WHERE clause filtering in MySQL - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to select all records where the age is greater than 30.

MySQL

SELECT * FROM employees WHERE age [1] 30;

Drag options to blanks, or click blank then click option'

A<=

B<

C=

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '=' instead of '>' will only select rows where age is exactly 30.

Using '<' will select ages less than 30, which is incorrect.

The WHERE clause filters rows where the age is greater than 30, so the correct operator is >.

2fill in blank

medium

Complete the code to select employees whose department is 'Sales'.

MySQL

SELECT * FROM employees WHERE department [1] 'Sales';

Drag options to blanks, or click blank then click option'

A=

B!=

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '!=' will select employees not in Sales, which is the opposite.

Using '>' or '<' does not make sense for string comparison here.

The WHERE clause checks for equality with the string 'Sales', so the correct operator is '='.

3fill in blank

hard

Fix the error in the code to select employees hired before 2020.

MySQL

SELECT * FROM employees WHERE hire_date [1] '2020-01-01';

Drag options to blanks, or click blank then click option'

A>

B<

C>=

D=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' will select employees hired after 2020, which is incorrect.

Using '=' will only select employees hired exactly on 2020-01-01.

To select employees hired before 2020, the hire_date must be less than '2020-01-01', so the operator is <.

4fill in blank

hard

Fill both blanks to select employees with salary greater than 50000 and department 'HR'.

MySQL

SELECT * FROM employees WHERE salary [1] 50000 [2] department = 'HR';

Drag options to blanks, or click blank then click option'

A>

B<

CAND

DOR

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' for salary will select lower salaries, which is wrong.

Using OR will select employees who meet either condition, not both.

The salary must be greater than 50000, so use >. Both conditions must be true, so use AND.

5fill in blank

hard

Fill all three blanks to select employees where age is less than 40, department is 'IT', and salary is at least 60000.

MySQL

SELECT * FROM employees WHERE age [1] 40 [2] department [3] 'IT' AND salary >= 60000;

Drag options to blanks, or click blank then click option'

A>

B<

C=

DAND

Attempts:

3 left

💡 Hint

Common Mistakes

Using > for age will select older employees, which is wrong.

Using OR instead of AND will select employees meeting any condition, not all.

Using != instead of = will select employees not in IT.

Age less than 40 uses <. The department condition is combined with AND. The department must equal 'IT', so use =.

Practice

1. What does the WHERE clause do in a SQL query?

easy

A. Filters rows based on a specified condition

B. Sorts the rows in ascending order

C. Joins two tables together

D. Creates a new table in the database

Solution

1. Step 1: Understand the purpose of WHERE clause

   The WHERE clause is used to filter rows that meet a specific condition in a SELECT query.

2. Step 2: Differentiate from other SQL clauses

   Sorting is done by ORDER BY, joining by JOIN, and creating tables by CREATE TABLE, so these are not correct.

3. Final Answer:

   Filters rows based on a specified condition -> Option A

4. Quick Check:

   WHERE clause = filters rows [OK]

Hint: WHERE filters rows by condition, not sorting or joining [OK]

Common Mistakes:

• Confusing WHERE with ORDER BY
• Thinking WHERE creates or joins tables
• Assuming WHERE changes table structure

2. Which of the following is the correct syntax to select all columns from a table named employees where the age is greater than 30?

easy

A. SELECT * FROM employees WHERE age => 30;

B. SELECT * FROM employees WHERE age > 30;

C. SELECT * employees WHERE age > 30;

D. SELECT * FROM employees WHERE age < 30;

Solution

1. Step 1: Check the basic SELECT syntax

   The correct syntax to select all columns is SELECT * FROM table_name.

2. Step 2: Verify the WHERE condition syntax

   The comparison operator for greater than is >, not =>. Also, the condition should match the question (age > 30).

3. Final Answer:

   SELECT * FROM employees WHERE age > 30; -> Option B

4. Quick Check:

   Correct syntax with > operator [OK]

Hint: Use > for greater than, syntax: SELECT * FROM table WHERE condition [OK]

Common Mistakes:

• Using => instead of >
• Omitting FROM keyword
• Using wrong comparison operator

3. Given the table products with columns id, name, and price, what will the query SELECT name FROM products WHERE price <= 50; return?

medium

A. All product names with price less than or equal to 50

B. All product names with price greater than 50

C. All product names regardless of price

D. Syntax error due to <= operator

Solution

1. Step 1: Understand the WHERE condition

   The condition price <= 50 means selecting rows where price is less than or equal to 50.

2. Step 2: Identify the selected columns

   The query selects only the name column from those filtered rows.

3. Final Answer:

   All product names with price less than or equal to 50 -> Option A

4. Quick Check:

   price <= 50 filters products [OK]

Hint: <= means less than or equal, filters rows accordingly [OK]

Common Mistakes:

• Confusing <= with >= operator
• Assuming it returns all products
• Thinking <= causes syntax error

4. Identify the error in the following query: SELECT * FROM orders WHERE status = 'shipped' OR;

medium

A. Incorrect use of single quotes around 'shipped'

B. Using * instead of column names

C. Missing semicolon at the end

D. Missing condition after OR operator

Solution

1. Step 1: Analyze the WHERE clause

   The WHERE clause ends with OR but has no condition after it, which is invalid syntax.

2. Step 2: Check other parts of the query

   Single quotes around 'shipped' are correct, semicolon is optional, and * is valid to select all columns.

3. Final Answer:

   Missing condition after OR operator -> Option D

4. Quick Check:

   OR must be followed by a condition [OK]

Hint: OR must always have conditions on both sides [OK]

Common Mistakes:

• Leaving OR without a following condition
• Thinking quotes around strings cause error
• Assuming semicolon is mandatory

5. You have a table students with columns id, name, and score. You want to select students who scored between 70 and 90 inclusive. Which query correctly uses the WHERE clause to achieve this?

hard

A. SELECT * FROM students WHERE score > 70 AND score < 90;

B. SELECT * FROM students WHERE score > 70 OR score < 90;

C. SELECT * FROM students WHERE score BETWEEN 70 AND 90;

D. SELECT * FROM students WHERE score = 70 AND score = 90;

Solution

1. Step 1: Understand the condition for scores between 70 and 90 inclusive

   We want scores greater than or equal to 70 and less than or equal to 90.

2. Step 2: Evaluate each option

   SELECT * FROM students WHERE score > 70 AND score < 90; uses > and < which excludes the boundary values 70 and 90, incorrect. SELECT * FROM students WHERE score > 70 OR score < 90; uses OR which is incorrect because it includes scores outside the range. SELECT * FROM students WHERE score BETWEEN 70 AND 90; uses BETWEEN which is a concise way to express the inclusive range. SELECT * FROM students WHERE score = 70 AND score = 90; checks if score equals both 70 and 90 simultaneously, which is impossible.

3. Step 3: Choose the best correct option

   BETWEEN is the simplest and most readable way to filter inclusive ranges.

4. Final Answer:

   SELECT * FROM students WHERE score BETWEEN 70 AND 90; -> Option C

5. Quick Check:

   BETWEEN includes boundaries, perfect for range filtering [OK]

Hint: Use BETWEEN for inclusive ranges, AND for combined conditions [OK]

Common Mistakes:

• Using OR instead of AND for range conditions
• Confusing BETWEEN boundaries as exclusive
• Using impossible conditions with AND equals