Pagination in Laravel

Introduction

Pagination helps split large lists of data into smaller pages. This makes it easier to read and faster to load.

Showing a list of blog posts on a website.

Displaying search results with many items.

Listing users or products in an admin panel.

Breaking down long tables into manageable pages.

Syntax

Laravel

$items = Model::paginate(10);

// In Blade view
{{ $items->links() }}

Use paginate(number) to get a set number of items per page.

Use links() in your Blade template to show page links.

Examples

Get 5 users per page and send to the view.

Laravel

$users = User::paginate(5);
return view('users.index', compact('users'));

Show each user name and the pagination links below.

Laravel

<!-- In Blade template -->
@foreach ($users as $user)
  <p>{{ $user->name }}</p>
@endforeach

{{ $users->links() }}

Get 15 published posts per page.

Laravel

$posts = Post::where('status', 'published')->paginate(15);

Sample Program

This controller gets 3 products per page. The Blade view shows product names and prices, then page links.

Laravel

<?php

namespace App\Http\Controllers;

use App\Models\Product;
use Illuminate\Http\Request;

class ProductController extends Controller
{
    public function index()
    {
        $products = Product::paginate(3);
        return view('products.index', compact('products'));
    }
}

// Blade file: resources/views/products/index.blade.php

/*
@foreach ($products as $product)
  <div>{{ $product->name }} - ${{ $product->price }}</div>
@endforeach

{{ $products->links() }}
*/

Important Notes

Pagination automatically reads the current page from the URL query (like ?page=2).

You can customize the pagination view if you want different styles.

Use simplePaginate() for simpler next/previous links without page numbers.

Summary

Pagination splits data into pages to improve usability and speed.

Use paginate() in your query and links() in your Blade view.

Laravel handles page numbers and URLs automatically.

Practice

1. What is the main purpose of using paginate() in Laravel?

easy

A. To join multiple tables in a query

B. To sort data alphabetically

C. To delete records from the database

D. To split large data sets into smaller pages for easier viewing

Solution

1. Step 1: Understand the function of paginate()

   The paginate() method divides a large set of data into smaller chunks or pages.

2. Step 2: Recognize the benefit of pagination

   This makes data easier to view and improves website speed by loading only a subset of data at a time.

3. Final Answer:

   To split large data sets into smaller pages for easier viewing -> Option D

4. Quick Check:

   Pagination = split data into pages [OK]

Hint: Remember paginate() breaks data into pages [OK]

Common Mistakes:

• Confusing paginate() with sorting methods
• Thinking paginate() deletes data
• Assuming paginate() merges tables

2. Which of the following is the correct way to paginate 10 items per page in a Laravel Eloquent query?

easy

A. $users = User::get(10);

B. $users = User::paginate(10);

C. $users = User::limit(10)->paginate();

D. $users = User::paginate()->take(10);

Solution

1. Step 1: Identify correct paginate() usage

   The paginate() method accepts the number of items per page as an argument, like paginate(10).

2. Step 2: Check other options for syntax errors

   get(10) does not paginate, limit(10)->paginate() is incorrect usage, and paginate()->take(10) is invalid chaining.

3. Final Answer:

   $users = User::paginate(10); -> Option B

4. Quick Check:

   paginate(10) sets items per page [OK]

Hint: Use paginate(number) to set items per page [OK]

Common Mistakes:

• Using get() instead of paginate()
• Chaining limit() before paginate() incorrectly
• Calling take() after paginate()

3. Given this code in a Laravel controller:

$posts = Post::paginate(5);

And this Blade snippet:

@foreach ($posts as $post)
  {{ $post->title }}
@endforeach
{{ $posts->links() }}

What will be the output behavior when visiting the page?

medium

A. Shows 5 post titles per page with navigation links to other pages

B. Shows all posts without any pagination links

C. Shows only the first post title without navigation

D. Throws an error because links() is not a valid method

Solution

1. Step 1: Understand paginate() and links() usage

   paginate(5) limits results to 5 per page. links() generates page navigation links automatically.

2. Step 2: Predict output behavior

   The page will display 5 post titles and show links to navigate between pages.

3. Final Answer:

   Shows 5 post titles per page with navigation links to other pages -> Option A

4. Quick Check:

   paginate(5) + links() = paged list with navigation [OK]

Hint: paginate() limits items, links() shows page navigation [OK]

Common Mistakes:

• Thinking links() is not a method
• Expecting all posts to show at once
• Assuming only one post shows

4. You wrote this code but get an error:

$users = User::paginate;

What is the problem and how to fix it?

medium

A. Missing parentheses after paginate; fix with paginate()

B. paginate is not a method; use get() instead

C. paginate requires a parameter; add paginate(10)

D. User model does not support pagination

Solution

1. Step 1: Identify syntax error

   paginate is a method and must be called with parentheses ().

2. Step 2: Correct the code

   Change User::paginate to User::paginate() to fix the error.

3. Final Answer:

   Missing parentheses after paginate; fix with paginate() -> Option A

4. Quick Check:

   Method calls need () [OK]

Hint: Always add () when calling methods [OK]

Common Mistakes:

• Forgetting parentheses on method calls
• Using get() instead of paginate() for pagination
• Assuming paginate needs a parameter always

5. You want to customize the pagination to show 15 items per page and use a Bootstrap 5 style in your Blade view. Which code snippet correctly achieves this?

hard

A. $posts = Post::paginate(15, 'bootstrap-5');

{{ $posts->links() }}

B. $posts = Post::paginate(15);

{{ $posts->links('bootstrap') }}

C. $posts = Post::paginate(15);

{{ $posts->links('pagination::bootstrap-5') }}

D. $posts = Post::paginate(15);

{{ $posts->links() }}

Solution

1. Step 1: Set items per page correctly

   Use paginate(15) to show 15 items per page.

2. Step 2: Use correct Bootstrap 5 pagination view

   Pass 'pagination::bootstrap-5' to links() to apply Bootstrap 5 styles.

3. Step 3: Verify other options

   The option with paginate(15, 'bootstrap-5') incorrectly passes the style to paginate(), links('bootstrap') uses wrong view name, and plain links() uses default style.

4. Final Answer:

   $posts = Post::paginate(15); {{ $posts->links('pagination::bootstrap-5') }} -> Option C

5. Quick Check:

   paginate(15) + links('pagination::bootstrap-5') = custom styled pagination [OK]

Hint: Use links('pagination::bootstrap-5') for Bootstrap 5 style [OK]

Common Mistakes:

• Passing style name to paginate() instead of links()
• Using wrong view name for Bootstrap
• Forgetting to set items per page