GROUP BY clause in MySQL - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to group the results by the "department" column.

MySQL

SELECT department, COUNT(*) FROM employees [1] department;

Drag options to blanks, or click blank then click option'

AWHERE

BORDER BY

CHAVING

DGROUP BY

Attempts:

3 left

💡 Hint

Common Mistakes

Using ORDER BY instead of GROUP BY.

Using WHERE to group rows.

The GROUP BY clause groups rows that have the same values in specified columns. Here, it groups by the department column.

2fill in blank

medium

Complete the code to show the average salary for each job title.

MySQL

SELECT job_title, AVG(salary) FROM employees [1] job_title;

Drag options to blanks, or click blank then click option'

AGROUP BY

BWHERE

CLIMIT

DORDER BY

Attempts:

3 left

💡 Hint

Common Mistakes

Using ORDER BY instead of GROUP BY.

Forgetting to group when using AVG.

The GROUP BY clause groups rows by job_title so the average salary is calculated per job title.

3fill in blank

hard

Fix the error in the query to correctly group by "category".

MySQL

SELECT category, SUM(quantity) FROM sales [1];

Drag options to blanks, or click blank then click option'

AGROUP BY category

BGROUP category

CGROUPBY category

DGROUP BY

Attempts:

3 left

💡 Hint

Common Mistakes

Writing GROUP category without BY.

Writing GROUPBY as one word.

The correct syntax is GROUP BY category. It groups rows by the category column.

4fill in blank

hard

Fill both blanks to group by "region" and filter groups with total sales over 1000.

MySQL

SELECT region, SUM(sales) FROM sales_data [1] region [2] SUM(sales) > 1000;

Drag options to blanks, or click blank then click option'

AGROUP BY

BORDER BY

CHAVING

DWHERE

Attempts:

3 left

💡 Hint

Common Mistakes

Using WHERE instead of HAVING to filter groups.

Forgetting to group before filtering.

Use GROUP BY region to group rows by region. Then use HAVING to filter groups where the sum of sales is greater than 1000.

5fill in blank

hard

Fill all three blanks to select the department name, count employees, and filter departments with more than 5 employees.

MySQL

SELECT [1], COUNT(*) FROM employees [2] [1] [3] COUNT(*) > 5;

Drag options to blanks, or click blank then click option'

Adepartment

BGROUP BY

CHAVING

DORDER BY

Attempts:

3 left

💡 Hint

Common Mistakes

Using WHERE instead of HAVING to filter groups.

Not grouping by the selected column.

Select department, group by it using GROUP BY, and filter groups with more than 5 employees using HAVING.

Practice

1. What is the main purpose of the GROUP BY clause in a MySQL query?

easy

A. To filter rows based on a condition

B. To sort the result set in ascending order

C. To join two or more tables together

D. To group rows that have the same values in specified columns

Solution

1. Step 1: Understand the role of GROUP BY

   The GROUP BY clause groups rows that share the same values in one or more columns.

2. Step 2: Differentiate from other clauses

   Sorting is done by ORDER BY, filtering by WHERE, and joining by JOIN. GROUP BY is specifically for grouping rows.

3. Final Answer:

   To group rows that have the same values in specified columns -> Option D

4. Quick Check:

   GROUP BY = group rows by column values [OK]

Hint: GROUP BY groups rows by column values [OK]

Common Mistakes:

• Confusing GROUP BY with ORDER BY
• Using GROUP BY to filter rows
• Thinking GROUP BY joins tables

2. Which of the following is the correct syntax to group rows by the column department in a MySQL query?

easy

A. SELECT * FROM employees GROUP BY department;

B. SELECT * FROM employees GROUP department BY;

C. SELECT * FROM employees ORDER BY department GROUP;

D. SELECT * FROM employees WHERE department GROUP BY;

Solution

1. Step 1: Recall correct GROUP BY syntax

   The correct syntax is: SELECT columns FROM table GROUP BY column_name;

2. Step 2: Check each option

   SELECT * FROM employees GROUP BY department; matches the correct syntax exactly. Others have misplaced keywords or wrong order.

3. Final Answer:

   SELECT * FROM employees GROUP BY department; -> Option A

4. Quick Check:

   GROUP BY column_name syntax = SELECT * FROM employees GROUP BY department; [OK]

Hint: GROUP BY follows SELECT ... FROM ... GROUP BY column [OK]

Common Mistakes:

• Placing GROUP BY after WHERE clause incorrectly
• Swapping GROUP BY and ORDER BY keywords
• Using GROUP BY without specifying columns

3. Given the table sales with columns region and amount, what will the following query return?

SELECT region, SUM(amount) FROM sales GROUP BY region;

medium

A. Total sales amount for each region

B. List of all sales amounts without grouping

C. Syntax error due to missing alias

D. Average sales amount for each region

Solution

1. Step 1: Understand the query components

   The query groups rows by region and sums the amount for each group.

2. Step 2: Interpret the result

   It returns one row per region with the total sales amount summed up.

3. Final Answer:

   Total sales amount for each region -> Option A

4. Quick Check:

   GROUP BY + SUM = total per group [OK]

Hint: SUM with GROUP BY gives total per group [OK]

Common Mistakes:

• Thinking it returns average instead of sum
• Expecting all rows without grouping
• Assuming syntax error without alias

4. Identify the error in this query:

SELECT department, COUNT(employee_id) FROM employees WHERE salary > 50000 GROUP BY employee_id;

medium

A. COUNT cannot be used with employee_id

B. GROUP BY should use department, not employee_id

C. WHERE clause cannot be used with GROUP BY

D. Missing ORDER BY clause

Solution

1. Step 1: Analyze GROUP BY usage

   The query groups by employee_id but selects department, which causes mismatch.

2. Step 2: Correct grouping column

   To count employees per department, GROUP BY should be on department, matching the selected column.

3. Final Answer:

   GROUP BY should use department, not employee_id -> Option B

4. Quick Check:

   GROUP BY column must match selected non-aggregated columns [OK]

Hint: GROUP BY columns must match selected non-aggregated columns [OK]

Common Mistakes:

• Grouping by wrong column not in SELECT
• Thinking WHERE conflicts with GROUP BY
• Assuming ORDER BY is mandatory

5. You have a products table with columns category, price, and stock. Which query correctly finds the average price and total stock for each category?

hard

A. SELECT category, AVG(price), SUM(stock) FROM products GROUP BY price;

B. SELECT category, price, stock FROM products GROUP BY category;

C. SELECT category, AVG(price), SUM(stock) FROM products GROUP BY category;

D. SELECT category, AVG(price), SUM(stock) FROM products;

Solution

1. Step 1: Identify aggregation needs

   We want average price and total stock per category, so use AVG(price) and SUM(stock).

2. Step 2: Group by category

   To get results per category, GROUP BY category is required.

3. Step 3: Check each option

   SELECT category, AVG(price), SUM(stock) FROM products GROUP BY category; correctly uses GROUP BY category with AVG and SUM. Others miss grouping or group by wrong column.

4. Final Answer:

   SELECT category, AVG(price), SUM(stock) FROM products GROUP BY category; -> Option C

5. Quick Check:

   Aggregate functions + GROUP BY category = SELECT category, AVG(price), SUM(stock) FROM products GROUP BY category; [OK]

Hint: Use GROUP BY category with AVG and SUM for correct aggregation [OK]

Common Mistakes:

• Grouping by wrong column like price
• Not using GROUP BY with aggregate functions
• Selecting columns without aggregation or grouping