Pagination in Laravel - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ component_behavior

intermediate

What is the output of this Laravel pagination code?

Consider this Laravel controller code fetching users with pagination:

public function index() {
    $users = User::paginate(3);
    return view('users.index', compact('users'));
}

What will $users->count() return if the users table has 7 records?

Laravel

public function index() {
    $users = User::paginate(3);
    return view('users.index', compact('users'));
}

A 7

B 3

C 1

D 0

💡 Hint

Pagination limits the number of records per page.

The paginate(3) method limits the results to 3 per page. So $users->count() returns 3 on the first page even if total records are 7.

📝 Syntax

intermediate

Which option correctly paginates posts with 5 items per page?

You want to paginate posts in Laravel with 5 items per page. Which code snippet is correct?

A $posts = Post::paginate(5);

B $posts = Post::paginatePerPage(5);

C $posts = Post::getPaginate(5);

D $posts = Post::paginate->(5);

💡 Hint

Check Laravel's official pagination method name.

The correct method is paginate(5). Other options are invalid method calls and cause errors.

❓ state_output

advanced

What is the value of $users->lastPage() when paginating 12 users with 5 per page?

Given this code:

$users = User::paginate(5);

If the users table has 12 records, what does $users->lastPage() return?

Laravel

$users = User::paginate(5);

A 3

B 2

C 5

D 12

💡 Hint

Think about how many pages are needed for 12 items with 5 per page.

12 items with 5 per page means 3 pages (5 + 5 + 2). So lastPage() returns 3.

🔧 Debug

advanced

Why does this Laravel pagination code cause an error?

Look at this code snippet:

$users = User::paginate();

It causes an error. Why?

Laravel

$users = User::paginate();

A paginate() must be called on a query builder, not a model

B User model is missing

C paginate() requires a number argument for items per page

D paginate() is deprecated in Laravel

💡 Hint

Check the method signature for paginate.

paginate() requires the number of items per page as an argument. Calling it without arguments causes an error.

🧠 Conceptual

expert

Which option best describes the behavior of Laravel's simplePaginate() compared to paginate()?

Choose the correct statement about simplePaginate() versus paginate() in Laravel.

A simplePaginate() loads all records and paginates in memory

B simplePaginate() counts total records and shows page numbers like paginate()

C simplePaginate() is deprecated and replaced by paginate()

D simplePaginate() does not count total records and only provides next/previous links

💡 Hint

Think about performance differences between the two methods.

simplePaginate() skips counting total records for better performance and only provides next and previous links, unlike paginate() which shows full page numbers.