Ordered vs unordered inserts in MongoDB - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to perform an ordered insert of multiple documents in MongoDB.

MongoDB

db.collection.insertMany([{name: 'Alice'}, {name: 'Bob'}], {ordered: [1])

Drag options to blanks, or click blank then click option'

Afalse

Btrue

Cnull

Dundefined

Attempts:

3 left

💡 Hint

Common Mistakes

Using false will make inserts unordered, which is not what is asked.

Setting ordered: true ensures documents are inserted in order, stopping at the first error.

2fill in blank

medium

Complete the code to perform an unordered insert of multiple documents in MongoDB.

MongoDB

db.collection.insertMany([{name: 'Carol'}, {name: 'Dave'}], {ordered: [1])

Drag options to blanks, or click blank then click option'

Atrue

Bundefined

Cnull

Dfalse

Attempts:

3 left

💡 Hint

Common Mistakes

Using true will stop inserts on the first error.

Setting ordered: false allows MongoDB to insert documents in any order and continue after errors.

3fill in blank

hard

Fix the error in the code to correctly perform an unordered insert.

MongoDB

db.collection.insertMany([{name: 'Eve'}, {name: 'Frank'}], {ordered: [1])

Drag options to blanks, or click blank then click option'

Afalse

Btrue

C0

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 or 1 instead of boolean values causes errors.

The ordered option must be a boolean. Using false enables unordered inserts.

4fill in blank

hard

Fill both blanks to perform an unordered insert and handle errors without stopping.

MongoDB

db.collection.insertMany([{name: 'Grace'}, {name: 'Heidi'}], {ordered: [1], [2]: true})

Drag options to blanks, or click blank then click option'

Afalse

BwriteConcern

CbypassDocumentValidation

Dtrue

Attempts:

3 left

💡 Hint

Common Mistakes

Using true for ordered inserts when unordered is needed.

Setting ordered: false allows unordered inserts, and bypassDocumentValidation: true skips validation errors.

5fill in blank

hard

Fill all three blanks to perform an unordered insert with write concern and bypass validation.

MongoDB

db.collection.insertMany([{name: 'Ivan'}, {name: 'Judy'}], {ordered: [1], [2]: 1, [3]: true})

Drag options to blanks, or click blank then click option'

Atrue

BwriteConcern

CbypassDocumentValidation

Dfalse

Attempts:

3 left

💡 Hint

Common Mistakes

Confusing ordered true/false and missing writeConcern option.

Use ordered: false for unordered inserts, writeConcern: 1 to confirm writes, and bypassDocumentValidation: true to skip validation.

Practice

1. What happens when you perform an ordered insert in MongoDB and one document fails to insert?

easy

A. MongoDB skips the failed document and continues inserting the rest.

B. The insert operation stops immediately and no further documents are inserted.

C. MongoDB retries the failed document until it succeeds.

D. All documents are inserted regardless of errors.

Solution

1. Step 1: Understand ordered insert behavior

   In ordered inserts, MongoDB processes documents one by one in order.

2. Step 2: Effect of an error in ordered inserts

   If a document fails, MongoDB stops inserting further documents immediately.

3. Final Answer:

   The insert operation stops immediately and no further documents are inserted. -> Option B

4. Quick Check:

   Ordered insert stops on first error = A [OK]

Hint: Ordered inserts stop at first error, no more inserts after failure [OK]

Common Mistakes:

• Thinking unordered behavior applies to ordered inserts
• Assuming MongoDB retries failed documents automatically
• Believing all documents insert regardless of errors

2. Which of the following is the correct syntax to perform an unordered insert of multiple documents in MongoDB?

easy

A. db.collection.insertMany(docs, { ordered: true })

B. db.collection.insertMany(docs, { unordered: true })

C. db.collection.insertMany(docs, { continueOnError: true })

D. db.collection.insertMany(docs, { ordered: false })

Solution

1. Step 1: Identify the option to control insert order

   MongoDB uses the ordered option in insertMany to control insert order.

2. Step 2: Syntax for unordered insert

   Setting ordered: false makes the insert unordered, allowing MongoDB to continue on errors.

3. Final Answer:

   db.collection.insertMany(docs, { ordered: false }) -> Option D

4. Quick Check:

   Unordered insert uses ordered: false = C [OK]

Hint: Use ordered: false option for unordered inserts in insertMany [OK]

Common Mistakes:

• Using unordered: true which is invalid
• Confusing ordered: true with unordered inserts
• Using continueOnError which is deprecated

3. Consider the following code snippet:

db.collection.insertMany([
  { _id: 1, name: 'Alice' },
  { _id: 2, name: 'Bob' },
  { _id: 1, name: 'Charlie' }
], { ordered: false })

What will be the result of this operation?

medium

A. First and second documents are inserted; third fails due to duplicate _id but others succeed.

B. Only the first document is inserted; operation stops at duplicate _id error.

C. All three documents are inserted successfully.

D. Operation fails completely with no documents inserted.

Solution

1. Step 1: Analyze unordered insert behavior with duplicate key

   With ordered: false, MongoDB tries to insert all documents even if some fail.

2. Step 2: Identify duplicate _id effect

   The third document has a duplicate _id (1), causing a duplicate key error for that document only.

3. Step 3: Result of insertMany with unordered option

   First and second documents insert successfully; third fails but does not stop the operation.

4. Final Answer:

   First and second documents are inserted; third fails due to duplicate _id but others succeed. -> Option A

5. Quick Check:

   Unordered insert continues despite errors = B [OK]

Hint: Unordered inserts continue past errors, partial success possible [OK]

Common Mistakes:

• Assuming operation stops on first error even with ordered: false
• Thinking duplicate keys allow all inserts
• Believing all inserts fail if one fails

4. You wrote the following code but it throws an error and stops inserting after the first document:

db.collection.insertMany(docs, { unordered: true })

What is the likely cause and how to fix it?

medium

A. The option name is incorrect; use ordered: false instead of unordered: true.

B. The documents have duplicate keys; remove duplicates to fix.

C. MongoDB does not support insertMany; use insertOne instead.

D. The collection is read-only; change permissions.

Solution

1. Step 1: Identify incorrect option usage

   The option unordered is not valid in MongoDB insertMany.

2. Step 2: Correct option for unordered inserts

   Use ordered: false to perform unordered inserts.

3. Final Answer:

   The option name is incorrect; use ordered: false instead of unordered: true. -> Option A

4. Quick Check:

   Use ordered: false, not unordered: true = A [OK]

Hint: Use ordered: false, not unordered: true for unordered inserts [OK]

Common Mistakes:

• Using unordered: true which is invalid syntax
• Assuming insertMany is unsupported
• Ignoring duplicate key errors as cause

5. You want to insert 1000 documents quickly into a MongoDB collection. Some documents might have duplicate keys causing errors. Which insert option should you choose to maximize speed and insert as many documents as possible?

hard

A. Use ordered inserts with ordered: true to ensure strict order.

B. Use bulkWrite with ordered set to true for atomic inserts.

C. Use unordered inserts with ordered: false to continue despite errors.

D. Insert documents one by one using insertOne to catch errors early.

Solution

1. Step 1: Understand the goal of speed and partial success

   Unordered inserts allow MongoDB to insert documents in parallel and continue despite errors.

2. Step 2: Choose option that maximizes speed and partial inserts

   Setting ordered: false in insertMany achieves this by not stopping on errors.

3. Final Answer:

   Use unordered inserts with ordered: false to continue despite errors. -> Option C

4. Quick Check:

   Unordered inserts maximize speed and partial success = D [OK]

Hint: Use ordered: false for fast inserts with partial success [OK]

Common Mistakes:

• Choosing ordered inserts which stop on first error
• Inserting one by one which is slower
• Assuming bulkWrite with ordered true is faster