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MongoDBquery~30 mins

Pagination pattern with skip and limit in MongoDB - Mini Project: Build & Apply

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Pagination pattern with skip and limit
📖 Scenario: You are building a simple blog website. You have a collection called posts in your MongoDB database. Each post has a title and content. You want to show posts page by page, so users can see a few posts at a time instead of all at once.
🎯 Goal: Build a MongoDB query that uses skip and limit to get posts for a specific page number. This will help you show only a few posts per page.
📋 What You'll Learn
Create a variable called posts that contains 10 documents with title and content fields exactly as specified.
Create a variable called pageSize and set it to 3.
Create a variable called pageNumber and set it to 2.
Write a MongoDB query called pagedPosts that uses skip and limit to get the correct posts for the given pageNumber and pageSize.
💡 Why This Matters
🌍 Real World
Pagination is used in websites and apps to show data in small parts, like pages of posts or products, so users can browse easily without waiting for all data to load.
💼 Career
Knowing how to use skip and limit in MongoDB is important for backend developers and database administrators to efficiently manage large datasets and improve application performance.
Progress0 / 4 steps
1
DATA SETUP: Create the posts collection with 10 documents
Create a variable called posts that is an array of 10 objects. Each object must have a title and content field. Use these exact titles and contents: { title: 'Post 1', content: 'Content 1' }, { title: 'Post 2', content: 'Content 2' }, ..., up to { title: 'Post 10', content: 'Content 10' }.
MongoDB
Hint

Use a list with 10 objects. Each object has title and content keys with string values.

2
CONFIGURATION: Set the page size
Create a variable called pageSize and set it to 3. This will control how many posts show on each page.
MongoDB
Hint

Just create a variable pageSize and assign the number 3.

3
CORE LOGIC: Set the page number
Create a variable called pageNumber and set it to 2. This means you want to get the second page of posts.
MongoDB
Hint

Just create a variable pageNumber and assign the number 2.

4
COMPLETION: Write the MongoDB query using skip and limit
Create a variable called pagedPosts that uses the MongoDB find() method on posts and applies skip and limit to get the posts for the current pageNumber and pageSize. Use skip = (pageNumber - 1) * pageSize and limit = pageSize.
MongoDB
Hint

Use db.posts.find().skip((pageNumber - 1) * pageSize).limit(pageSize) to get the correct page.

Practice

(1/5)
1.

What does the skip method do in MongoDB pagination?

easy
A. It limits the number of documents returned.
B. It deletes documents from the collection.
C. It sorts the documents in ascending order.
D. It skips a specified number of documents before returning results.

Solution

  1. Step 1: Understand the role of skip

    The skip method tells MongoDB to ignore a certain number of documents from the start of the result set.

  2. Step 2: Compare with other methods

    limit controls how many documents to return, not skipping. Sorting and deleting are unrelated to skip.

  3. Final Answer:

    It skips a specified number of documents before returning results. -> Option D

  4. Quick Check:

    skip = skip documents [OK]
Hint: Skip jumps over documents, limit sets how many to show [OK]
Common Mistakes:
  • Confusing skip with limit
  • Thinking skip sorts documents
  • Assuming skip deletes documents
2.

Which of the following is the correct syntax to get the second page of results with 5 documents per page in MongoDB?

db.collection.find().skip(?).limit(?)
easy
A. skip(1).limit(5)
B. skip(10).limit(5)
C. skip(5).limit(5)
D. skip(0).limit(5)

Solution

  1. Step 1: Calculate skip value for page 2

    Each page has 5 documents, so page 1 skips 0, page 2 skips 5 documents (5 * (2-1) = 5).

  2. Step 2: Set limit to page size

    Limit should be 5 to get 5 documents per page.

  3. Final Answer:

    skip(5).limit(5) -> Option C

  4. Quick Check:

    Page 2 skip = 5, limit = 5 [OK]
Hint: Skip = pageSize * (pageNumber - 1), limit = pageSize [OK]
Common Mistakes:
  • Using skip(10) for page 2
  • Setting skip to 1 instead of 5
  • Confusing skip and limit values
3.

Given a collection with documents numbered 1 to 10, what documents will this query return?

db.collection.find().skip(3).limit(4)
medium
A. Documents 1 to 4
B. Documents 4 to 7
C. Documents 3 to 6
D. Documents 5 to 8

Solution

  1. Step 1: Understand skip(3)

    Skip the first 3 documents: documents 1, 2, and 3 are ignored.

  2. Step 2: Apply limit(4)

    Return the next 4 documents after skipping: documents 4, 5, 6, and 7.

  3. Final Answer:

    Documents 4 to 7 -> Option B

  4. Quick Check:

    Skip 3, then limit 4 = docs 4-7 [OK]
Hint: Skip removes first N, limit picks next M documents [OK]
Common Mistakes:
  • Counting skip as inclusive
  • Starting limit count before skip
  • Off-by-one errors in document numbers
4.

Identify the error in this pagination query to get page 3 with 10 documents per page:

db.collection.find().skip(20).limit(20)
medium
A. limit should be 10, not 20
B. skip value is too high
C. skip should be 30 for page 3
D. No error, query is correct

Solution

  1. Step 1: Calculate correct skip and limit for page 3

    Skip should be 10 * (3-1) = 20, which is correct here.

  2. Step 2: Check limit value

    Limit should be 10 to get 10 documents per page, but query uses limit(20), which is too many.

  3. Final Answer:

    limit should be 10, not 20 -> Option A

  4. Quick Check:

    Limit = page size = 10 [OK]
Hint: Limit equals page size, skip = pageSize*(page-1) [OK]
Common Mistakes:
  • Setting limit equal to skip
  • Using skip as page number
  • Assuming no limit needed
5.

You want to display page 4 of a product list with 8 items per page. However, the total products are 30. Which query correctly handles this pagination without returning empty results?

db.products.find().skip(?).limit(?)
hard
A. skip(24).limit(8)
B. skip(32).limit(8)
C. skip(16).limit(8)
D. skip(30).limit(8)

Solution

  1. Step 1: Calculate skip for page 4

    Skip = 8 * (4-1) = 24 documents to reach page 4.

  2. Step 2: Check total documents and limit

    Total is 30, so skipping 24 leaves 6 documents (30-24). Limit 8 is okay; it will return only available 6 documents without error.

  3. Step 3: Analyze other options

    skip(32) and skip(30) exceed total documents, returning empty results. skip(16) is for page 3, not page 4.

  4. Final Answer:

    skip(24).limit(8) -> Option A

  5. Quick Check:

    Page 4 skip = 24, limit = 8, total 30 [OK]
Hint: Skip = pageSize*(page-1), limit = pageSize, check total docs [OK]
Common Mistakes:
  • Skipping beyond total documents
  • Using wrong skip for page number
  • Ignoring total document count