[Solved] What will be the output of this code snippet?def check_diagonal_win(board): n = len(board) if all(board[i][i] == 'O' for i in range(n)):... | LLD

LLD - Design — Tic-Tac-Toe Game

What will be the output of this code snippet?

def check_diagonal_win(board):
    n = len(board)
    if all(board[i][i] == 'O' for i in range(n)):
        return True
    return False

board = [['O','X','X'],['X','O',''],['X','','O']]
print(check_diagonal_win(board))

ATrue

BFalse

CNone

DError

Step-by-Step Solution

Solution:

Step 1: Understand diagonal check logic
The function checks if all elements from top-left to bottom-right are 'O'.
Step 2: Verify board diagonal elements
board[0][0] = 'O', board[1][1] = 'O', board[2][2] = 'O', so condition is True.
Final Answer:
True -> Option A
Quick Check:
Diagonal all 'O' returns True [OK]

Quick Trick: Diagonal check uses indices i,i [OK]

Common Mistakes:

MISTAKES

Checking wrong diagonal
Using wrong indices
Assuming False due to other cells

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What will be the output of this code snippet?

Step 1: Understand diagonal check logic

Step 2: Verify board diagonal elements

Final Answer:

Quick Check:

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