DATEDIFF and TIMESTAMPDIFF in MySQL - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ query_result

intermediate

Calculate days difference using DATEDIFF

What is the output of this query?

SELECT DATEDIFF('2024-06-15', '2024-06-10') AS days_diff;

MySQL

SELECT DATEDIFF('2024-06-15', '2024-06-10') AS days_diff;

A 5

B 6

C -5

D 10

💡 Hint

DATEDIFF returns the number of days between two dates as end_date - start_date.

DATEDIFF counts how many days are between the first and second date. Here, 2024-06-15 minus 2024-06-10 equals 5 days.

❓ query_result

intermediate

Calculate months difference using TIMESTAMPDIFF

What is the output of this query?

SELECT TIMESTAMPDIFF(MONTH, '2023-01-01', '2024-06-01') AS months_diff;

MySQL

SELECT TIMESTAMPDIFF(MONTH, '2023-01-01', '2024-06-01') AS months_diff;

A 19

B 18

C 17

D 16

💡 Hint

TIMESTAMPDIFF counts full months between the two dates.

From January 1, 2023 to June 1, 2024 is 17 full months.

📝 Syntax

advanced

Identify the syntax error in TIMESTAMPDIFF usage

Which option contains a syntax error when using TIMESTAMPDIFF in MySQL?

A SELECT TIMESTAMPDIFF('DAY', '2024-01-01', '2024-01-10');

B SELECT TIMESTAMPDIFF(MONTH, '2024-01-01', '2024-02-01');

C SELECT TIMESTAMPDIFF(DAY, '2024-01-01', '2024-01-10');

D SELECT TIMESTAMPDIFF(YEAR, '2023-01-01', '2024-01-01');

💡 Hint

The first argument to TIMESTAMPDIFF should be a keyword, not a string.

TIMESTAMPDIFF expects the unit (e.g., DAY, MONTH) without quotes. Option A uses quotes, causing a syntax error.

❓ query_result

advanced

Compare DATEDIFF and TIMESTAMPDIFF outputs

What is the output of this query?

SELECT DATEDIFF('2024-06-15 12:00:00', '2024-06-10 23:59:59') AS diff1, TIMESTAMPDIFF(DAY, '2024-06-10 23:59:59', '2024-06-15 12:00:00') AS diff2;

MySQL

SELECT DATEDIFF('2024-06-15 12:00:00', '2024-06-10 23:59:59') AS diff1, TIMESTAMPDIFF(DAY, '2024-06-10 23:59:59', '2024-06-15 12:00:00') AS diff2;

A diff1 = 4, diff2 = 4

B diff1 = 4, diff2 = 5

C diff1 = 5, diff2 = 5

D diff1 = 5, diff2 = 4

💡 Hint

DATEDIFF counts date boundaries ignoring time, TIMESTAMPDIFF counts full days.

DATEDIFF counts the difference in days ignoring time parts, so it returns 5. TIMESTAMPDIFF counts full 24-hour days, so it returns 4.

🧠 Conceptual

expert

Understanding behavior of TIMESTAMPDIFF with negative intervals

What is the output of this query?

SELECT TIMESTAMPDIFF(DAY, '2024-06-15', '2024-06-10') AS days_diff;

MySQL

SELECT TIMESTAMPDIFF(DAY, '2024-06-15', '2024-06-10') AS days_diff;

A 5

B -5

C 0

D NULL

💡 Hint

TIMESTAMPDIFF returns negative values if the second date is earlier than the first.

TIMESTAMPDIFF returns the signed difference, so when the second date is before the first, it returns a negative number.

Practice

1. What does the MySQL function DATEDIFF(date1, date2) return?

easy

A. The number of days between date1 and date2

B. The number of seconds between date1 and date2

C. The difference in months between date1 and date2

D. The current date and time

Solution

1. Step 1: Understand the function purpose

   DATEDIFF calculates the difference between two dates in days only.

2. Step 2: Confirm the output type

   The output is an integer representing how many days separate the two dates.

3. Final Answer:

   The number of days between date1 and date2 -> Option A

4. Quick Check:

   DATEDIFF returns days difference [OK]

Hint: DATEDIFF always returns days difference between two dates [OK]

Common Mistakes:

• Thinking it returns seconds or months
• Confusing order of dates for output sign
• Using it to get current date/time

2. Which of the following is the correct syntax to find the difference in hours between two datetime values start_time and end_time using TIMESTAMPDIFF?

easy

A. TIMESTAMPDIFF(HOUR, start_time, end_time)

B. TIMESTAMPDIFF(start_time, end_time, HOUR)

C. TIMESTAMPDIFF('HOUR', end_time, start_time)

D. TIMESTAMPDIFF(end_time, start_time, 'HOUR')

Solution

1. Step 1: Recall TIMESTAMPDIFF syntax

   The correct syntax is TIMESTAMPDIFF(unit, datetime1, datetime2) where unit is a keyword like HOUR without quotes.

2. Step 2: Match parameters order

   Unit first, then start_time, then end_time is correct.

3. Final Answer:

   TIMESTAMPDIFF(HOUR, start_time, end_time) -> Option A

4. Quick Check:

   Unit first, then start, then end [OK]

Hint: TIMESTAMPDIFF(unit, start, end) with unit unquoted [OK]

Common Mistakes:

• Putting unit last or in quotes
• Swapping start and end parameters
• Using lowercase unit in quotes

3. Given the query:
SELECT TIMESTAMPDIFF(DAY, '2024-01-01', '2024-01-10') AS diff_days;
What will be the output of diff_days?

medium

A. Error

B. 10

C. 11

D. 9

Solution

1. Step 1: Understand TIMESTAMPDIFF with DAY unit

   It counts full days between the two dates, excluding the start date.

2. Step 2: Calculate days between 2024-01-01 and 2024-01-10

   From Jan 1 to Jan 10 is 9 full days difference.

3. Final Answer:

   9 -> Option D

4. Quick Check:

   10 - 1 = 9 days difference [OK]

Hint: TIMESTAMPDIFF counts full units between dates [OK]

Common Mistakes:

• Counting both start and end dates
• Expecting 10 instead of 9
• Confusing with DATEDIFF behavior

4. Identify the error in this query:
SELECT TIMESTAMPDIFF('MINUTE', '2024-04-01 10:00:00', '2024-04-01 11:30:00');

medium

A. TIMESTAMPDIFF cannot use MINUTE as unit

B. Dates must be swapped in order

C. Unit 'MINUTE' should not be in quotes

D. Dates must be in DATE format, not datetime

Solution

1. Step 1: Check TIMESTAMPDIFF unit syntax

   The unit keyword like MINUTE must be unquoted, as a keyword, not a string.

2. Step 2: Validate other parts

   The dates and order are correct; MINUTE is a valid unit; datetime format is allowed.

3. Final Answer:

   Unit 'MINUTE' should not be in quotes -> Option C

4. Quick Check:

   Unit keywords are unquoted [OK]

Hint: Remove quotes around unit in TIMESTAMPDIFF [OK]

Common Mistakes:

• Quoting the unit keyword
• Swapping date order unnecessarily
• Thinking datetime is invalid input

5. You want to find the total number of months between two dates '2023-01-15' and '2024-06-10', but only count full months passed. Which query correctly does this?

hard

A. SELECT DATEDIFF('2024-06-10', '2023-01-15') / 30;

B. SELECT TIMESTAMPDIFF(MONTH, '2023-01-15', '2024-06-10');

C. SELECT TIMESTAMPDIFF(DAY, '2023-01-15', '2024-06-10') / 30;

D. SELECT TIMESTAMPDIFF(YEAR, '2023-01-15', '2024-06-10') * 12;

Solution

1. Step 1: Understand requirement for full months

   We need full months difference, not approximate days divided by 30.

2. Step 2: Check each option

   SELECT TIMESTAMPDIFF(MONTH, '2023-01-15', '2024-06-10'); uses TIMESTAMPDIFF with MONTH unit, which counts full months correctly.
   SELECT DATEDIFF('2024-06-10', '2023-01-15') / 30; and C use days divided by 30, which is approximate and can be wrong.
   SELECT TIMESTAMPDIFF(YEAR, '2023-01-15', '2024-06-10') * 12; counts years times 12, ignoring leftover months.

3. Final Answer:

   SELECT TIMESTAMPDIFF(MONTH, '2023-01-15', '2024-06-10'); -> Option B

4. Quick Check:

   Use TIMESTAMPDIFF with MONTH for full months [OK]

Hint: Use TIMESTAMPDIFF with MONTH for full months difference [OK]

Common Mistakes:

• Dividing days by 30 for months
• Using YEAR unit and multiplying
• Using DATEDIFF which returns days only