The skip method helps you start reading data from a specific point, ignoring the first few items. This is useful when you want to see data in parts or pages.
When showing search results page by page on a website.
When you want to ignore the first few records and see the rest.
When you are browsing a long list and want to jump to a later section.
When testing or debugging and you want to skip some initial data.
Syntax
MongoDB
db.collection.find().skip(numberToSkip)
numberToSkip is how many documents you want to ignore from the start.
Use skip together with limit to control how many documents you get back.
Examples
Skip the first 5 users and show the rest.
MongoDB
db.users.find().skip(5)
Skip 10 products, then show the next 5 products only.
MongoDB
db.products.find().skip(10).limit(5)
Skip zero documents, so this returns all orders starting from the first.
MongoDB
db.orders.find().skip(0)
Sample Program
This example adds 5 books to the collection. Then it finds all books but skips the first 2, so it returns books starting from the 3rd one.
MongoDB
db.books.insertMany([
{ title: "Book A" },
{ title: "Book B" },
{ title: "Book C" },
{ title: "Book D" },
{ title: "Book E" }
])
// Now find books skipping the first 2const result = db.books.find().skip(2).toArray()
result
OutputSuccess
Important Notes
Skipping many documents can slow down your query because MongoDB still reads the skipped documents internally.
Always use skip with limit for pagination to avoid loading too much data at once.
Summary
skip lets you ignore a number of documents from the start.
It is useful for paging through data in chunks.
Combine skip with limit for best results.
Practice
(1/5)
1. What does the skip() method do in MongoDB queries?
easy
A. It limits the number of documents returned.
B. It skips a specified number of documents from the start of the result set.
C. It sorts the documents in ascending order.
D. It deletes documents from the collection.
Solution
Step 1: Understand the purpose of skip()
The skip() method is used to ignore a certain number of documents from the beginning of the query result.
Step 2: Differentiate from other methods
Unlike limit() which restricts the number of documents returned, skip() just moves the starting point forward.
Final Answer:
It skips a specified number of documents from the start of the result set. -> Option B
Quick Check:
skip() = skip documents [OK]
Hint: Remember: skip moves start point, limit controls count [OK]
Common Mistakes:
Confusing skip with limit
Thinking skip sorts documents
Assuming skip deletes documents
2. Which of the following is the correct syntax to skip 5 documents in a MongoDB query on collection users?
easy
A. db.users.find().skip(5)
B. db.users.skip(5).find()
C. db.users.find().limit(5)
D. db.users.find().offset(5)
Solution
Step 1: Recall correct method chaining
In MongoDB, skip() is chained after find() to skip documents.
Step 2: Check each option
db.users.find().skip(5) uses find().skip(5) which is correct syntax. db.users.skip(5).find() incorrectly places skip() before find(). db.users.find().limit(5) uses limit() which limits results, not skips. db.users.find().offset(5) uses offset() which is not a MongoDB method.
Final Answer:
db.users.find().skip(5) -> Option A
Quick Check:
Correct chaining = find().skip() [OK]
Hint: Always chain skip() after find() in MongoDB [OK]
Common Mistakes:
Using skip() before find()
Confusing skip() with limit()
Using offset() which is invalid
3. Given the collection products with documents [{"name": "A"}, {"name": "B"}, {"name": "C"}, {"name": "D"}], what will db.products.find().skip(2).limit(2).toArray() return?
medium
A. [{"name": "A"}, {"name": "B"}]
B. [{"name": "B"}, {"name": "C"}]
C. [{"name": "D"}]
D. [{"name": "C"}, {"name": "D"}]
Solution
Step 1: Understand skip and limit effect
skip(2) ignores the first two documents: "A" and "B". Then limit(2) returns the next two documents.
Step 2: Identify returned documents
After skipping "A" and "B", the next two are "C" and "D". So the result is [{"name": "C"}, {"name": "D"}].
Final Answer:
[{"name": "C"}, {"name": "D"}] -> Option D
Quick Check:
skip 2 + limit 2 = next 2 docs [OK]
Hint: Skip removes first N, limit picks next M [OK]
Common Mistakes:
Forgetting skip removes documents
Mixing order of skip and limit
Assuming skip returns skipped docs
4. You wrote db.orders.skip(3).find() to skip 3 documents but it throws an error. What is the problem?
medium
A. The skip() method must be called after find().
B. The skip() method does not exist in MongoDB.
C. You must use limit() before skip().
D. The number inside skip() must be a string.
Solution
Step 1: Check method order in MongoDB queries
In MongoDB, skip() is a cursor method and must be chained after find(), not before.
Step 2: Identify the error cause
Calling skip() before find() causes a syntax error because skip() is not a collection method.
Final Answer:
The skip() method must be called after find(). -> Option A
Quick Check:
Correct chaining order = find().skip() [OK]
Hint: Always call skip() after find() to avoid errors [OK]
Common Mistakes:
Calling skip() before find()
Using string instead of number in skip()
Thinking skip() requires limit() first
5. You want to display page 3 of a product list with 10 items per page using MongoDB. Which query correctly skips the right number of documents?
hard
A. db.products.find().skip(10).limit(3)
B. db.products.find().skip(30).limit(10)
C. db.products.find().skip(20).limit(10)
D. db.products.find().limit(10).skip(20)
Solution
Step 1: Calculate skip value for page 3
Each page shows 10 items. Page 1 skips 0, page 2 skips 10, so page 3 skips 20 documents (2 pages x 10 items).
Step 2: Verify query correctness
db.products.find().skip(20).limit(10) skips 20 and limits to 10, which is correct. db.products.find().skip(30).limit(10) skips 30 which is too many for page 3. db.products.find().skip(10).limit(3) skips 10 but limits to 3 items, wrong limit. db.products.find().limit(10).skip(20) places limit before skip, which limits to first 10 documents then skips 20 from them (impossible), returning empty.
Final Answer:
db.products.find().skip(20).limit(10) -> Option C
Quick Check:
Page 3 skip = (3-1)*10 = 20 [OK]
Hint: Skip = (page-1)*itemsPerPage, then limit itemsPerPage [OK]
Common Mistakes:
Calculating skip as page*itemsPerPage
Swapping skip and limit order
Using wrong limit count
Recommended
Ready to prove it?
Pass the test and this pattern moves unknownstrongwhile earning +1 Grip toward your certificate.