

Common Mistakes

Using COUNT instead of AVG for average.

Mixing up MIN and MAX.

Use MIN for minimum, MAX for maximum, and AVG for average values.

Practice

1. What does the MIN function do in MySQL?

easy

A. Finds the smallest value in a column

B. Finds the largest value in a column

C. Counts the number of rows

D. Calculates the average value

Solution

1. Step 1: Understand the purpose of MIN function

   The MIN function is designed to find the smallest value in a specified column of a table.

2. Step 2: Compare with other aggregate functions

   Unlike MAX which finds the largest value, MIN specifically returns the minimum value.

3. Final Answer:

   Finds the smallest value in a column -> Option A

4. Quick Check:

   MIN = smallest value [OK]

Hint: MIN always returns the smallest value in a column [OK]

Common Mistakes:

• Confusing MIN with MAX
• Thinking MIN counts rows
• Assuming MIN calculates average

2. Which of the following is the correct syntax to find the maximum value in the price column of a table named products?

easy

A. SELECT MAX(price) IN products;

B. SELECT MAX price FROM products;

C. SELECT MAX(price) FROM products WHERE;

D. SELECT MAX(price) FROM products;

Solution

1. Step 1: Recall correct SQL aggregate function syntax

   The correct syntax for using MAX is: SELECT MAX(column_name) FROM table_name;

2. Step 2: Check each option for syntax errors

   SELECT MAX(price) FROM products; uses correct parentheses and FROM clause. Options A, B, and D have syntax errors or incomplete clauses.

3. Final Answer:

   SELECT MAX(price) FROM products; -> Option D

4. Quick Check:

   MAX(price) syntax = SELECT MAX(price) FROM table [OK]

Hint: Use parentheses around column name with MAX [OK]

Common Mistakes:

• Omitting parentheses in MAX function
• Using IN instead of FROM
• Leaving incomplete WHERE clause

3. Given the table employees with a column salary containing values (3000, 4500, 2500, 5000), what will this query return?
SELECT MIN(salary), MAX(salary) FROM employees;

medium

A. (4500, 3000)

B. (2500, 5000)

C. (5000, 2500)

D. (3000, 4500)

Solution

1. Step 1: Identify the smallest and largest salary values

   The salaries are 3000, 4500, 2500, and 5000. The smallest is 2500 and the largest is 5000.

2. Step 2: Understand the query output format

   The query returns a single row with two columns: MIN(salary) and MAX(salary), so the output is (2500, 5000).

3. Final Answer:

   (2500, 5000) -> Option B

4. Quick Check:

   MIN=2500, MAX=5000 [OK]

Hint: MIN returns smallest, MAX returns largest value [OK]

Common Mistakes:

• Mixing up MIN and MAX values
• Assuming output is multiple rows
• Confusing order of returned values

4. What is wrong with this query to find the minimum age from the users table?
SELECT MIN age FROM users;

medium

A. Missing parentheses around the column name

B. Incorrect table name

C. MIN cannot be used with numeric columns

D. Missing WHERE clause

Solution

1. Step 1: Check the syntax of the MIN function usage

   The MIN function requires parentheses around the column name, like MIN(age).

2. Step 2: Identify the error in the query

   The query is missing parentheses, so it will cause a syntax error.

3. Final Answer:

   Missing parentheses around the column name -> Option A

4. Quick Check:

   MIN requires parentheses [OK]

Hint: Always use parentheses with MIN and MAX [OK]

Common Mistakes:

• Omitting parentheses in function calls
• Assuming WHERE clause is mandatory
• Thinking MIN can't be used on numbers

5. You have a table orders with columns order_id, customer_id, and amount. How would you write a query to find the highest order amount for each customer?

hard

A. SELECT customer_id, amount FROM orders WHERE amount = MAX(amount);

B. SELECT MAX(amount) FROM orders GROUP BY customer_id;

C. SELECT customer_id, MAX(amount) FROM orders GROUP BY customer_id;

D. SELECT customer_id, MAX(amount) FROM orders;

Solution

1. Step 1: Understand the requirement to group by customer

   We want the highest order amount per customer, so we must group results by customer_id.

2. Step 2: Use MAX with GROUP BY

   Using MAX(amount) with GROUP BY customer_id returns the maximum amount for each customer.

3. Step 3: Check each option

   SELECT customer_id, MAX(amount) FROM orders GROUP BY customer_id; correctly groups by customer_id and selects MAX(amount). SELECT MAX(amount) FROM orders GROUP BY customer_id; misses customer_id in SELECT. SELECT customer_id, amount FROM orders WHERE amount = MAX(amount); uses invalid WHERE with aggregate. SELECT customer_id, MAX(amount) FROM orders; lacks GROUP BY.

4. Final Answer:

   SELECT customer_id, MAX(amount) FROM orders GROUP BY customer_id; -> Option C

5. Quick Check:

   MAX with GROUP BY returns max per group [OK]

Hint: Use GROUP BY with MAX to get max per group [OK]

Common Mistakes:

• Not using GROUP BY when aggregating per group
• Using WHERE with aggregate functions incorrectly
• Selecting columns not in GROUP BY without aggregation