Why sequences matter for performance in Kotlin - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a list of numbers from 1 to 5.

Kotlin

val numbers = listOf([1])

Drag options to blanks, or click blank then click option'

AlistOf(1, 2, 3, 4, 5)

B1..5

C1, 2, 3, 4, 5

DarrayOf(1, 2, 3, 4, 5)

Attempts:

3 left

💡 Hint

Common Mistakes

Using a range like 1..5 inside listOf creates a list with one element (the range), not the numbers.

Using arrayOf instead of listOf creates an array, not a list.

We use listOf with explicit values separated by commas to create a list.

2fill in blank

medium

Complete the code to convert a list to a sequence.

Kotlin

val seq = numbers.[1]()

Drag options to blanks, or click blank then click option'

AasSequence

BtoSet

CtoList

Dmap

Attempts:

3 left

💡 Hint

Common Mistakes

Using toList() returns a list, not a sequence.

Using map() requires a lambda and does not convert to sequence.

The asSequence() function converts a collection to a sequence for lazy operations.

3fill in blank

hard

Fix the error in the code to filter even numbers using a sequence.

Kotlin

val evens = numbers.asSequence().filter { it [1] 2 == 0 }.toList()

Drag options to blanks, or click blank then click option'

A%

B/

C*

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using division / instead of modulo %.

Using multiplication or addition operators which do not check divisibility.

The modulo operator % checks if a number is divisible by 2 (even).

4fill in blank

hard

Fill both blanks to create a sequence that maps numbers to their squares and then converts to a list.

Kotlin

val squares = numbers.[1]().[2] { it * it }.toList()

Drag options to blanks, or click blank then click option'

AasSequence

Bmap

Cfilter

DtoList

Attempts:

3 left

💡 Hint

Common Mistakes

Using filter instead of map to transform elements.

Using toList too early, before mapping.

First convert to a sequence with asSequence(), then use map to square each number.

5fill in blank

hard

Fill all three blanks to create a sequence that filters odd numbers, maps to double their value, and converts to a list.

Kotlin

val result = numbers.[1]().[2] { it % 2 != 0 }.[3] { it * 2 }.toList()

Drag options to blanks, or click blank then click option'

AasSequence

Bfilter

Cmap

DtoList

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up filter and map order.

Not converting to sequence before filtering and mapping.

Convert to sequence with asSequence(), filter odd numbers with filter, then double values with map.

Practice

1. What is the main advantage of using Sequence in Kotlin compared to a regular List?

easy

A. It processes elements lazily, improving performance with large data.

B. It stores elements in a database automatically.

C. It converts all elements to strings immediately.

D. It requires less code to create than a list.

Solution

1. Step 1: Understand how sequences process data

   Sequences process elements one by one only when needed, not all at once.

2. Step 2: Compare with lists

   Lists process all elements eagerly, which can be slower and use more memory for large data.

3. Final Answer:

   It processes elements lazily, improving performance with large data. -> Option A

4. Quick Check:

   Lazy processing = better performance [OK]

Hint: Sequences process lazily, lists process eagerly [OK]

Common Mistakes:

• Thinking sequences store data in a database
• Confusing lazy processing with immediate conversion
• Assuming sequences need less code to create

2. Which of the following is the correct way to create a sequence from a list in Kotlin?

easy

A. val seq = list.toSequence()

B. val seq = list.asSequence()

C. val seq = Sequence(list)

D. val seq = list.sequence()

Solution

1. Step 1: Recall Kotlin sequence creation syntax

   The standard way to create a sequence from a list is using asSequence().

2. Step 2: Check each option

   val seq = list.asSequence() uses list.asSequence(), which is correct. Others are invalid or do not exist.

3. Final Answer:

   val seq = list.asSequence() -> Option B

4. Quick Check:

   Use asSequence() to convert list to sequence [OK]

Hint: Use asSequence() to convert list to sequence [OK]

Common Mistakes:

• Using toSequence() which does not exist
• Trying to call sequence() on list
• Trying to instantiate Sequence directly

3. What will be the output of this Kotlin code?

val list = listOf(1, 2, 3, 4, 5)
val result = list.asSequence()
    .map { println("Mapping $it"); it * 2 }
    .filter { println("Filtering $it"); it > 5 }
    .toList()
println(result)

medium

A. Mapping and filtering printed step-by-step, then [6, 8, 10]

B. No output except [6, 8, 10]

C. [6, 8, 10] with all mapping and filtering printed before the list

D. Compilation error due to println inside lambda

Solution

1. Step 1: Understand lazy evaluation of sequences

   Sequences process elements one by one, so map and filter print statements happen step-by-step per element.

2. Step 2: Trace the output

   For each element, "Mapping" prints, then "Filtering" prints, then next element. Finally, the filtered list [6, 8, 10] prints.

3. Final Answer:

   Mapping and filtering printed step-by-step, then [6, 8, 10] -> Option A

4. Quick Check:

   Lazy = step-by-step prints [OK]

Hint: Sequences print lazily per element, not all at once [OK]

Common Mistakes:

• Assuming all map prints happen before filter prints
• Expecting no prints due to lazy evaluation
• Thinking println causes compile error

4. Identify the problem in this Kotlin code that tries to improve performance using sequences:

val numbers = (1..5).toList()
val doubled = numbers.map { it * 2 }
val filtered = doubled.asSequence().filter { it > 5 }.toList()
println(filtered)

medium

A. toList() is missing after map, causing error.

B. Filter is applied before map, causing wrong results.

C. Sequence is created after map, so map is eager and wastes memory.

D. Sequence cannot be created from a list.

Solution

1. Step 1: Analyze the order of operations

   Mapping happens first on the list eagerly, then sequence is created only for filtering.

2. Step 2: Understand performance impact

   Because map is eager, it processes all elements immediately, losing sequence benefits.

3. Final Answer:

   Sequence is created after map, so map is eager and wastes memory. -> Option C

4. Quick Check:

   Sequence after map loses lazy benefits [OK]

Hint: Create sequence before map to keep lazy processing [OK]

Common Mistakes:

• Thinking filter order is wrong
• Expecting error due to missing toList() after map
• Believing sequence can't be made from list

5. You have a large list of numbers and want to find the sum of squares of even numbers greater than 10. Which Kotlin code snippet uses sequences best for performance?

hard

A. val sum = numbers.filter { it > 10 }
.filter { it % 2 == 0 }
.map { it * it }
.sum()

B. val sum = numbers.asSequence()
.map { it * it }
.filter { it > 10 && it % 2 == 0 }
.sum()

C. val sum = numbers.map { it * it }
.filter { it > 10 && it % 2 == 0 }
.sum()

D. val sum = numbers.asSequence()
.filter { it > 10 }
.filter { it % 2 == 0 }
.map { it * it }
.sum()

Solution

1. Step 1: Identify the correct order for filtering and mapping

   Filter first for numbers > 10 and even, then map to square to avoid unnecessary calculations.

2. Step 2: Use sequence to process lazily

   Using asSequence() before filters and map ensures lazy evaluation and better performance on large lists.

3. Final Answer:

   val sum = numbers.asSequence() .filter { it > 10 } .filter { it % 2 == 0 } .map { it * it } .sum() -> Option D

4. Quick Check:

   Sequence + filter before map = best performance [OK]

Hint: Filter before map, use sequence for lazy processing [OK]

Common Mistakes:

• Mapping before filtering wastes work
• Not using sequence loses lazy benefits
• Combining filters incorrectly after map